Question Number 194384 by Mingma last updated on 05/Jul/23 Commented by Bharathi last updated on 05/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194386 by SANOGO last updated on 05/Jul/23 $${calcul}\:{the}\:{the}\:{derive}\:{of} \\ $$$${cos}^{\mathrm{3}} \left(\frac{\theta}{\mathrm{3}}\right)' \\ $$ Answered by Frix last updated on 05/Jul/23 $${f}\left({t}\right)={t}^{\mathrm{3}} \\ $$$${g}\left({t}\right)=\mathrm{cos}\:{t}…
Question Number 194412 by SaRahAli last updated on 05/Jul/23 Answered by som(math1967) last updated on 05/Jul/23 $$\:\int{ln}\left({lnx}\right){dx}+\int\frac{{dx}}{\left({lnx}\right)^{\mathrm{2}} } \\ $$$$={ln}\left({lnx}\right)\int{dx}−\int\left\{\frac{{d}}{{dx}}{ln}\left({lnx}\right)\int{dx}\right\}{dx} \\ $$$$\:\:+\int\frac{{dx}}{\left({lnx}\right)^{\mathrm{2}} } \\ $$$$={xln}\left({lnx}\right)−\int\frac{{xdx}}{{xlnx}}\:+\int\frac{{dx}}{\left({lnx}\right)^{\mathrm{2}}…
Question Number 194383 by Mingma last updated on 05/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194410 by necx122 last updated on 05/Jul/23 Commented by necx122 last updated on 05/Jul/23 $${I}'{ve}\:{dedicated}\:{sometime}\:{to}\:{solving}\:{the} \\ $$$${question}\:{but}\:{it}\:{seems}\:{as}\:{though}\:{some} \\ $$$${parameters}\:{are}\:{missing}.{Please}\:{help} \\ $$$${me}\:{out}.\: \\ $$…
Question Number 194373 by MM42 last updated on 05/Jul/23 $${Show}\:\:\: \\ $$$$\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\frac{\mathrm{1}}{\mathrm{2}{i}−\mathrm{1}}−\:\frac{\mathrm{1}}{\mathrm{2}{i}}\right)=\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\:\frac{\mathrm{1}}{{n}+{i}}\: \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 194406 by Safojon last updated on 05/Jul/23 Answered by BaliramKumar last updated on 05/Jul/23 $$\mathrm{i}\:\mathrm{find}\:\mathrm{2007}^{\mathrm{th}} \:\mathrm{digit}\:=\:\mathrm{5} \\ $$ Commented by Safojon last updated…
Question Number 194401 by Tinku Tara last updated on 05/Jul/23 $$\mathrm{Hi} \\ $$$$\mathrm{Please}\:\mathrm{do}\:\mathrm{not}\:\mathrm{post}\:\mathrm{junk}\:\mathrm{content}\:\mathrm{in} \\ $$$$\mathrm{this}\:\mathrm{forum}.\:\mathrm{It}\:\mathrm{does}\:\mathrm{not}\:\mathrm{help}\:\mathrm{you}\:\mathrm{in} \\ $$$$\mathrm{anyway}\:\mathrm{and}\:\mathrm{it}\:\mathrm{increases}\:\mathrm{our}\:\mathrm{effort}\: \\ $$$$\mathrm{in}\:\mathrm{cleaning}\:\mathrm{up}. \\ $$ Terms of Service Privacy…
Question Number 194335 by mathlove last updated on 04/Jul/23 Answered by cortano12 last updated on 04/Jul/23 $$\:\:\:\underbrace{\lesseqgtr^{} } \\ $$ Commented by mathlove last updated…
Question Number 194350 by SaRahAli last updated on 04/Jul/23 Answered by MM42 last updated on 04/Jul/23 $$\mathrm{1}+\sqrt{−\mathrm{1}}=\mathrm{1}+{i}=\sqrt{\mathrm{2}}×{e}^{\frac{\pi}{\mathrm{4}}{i}} \\ $$$$\Rightarrow\left(\mathrm{1}+{t}\right)^{\mathrm{20}} =\mathrm{2}^{\mathrm{10}} ×{e}^{\mathrm{5}\pi{i}} =−\mathrm{1024}\:\checkmark \\ $$$$ \\…