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Author: Tinku Tara

Question-77420

Question Number 77420 by BK last updated on 06/Jan/20 Commented by mr W last updated on 06/Jan/20 $${the}\:{three}\:{triangles}\:{are}\:{similar}. \\ $$$${the}\:{radii}\:{of}\:{their}\:{incircles}\:{are}\:{in} \\ $$$${the}\:{same}\:{ratio}\:{as}\:{their}\:{side}\:{lengthes}, \\ $$$${therefore}\:{x}=\mathrm{5}. \\…

Draw-the-structural-formula-of-the-compound-2-2-7-trimethyl-4-1-methylpropyl-nonane-

Question Number 11883 by tawa last updated on 03/Apr/17 $$\mathrm{Draw}\:\mathrm{the}\:\mathrm{structural}\:\mathrm{formula}\:\mathrm{of}\:\mathrm{the}\:\mathrm{compound} \\ $$$$\mathrm{2},\mathrm{2},\mathrm{7}\:-\:\mathrm{trimethyl}\:-\:\mathrm{4}\:-\:\left(\mathrm{1}\:-\:\mathrm{methylpropyl}\right)\:\mathrm{nonane} \\ $$ Answered by sandy_suhendra last updated on 04/Apr/17 Commented by tawa last…

S-ABCD-3-2-2-BAO-MAO-22-5-BCM-DCM-S-AOB-

Question Number 11880 by @ANTARES_VY last updated on 03/Apr/17 $$\boldsymbol{\mathrm{S}}_{\boldsymbol{\mathrm{ABCD}}} =\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}} \\ $$$$\angle\boldsymbol{\mathrm{BAO}}=\angle\boldsymbol{\mathrm{MAO}}=\mathrm{22},\mathrm{5}° \\ $$$$\angle\boldsymbol{\mathrm{BCM}}=\angle\boldsymbol{\mathrm{DCM}} \\ $$$$\boldsymbol{\mathrm{S}}_{\boldsymbol{\mathrm{AOB}}} =? \\ $$ Terms of Service Privacy Policy…

Question-77412

Question Number 77412 by BK last updated on 06/Jan/20 Commented by Tony Lin last updated on 06/Jan/20 $$\zeta\left({s}\right)=\frac{\mathrm{1}}{\mathrm{1}^{{s}} }+\frac{\mathrm{1}}{\mathrm{2}^{{s}} }+\frac{\mathrm{1}}{\mathrm{3}^{{s}} }+\centerdot\centerdot\centerdot+\frac{\mathrm{1}}{{n}^{{s}} } \\ $$$$\zeta\left(\mathrm{2}\right)=\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}}…