Question Number 77593 by BK last updated on 08/Jan/20 Commented by $@ty@m123 last updated on 08/Jan/20 $${The}\:{repeatation}\:{of}\:{this}\:{question}\: \\ $$$${is}\:{sufficient}\:{to}\:{prove}\:{that}\:{Mr}.\:{BK} \\ $$$${is}\:{none}\:{other}\:{than}… \\ $$ Commented by…
Question Number 77591 by naka3546 last updated on 08/Jan/20 $${x}\:+\:\frac{\mathrm{1}}{{x}}\:\:=\:\:\mathrm{1} \\ $$$${x}^{\mathrm{100}} \:+\:\frac{\mathrm{1}}{{x}^{\mathrm{100}} }\:\:=\:\:? \\ $$$${x}^{\mathrm{2020}} \:+\:\frac{\mathrm{1}}{{x}^{\mathrm{2020}} }\:\:=\:\:? \\ $$ Commented by jagoll last updated…
Question Number 143127 by liberty last updated on 10/Jun/21 Answered by EDWIN88 last updated on 11/Jun/21 $$\:\mathrm{Let}\:\begin{cases}{\overset{\rightarrow} {\mathrm{a}}=\mathrm{QR}=\left(\mathrm{1},\mathrm{3},−\mathrm{1}\right)}\\{\overset{\rightarrow} {\mathrm{b}}=\mathrm{QS}=\left(−\mathrm{3},\mathrm{2},\mathrm{3}\right)}\\{\overset{\rightarrow} {\mathrm{c}}=\mathrm{QP}=\left(\mathrm{0},\mathrm{3},\mathrm{3}\right)}\end{cases} \\ $$$$\mathrm{distance}\:\mathrm{d}\:\mathrm{from}\:\mathrm{P}\:\mathrm{to}\:\mathrm{plane}\:\mathrm{is}\: \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{d}\:=\:\frac{\mid\overset{\rightarrow} {\mathrm{a}}.\left(\overset{\rightarrow}…
Question Number 143122 by loveineq last updated on 10/Jun/21 $$\mathrm{Let}\:{a},{b}\:\in\left[\mathrm{0},\mathrm{1}\right]\:\mathrm{and}\:{a}+{b}\:\leqslant\:\mathrm{1}.\:\mathrm{Prove}\:\mathrm{that} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{\mathrm{1}}{\mathrm{1}+{a}}+\frac{\mathrm{1}}{\mathrm{1}+{b}}+\frac{\mathrm{1}}{\mathrm{2}}\:\leqslant\:\frac{\mathrm{2}}{{a}+{b}}\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 12047 by Joel576 last updated on 10/Apr/17 $$\int\mathrm{4}{x}^{\mathrm{3}} \left(\mathrm{3}{x}^{\mathrm{2}} \:+\:\mathrm{2}\right)^{\mathrm{5}} \:{dx} \\ $$ Commented by Joel576 last updated on 10/Apr/17 Answered by sma3l2996…
Question Number 12046 by 7991 last updated on 10/Apr/17 $${how}\:{much}\:{matrices}\:{of}\:{integers}\:{number} \\ $$$${A}=\begin{bmatrix}{{a}}&{{b}}\\{{c}}&{{d}}\end{bmatrix}{if}\:{A}^{\mathrm{2}} +{A}=\mathrm{2}{I},\:{c}=\mathrm{0},\:{det}\left({A}\right)=\mathrm{4} \\ $$ Answered by sma3l2996 last updated on 10/Apr/17 $${A}^{\mathrm{2}} =\begin{bmatrix}{{a}}&{{b}}\\{\mathrm{0}}&{{d}}\end{bmatrix}\begin{bmatrix}{{a}}&{{b}}\\{\mathrm{0}}&{{d}}\end{bmatrix}=\begin{bmatrix}{{a}^{\mathrm{2}} }&{{ab}+{db}}\\{\mathrm{0}}&{{d}^{\mathrm{2}}…
Question Number 12045 by 7991 last updated on 10/Apr/17 $${how}\:{much}\:{matrices}\:{of}\:{integers}\:{number} \\ $$$${A}=\begin{bmatrix}{{a}}&{{b}}\\{{c}}&{{d}}\end{bmatrix}{if}\:{A}^{\mathrm{2}} ={I}\:{and}\:{b}={c} \\ $$ Answered by sma3l2996 last updated on 10/Apr/17 $${A}^{\mathrm{2}} =\begin{bmatrix}{{a}}&{{b}}\\{{c}}&{{d}}\end{bmatrix}\begin{bmatrix}{{a}}&{{b}}\\{{c}}&{{d}}\end{bmatrix}=\begin{bmatrix}{{a}^{\mathrm{2}} +{bc}}&{{ab}+{db}}\\{{ac}+{dc}}&{{bc}+{d}^{\mathrm{2}}…
Question Number 12044 by 7991 last updated on 10/Apr/17 $${A}\in{M}_{{n}×{n}} \\ $$$${A}^{\mathrm{2}} ={A} \\ $$$$\left({I}+{A}\right)^{−\mathrm{1}} =….??? \\ $$ Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 10/Apr/17…
Question Number 143113 by qaz last updated on 10/Jun/21 $$\mathrm{x}^{\mathrm{3}} =\frac{\mathrm{1}}{\mathrm{3}!}\int_{\mathrm{0}} ^{\mathrm{x}} \mathrm{f}\left(\mathrm{x}−\mathrm{t}\right)\mathrm{f}\left(\mathrm{t}\right)\mathrm{dt} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=? \\ $$ Commented by mr W last updated on 10/Jun/21…
Question Number 143114 by bounhome last updated on 10/Jun/21 $${solve}: \\ $$$$\underset{{z}\rightarrow{i}} {\mathrm{lim}}\frac{\mathrm{3}{z}^{\mathrm{4}} −\mathrm{2}{z}^{\mathrm{3}} +\mathrm{8}{z}^{\mathrm{2}} −\mathrm{2}{z}+\mathrm{5}}{{z}−{i}}=? \\ $$ Answered by liberty last updated on 10/Jun/21…