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Author: Tinku Tara

Question-143499

Question Number 143499 by mnjuly1970 last updated on 15/Jun/21 Commented by MJS_new last updated on 15/Jun/21 $$ \\ $$$$\mathrm{tan}\:\left(\mathrm{60}°−\alpha\right)\:=\frac{\sqrt{\mathrm{3}}−\mathrm{tan}\:\alpha}{\mathrm{1}+\sqrt{\mathrm{3}}\mathrm{tan}\:\alpha} \\ $$$$\mathrm{tan}\:\left(\mathrm{60}°+\alpha\right)\:=\frac{\sqrt{\mathrm{3}}+\mathrm{tan}\:\alpha}{\mathrm{1}−\sqrt{\mathrm{3}}\mathrm{tan}\:\alpha} \\ $$$$\mathrm{tan}\:\mathrm{3}\alpha\:=\frac{\left(\mathrm{3}−\mathrm{tan}^{\mathrm{2}} \:\alpha\right)\mathrm{tan}\:\alpha}{\mathrm{1}−\mathrm{3tan}^{\mathrm{2}} \:\alpha}…

2x-3-1-x-4-x-dx-

Question Number 77960 by jagoll last updated on 12/Jan/20 $$\int\:\frac{\mathrm{2}{x}^{\mathrm{3}} −\mathrm{1}}{{x}^{\mathrm{4}} +{x}}\:{dx}? \\ $$ Commented by john santu last updated on 12/Jan/20 $${we}\:{divide}\:{by}\:{x}^{\mathrm{2}} \\ $$$$\int\:\frac{\mathrm{2}{x}−\frac{\mathrm{1}}{{x}^{\mathrm{2}}…

Question-12422

Question Number 12422 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 21/Apr/17 Commented by mrW1 last updated on 22/Apr/17 $${f}\left({x}\right)=\int\frac{{dx}}{{x}^{\mathrm{2}} −\mathrm{2}{x}\mathrm{cos}\:\varphi+\mathrm{1}}={F}\left({x},\varphi\right)+{C} \\ $$$${f}\left(\mathrm{0}\right)={F}\left(\mathrm{0},\varphi\right)+{C} \\ $$$$\underset{\varphi\rightarrow\mathrm{0}} {\mathrm{lim}}\:{f}\left(\mathrm{0}\right)=\underset{\varphi\rightarrow\mathrm{0}} {\mathrm{lim}}\:{F}\left(\mathrm{0},\varphi\right)+{C} \\…

If-a-body-of-2kg-mass-is-at-a-distance-of-7200km-from-the-centre-of-the-earth-What-would-the-acceleration-due-to-gravity-be-at-this-point-in-the-Earths-field-a-9-6m-s-2-b-10m-s-2-c-11-3m-s

Question Number 12419 by tawa last updated on 21/Apr/17 $$\mathrm{If}\:\mathrm{a}\:\mathrm{body}\:\mathrm{of}\:\mathrm{2kg}\:\mathrm{mass}\:\mathrm{is}\:\mathrm{at}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{7200km}\:\mathrm{from}\:\mathrm{the}\:\mathrm{centre}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{earth}\:.\:\mathrm{What}\:\mathrm{would}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{due}\:\mathrm{to}\:\mathrm{gravity}\:\mathrm{be}\:\mathrm{at}\:\mathrm{this}\:\mathrm{point}\:\mathrm{in} \\ $$$$\mathrm{the}\:\mathrm{Earths}\:\mathrm{field}\:? \\ $$$$\left(\mathrm{a}\right)\:\mathrm{9}.\mathrm{6m}/\mathrm{s}^{\mathrm{2}} \:\left(\mathrm{b}\right)\:\mathrm{10m}/\mathrm{s}^{\mathrm{2}} \:\left(\mathrm{c}\right)\:\mathrm{11}.\mathrm{3m}/\mathrm{s}^{\mathrm{2}} \:\left(\mathrm{d}\right)\:\mathrm{12}.\mathrm{7m}/\mathrm{s}^{\mathrm{2}} \:\left(\mathrm{e}\right)\:\mathrm{15}.\mathrm{6m}/\mathrm{s}^{\mathrm{2}} \\ $$ Answered by ajfour…