Question Number 77988 by ajfour last updated on 12/Jan/20 Commented by ajfour last updated on 12/Jan/20 $${If}\:{the}\:{central}\:{rectangle}\:{has} \\ $$$${has}\:{sides}\:{half}\:{of}\:{that}\:{of}\:{outer} \\ $$$${one},\:{then}\:{find}\:{AB}. \\ $$ Answered by…
Question Number 143521 by SLVR last updated on 15/Jun/21 Commented by SLVR last updated on 15/Jun/21 $${kindly}\:\:{help}\:{me} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 143523 by lapache last updated on 15/Jun/21 $${Determiner}\:{l}'{origine}\:{de}\:{laplace} \\ $$$$\mathrm{1}−{F}\left({p}\right)=\frac{{p}}{\left({p}+\mathrm{2}\right)^{\mathrm{2}} } \\ $$ Answered by Dwaipayan Shikari last updated on 15/Jun/21 $${F}\left({p}\right)=\mathrm{1}−\frac{{p}}{\left({p}+\mathrm{2}\right)^{\mathrm{2}} }…
Question Number 143516 by mathdanisur last updated on 15/Jun/21 Commented by amin96 last updated on 15/Jun/21 $$? \\ $$ Answered by MJS_new last updated on…
Question Number 12446 by tawa last updated on 22/Apr/17 $$\mathrm{find}\:\mathrm{x} \\ $$$$\sqrt{\mathrm{x}}\:\:=\:\:\mathrm{8}^{\mathrm{x}} \\ $$ Commented by mrW1 last updated on 23/Apr/17 $${For}\:{equation}\:\sqrt{{x}}={a}^{{x}} \:{the}\:{solution}\:{is} \\ $$$${x}=−\frac{{W}\left(−\mathrm{2ln}\:{a}\right)}{\mathrm{2ln}\:{a}}…
Question Number 143519 by tugu last updated on 15/Jun/21 $$ \\ $$$${The}\:{first}\:{two}\:{terms}\:{of}\:{the}\:\left\{{a}_{{n}} \right\}\:{series}\:\:\:{are}\:{defind}\:{as}\:{a}_{{n}} ={a}_{{n}−\mathrm{1}} +{a}_{{n}−\mathrm{2}} \:\:{for}\:{the}\:{general}\:{term} \\ $$$$\:{a}_{\mathrm{1}} =\mathrm{5},\:{a}_{\mathrm{2}} =\mathrm{8}\:{and}\:{n}\geqslant\mathrm{3}\:. \\ $$$${since}\:{the}\:{L}={li}\underset{{n}\rightarrow\infty} {{m}}\frac{{a}_{{n}+\mathrm{1}} }{{a}_{{n}} }\:\:{what}\:{is}\:{the}\:{value}\:{of}\:{L}…
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Question Number 12442 by tawa last updated on 22/Apr/17 $$\mathrm{Solve}:\:\:\:\mathrm{z}^{\mathrm{4}} \:=\:−\:\mathrm{16} \\ $$ Answered by ajfour last updated on 22/Apr/17 $${z}^{\mathrm{4}} =\mathrm{2}^{\mathrm{4}} {e}^{{i}\left(\pi+\mathrm{2}{k}\pi\right)} \\ $$$${z}=\mathrm{2}{e}^{{i}\left(\frac{\pi}{\mathrm{4}}+\frac{\mathrm{2}{k}\pi}{\mathrm{4}}\:\right)}…
Question Number 143514 by ERA last updated on 15/Jun/21 Commented by Rasheed.Sindhi last updated on 15/Jun/21 $${Do}\:{you}\:{have}\:{booked}\:{space}\:{for}\: \\ $$$${question}\:{in}\:{advance}? \\ $$ Terms of Service Privacy…