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Author: Tinku Tara

Please-help-explain-how-to-solve-e-1-x-dx-

Question Number 12500 by FilupS last updated on 24/Apr/17 $$\mathrm{Please}\:\mathrm{help}\:\mathrm{explain}\:\mathrm{how}\:\mathrm{to}\:\mathrm{solve} \\ $$$$\int{e}^{\frac{\mathrm{1}}{{x}}} {dx} \\ $$ Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 24/Apr/17 $${e}^{\frac{\mathrm{1}}{{x}}} ={t}\Rightarrow\frac{\mathrm{1}}{{x}}={lnt}\Rightarrow\left({lnx}+{c}\right)^{'} ={lnt}\Rightarrow…

Water-flows-out-of-a-tank-through-a-hole-of-diameter-2cm-above-the-hole-1-Determine-the-velocity-of-outflow-2-The-rate-of-outflow-when-the-level-of-the-water-in-the-tank-is-2cm-above-the-hole-

Question Number 12499 by tawa last updated on 23/Apr/17 $$\mathrm{Water}\:\mathrm{flows}\:\mathrm{out}\:\mathrm{of}\:\mathrm{a}\:\mathrm{tank}\:\mathrm{through}\:\mathrm{a}\:\mathrm{hole}\:\mathrm{of}\:\mathrm{diameter}\:\mathrm{2cm}\:\mathrm{above}\:\mathrm{the}\:\mathrm{hole} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{Determine}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{outflow} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{The}\:\mathrm{rate}\:\mathrm{of}\:\mathrm{outflow}\:\mathrm{when}\:\mathrm{the}\:\mathrm{level}\:\mathrm{of}\:\mathrm{the}\:\mathrm{water}\:\mathrm{in}\:\mathrm{the}\:\mathrm{tank}\:\mathrm{is}\:\mathrm{2cm}\:\mathrm{above} \\ $$$$\mathrm{the}\:\mathrm{hole}.\: \\ $$ Answered by sandy_suhendra last updated on 24/Apr/17…

Question-143570

Question Number 143570 by cesarL last updated on 15/Jun/21 Answered by Ar Brandon last updated on 15/Jun/21 $$\mathrm{I}=\int\mathrm{tan}^{\mathrm{2}} \mathrm{8xsec}^{\mathrm{4}} \mathrm{8xdx} \\ $$$$\:\:=\int\mathrm{tan}^{\mathrm{2}} \mathrm{8xsec}^{\mathrm{2}} \mathrm{8x}\centerdot\mathrm{sec}^{\mathrm{2}} \mathrm{8xdx}…

lim-x-1-2-x-1-x-2-x-lim-n-n-n-1-n-1-

Question Number 143561 by ZiYangLee last updated on 15/Jun/21 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\left(\mathrm{1}−\frac{\mathrm{2}}{{x}^{} }+\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)^{{x}} =? \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\left(\sqrt{{n}}−\sqrt{{n}−\mathrm{1}}\right)\sqrt{{n}+\mathrm{1}}\:=? \\ $$ Answered by mr W last updated…