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Author: Tinku Tara

x-4-bx-2-cx-s-let-x-2-px-t-p-2-x-2-2ptx-t-2-bx-2-cx-s-p-2-b-x-2-2pt-c-x-s-t-2-p-2-b-px-t-2pt-c-x-s-t-2-p-p-2-b-2pt-c-0-and-p-2-b-t-s-t-2-s-t-t-

Question Number 143011 by ajfour last updated on 08/Jun/21 $$\:\:{x}^{\mathrm{4}} +{bx}^{\mathrm{2}} +{cx}={s} \\ $$$${let}\:\:{x}^{\mathrm{2}} ={px}+{t} \\ $$$$\Rightarrow\:{p}^{\mathrm{2}} {x}^{\mathrm{2}} +\mathrm{2}{ptx}+{t}^{\mathrm{2}} +{bx}^{\mathrm{2}} +{cx}={s} \\ $$$$\Rightarrow\:\left({p}^{\mathrm{2}} +{b}\right){x}^{\mathrm{2}} +\left(\mathrm{2}{pt}+{c}\right){x}…

Hello-sirs-i-want-that-you-explain-me-how-we-solve-the-trigonometric-inequality-with-tangente-we-can-take-for-example-tan2x-3-i-can-solve-this-type-of-equality-but-not-the-inequality-Pleas

Question Number 77472 by mathocean1 last updated on 06/Jan/20 $$\mathrm{Hello}\:\mathrm{sirs}…\: \\ $$$$\mathrm{i}\:\mathrm{want}\:\mathrm{that}\:\mathrm{you}\:\mathrm{explain}\:\mathrm{me}\:\mathrm{how}\: \\ $$$$\:\mathrm{we}\:\mathrm{solve}\:\mathrm{the}\:\mathrm{trigonometric} \\ $$$$\mathrm{inequality}\:\mathrm{with}\:\mathrm{tangente}.\: \\ $$$$\mathrm{we}\:\mathrm{can}\:\mathrm{take}\:\mathrm{for}\:\mathrm{example}\:\mathrm{tan2x}\geqslant\sqrt{\mathrm{3}} \\ $$$$\mathrm{i}\:\mathrm{can}\:\mathrm{solve}\:\mathrm{this}\:\mathrm{type}\:\mathrm{of}\:\mathrm{equality} \\ $$$$\mathrm{but}\:\mathrm{not}\:\mathrm{the}\:\mathrm{inequality}!\:\mathrm{Please}\: \\ $$$$\mathrm{i}\:\mathrm{need}\:\mathrm{your}\:\mathrm{help}…\:\mathrm{Even}\:\mathrm{the}\:\mathrm{steps} \\…

dx-5-4x-x-2-is-this-answer-correct-ln-1-4-x-5-ln6-1-x-C-

Question Number 11937 by tawa last updated on 05/Apr/17 $$\int\frac{\mathrm{dx}}{\:\sqrt{\mathrm{5}\:+\:\mathrm{4x}\:−\:\mathrm{x}^{\mathrm{2}} }}\: \\ $$$$ \\ $$$$ \\ $$$$\mathrm{is}\:\mathrm{this}\:\mathrm{answer}\:\mathrm{correct}\:?\:\:\:\:\:\:\:\:\:\:\:−\mathrm{ln}\left[\mathrm{1}/\mathrm{4}\left(\mathrm{x}\:−\:\mathrm{5}\right)\:−\:\mathrm{ln6}\left(−\:\mathrm{1}\:−\:\mathrm{x}\right)\right]\:+\:\mathrm{C} \\ $$ Commented by ridwan balatif last updated…