Menu Close

Author: Tinku Tara

Question-194425

Question Number 194425 by cortano12 last updated on 06/Jul/23 $$\:\:\:\:\:\:\:\underbrace{ } \\ $$ Answered by horsebrand11 last updated on 06/Jul/23 $$\:\:\:\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\:\frac{\sqrt{\mathrm{sin}\:\mathrm{x}}\:\left(\mathrm{1}+\frac{\sqrt{\mathrm{sin}\:\mathrm{x}}}{\mathrm{cos}\:\mathrm{x}}\right)}{\:\sqrt{\mathrm{x}}\:\left(\mathrm{1}+\:\sqrt{\mathrm{x}}\:\right)}=\:\mathrm{1} \\ $$…

If-a-b-c-gt-0-such-that-a-b-c-3-prove-that-1-1-ab-1-1-ac-1-1-bc-9-2-a-b-c-

Question Number 194421 by York12 last updated on 06/Jul/23 $$ \\ $$$${If}\:{a}\:,\:{b}\:,\:{c}\:>\mathrm{0}\:,\:{such}\:{that}\:{a}+{b}+{c}=\mathrm{3} \\ $$$${prove}\:{that} \\ $$$$\frac{\mathrm{1}}{\mathrm{1}+{ab}}+\frac{\mathrm{1}}{\mathrm{1}+{ac}}+\frac{\mathrm{1}}{\mathrm{1}+{bc}}\geqslant\frac{\mathrm{9}}{\mathrm{2}\left(\sqrt{{a}}+\sqrt{{b}}+\sqrt{{c}}\right)} \\ $$ Commented by York12 last updated on 07/Jul/23…

Question-194436

Question Number 194436 by sonukgindia last updated on 06/Jul/23 Answered by Frix last updated on 06/Jul/23 $$\mathrm{3}\:?\:\sqrt{\mathrm{3}}+\sqrt[{\mathrm{3}}]{\mathrm{2}} \\ $$$$\mathrm{3}−\sqrt{\mathrm{3}}\:?\:\sqrt[{\mathrm{3}}]{\mathrm{2}} \\ $$$$\mathrm{54}−\mathrm{30}\sqrt{\mathrm{3}}\:?\:\mathrm{2} \\ $$$$\mathrm{52}\:?\:\mathrm{30}\sqrt{\mathrm{3}} \\ $$$$\frac{\mathrm{26}}{\mathrm{15}}\:?\:\sqrt{\mathrm{3}}…

calcul-e-2ln-1-u-e-2ln-1-u-

Question Number 194434 by SANOGO last updated on 06/Jul/23 $${calcul} \\ $$$${e}^{\mathrm{2}{ln}\left(\mathrm{1}+{u}\right)\:} −{e}^{−\mathrm{2}{ln}\left(\mathrm{1}+{u}\right)} \:=? \\ $$ Answered by aba last updated on 06/Jul/23 $$\mathrm{e}^{\mathrm{2ln}\left(\mathrm{1}+\mathrm{u}\right)} −\mathrm{e}^{−\mathrm{2ln}\left(\mathrm{1}+\mathrm{u}\right)}…

Question-194363

Question Number 194363 by sonukgindia last updated on 05/Jul/23 Commented by Frix last updated on 05/Jul/23 $$\mathrm{There}'\mathrm{s}\:\mathrm{no}\:\mathrm{solution}. \\ $$$$\sqrt{{z}_{\mathrm{1}} +\sqrt{{z}_{\mathrm{2}} }}+\sqrt{{z}_{\mathrm{1}} −\sqrt{{z}_{\mathrm{2}} }}={r} \\ $$$$\mathrm{Solving}\:\mathrm{by}\:\mathrm{2}\:\mathrm{times}\:\left[\mathrm{squaring}\:\left(\mathrm{introduces}\right.\right.…

49-20-6-

Question Number 194389 by mathlove last updated on 05/Jul/23 $$\sqrt{\sqrt{\mathrm{49}+\mathrm{20}\sqrt{\mathrm{6}}}}=? \\ $$ Answered by som(math1967) last updated on 05/Jul/23 $$\sqrt{\sqrt{\mathrm{5}^{\mathrm{2}} +\left(\mathrm{2}\sqrt{\mathrm{6}}\right)^{\mathrm{2}} +\mathrm{2}.\mathrm{5}.\mathrm{2}\sqrt{\mathrm{6}}}} \\ $$$$\sqrt{\sqrt{\left(\mathrm{5}+\mathrm{2}\sqrt{\mathrm{6}}\right)^{\mathrm{2}} }}…

v2-282-has-been-published-This-update-fixes-issues-with-missed-notifications-and-adds-an-arbitarary-precision-scientific-calculator-

Question Number 194359 by Tinku Tara last updated on 05/Jul/23 $${v}\mathrm{2}.\mathrm{282}\:\mathrm{has}\:\mathrm{been}\:\mathrm{published}.\:\mathrm{This} \\ $$$$\mathrm{update}\:\mathrm{fixes}\:\mathrm{issues}\:\mathrm{with}\:\mathrm{missed} \\ $$$$\mathrm{notifications}\:\mathrm{and}\:\mathrm{adds}\:\mathrm{an} \\ $$$$\mathrm{arbitarary}\:\mathrm{precision}\: \\ $$$$\mathrm{scientific}\:\mathrm{calculator}. \\ $$ Commented by som(math1967) last…