Question Number 143393 by ZiYangLee last updated on 13/Jun/21 $$\mathrm{Given}\:\mathrm{that}\:{f}\left({r}\right)=\left({r}+\mathrm{1}\right)!\:\centerdot\:{r},\:\mathrm{show}\:\mathrm{that} \\ $$$${f}\left({r}\right)−{f}\left({r}−\mathrm{1}\right)={r}!\left({r}^{\mathrm{2}} +\mathrm{1}\right). \\ $$$$\mathrm{Hence}\:\mathrm{or}\:\mathrm{otherwise},\:\mathrm{show}\:\mathrm{that} \\ $$$$\mathrm{2}!\:\centerdot\:\mathrm{5}+\mathrm{3}!\:\centerdot\:\mathrm{10}+\mathrm{4}!\:\centerdot\:\mathrm{17}+……{n}!\left({n}^{\mathrm{2}} +\mathrm{1}\right)=\left({n}+\mathrm{1}\right)!\:\centerdot\:\left({n}−\mathrm{2}\right) \\ $$ Answered by TheHoneyCat last updated…
Question Number 77859 by jagoll last updated on 11/Jan/20 $${y}\:=\:\mid{x}\mid\:^{\mid{x}\mid} \:\: \\ $$$$\frac{{dy}}{{dx}}\:=\:? \\ $$ Commented by mathmax by abdo last updated on 11/Jan/20 $${y}\left({x}\right)={e}^{\mid{x}\mid{ln}\mid{x}\mid}…
Question Number 77856 by walidMTS last updated on 11/Jan/20 $$\underset{{x}\rightarrow\mathrm{0}} {{l}im}\left(\frac{{e}^{{x}} −{x}−\mathrm{1}}{{x}}\right) \\ $$ Commented by mathmax by abdo last updated on 11/Jan/20 $${we}\:{have}\:{e}^{{x}} =\sum_{{n}=\mathrm{0}}…
Question Number 12321 by tawa last updated on 19/Apr/17 $$\mathrm{When}\:\mathrm{a}\:\mathrm{known}\:\mathrm{standard}\:\mathrm{resistor}\:\mathrm{of}\:\mathrm{2}.\mathrm{0}\:\Omega\:\mathrm{is}\:\mathrm{connected}\:\mathrm{to}\:\mathrm{the}\:\mathrm{0}.\mathrm{0}\:\mathrm{cm}\:\mathrm{end}\:\mathrm{of} \\ $$$$\mathrm{a}\:\mathrm{meter}\:\mathrm{bridge}.\:\mathrm{The}\:\mathrm{balance}\:\mathrm{point}\:\mathrm{is}\:\mathrm{found}\:\mathrm{to}\:\mathrm{be}\:\mathrm{at}\:\mathrm{55}.\mathrm{0cm}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\: \\ $$$$\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{resistor}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 77854 by jagoll last updated on 11/Jan/20 $${a}\:{circle}\: \\ $$$${offends}\:{the}\:{y}\:{axis}\:{at}\:{point}\left(\mathrm{0},{b}\right)\: \\ $$$${and}\:{through}\:{the}\:{intersection} \\ $$$${of}\:{the}\:{curve}\:{y}\:=\:{x}\:−\mathrm{2}\sqrt{{x}}+\frac{\mathrm{1}}{\mathrm{4}}.\: \\ $$$${value}\:{of}\:{b}\:=\:? \\ $$ Commented by john santu last…
Question Number 12319 by tawa last updated on 19/Apr/17 Answered by chux last updated on 19/Apr/17 $$\frac{\mathrm{R}}{\mathrm{60}}=\frac{\mathrm{20}}{\mathrm{100}−\mathrm{60}} \\ $$$$\mathrm{R}=\frac{\mathrm{20}×\mathrm{60}}{\mathrm{40}}=\mathrm{30}\Omega \\ $$ Commented by tawa last…
Question Number 77855 by Pratah last updated on 11/Jan/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 143391 by daniel1301 last updated on 13/Jun/21 $${lim}_{{n}\rightarrow\infty} \left(\mathrm{1}\:−\:\frac{{n}}{{n}−\mathrm{2}}\right)^{\mathrm{4}{n}} =\:?? \\ $$$${chiaha}\:{daniel} \\ $$ Answered by ArielVyny last updated on 13/Jun/21 $${e}^{\mathrm{4}{nln}\left(\mathrm{1}−\frac{{n}}{{n}−\mathrm{2}}\right)} ={e}^{\mathrm{4}{nln}\left(\mathrm{0}^{+}…
Question Number 77852 by Math 1234 last updated on 11/Jan/20 $$\mathrm{5245} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 143390 by ZiYangLee last updated on 13/Jun/21 $$\mathrm{Given}\:\mathrm{that}\:\left(\frac{\mathrm{tan}\:\alpha}{\mathrm{sin}\:\theta}−\frac{\mathrm{tan}\:\beta}{\mathrm{tan}\:\theta}\right)^{\mathrm{2}} =\mathrm{tan}^{\mathrm{2}} \alpha−\mathrm{tan}^{\mathrm{2}} \beta, \\ $$$$\mathrm{prove}\:\mathrm{that}\:\mathrm{cos}\:\theta=\frac{\mathrm{tan}\:\beta}{\mathrm{tan}\:\alpha\:} \\ $$ Answered by mindispower last updated on 13/Jun/21 $$\Leftrightarrow\left(\frac{\mathrm{1}}{{sin}\left(\theta\right)}−\frac{\mathrm{1}}{{tg}\left(\theta\right)}.\frac{{tg}\left(\beta\right)}{{tg}\left(\alpha\right)}\right)^{\mathrm{2}}…