Question Number 194334 by cortano12 last updated on 04/Jul/23 $$\:\:\:\:\underbrace{ ^{} } \\ $$ Commented by Frix last updated on 04/Jul/23 $$\mathrm{The}\:\mathrm{real}\:\mathrm{part}\:\rightarrow\:\mathrm{0}\:\mathrm{but}\:\mathrm{the}\:\mathrm{imaginary}\:\mathrm{part} \\ $$$$\mathrm{is}\:<\mathrm{0}\:\mathrm{for}\:{x}<\mathrm{0}\:\mathrm{and}\:>\mathrm{0}\:\mathrm{for}\:{x}>\mathrm{0}\:\Rightarrow\:\mathrm{limit}\:\mathrm{does} \\…
Question Number 194344 by mathlove last updated on 04/Jul/23 Answered by qaz last updated on 04/Jul/23 $$\mathrm{sin}\:^{\mathrm{2}} {x}=\left({x}−\frac{\mathrm{1}}{\mathrm{6}}{x}^{\mathrm{3}} +…\right)^{\mathrm{2}} ={x}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{3}}{x}^{\mathrm{4}} +… \\ $$$${e}^{{x}} +{e}^{−{x}}…
Question Number 194343 by BaliramKumar last updated on 04/Jul/23 $$\lfloor\mathrm{9}.\overset{−} {\mathrm{9}}\rfloor\:=\:? \\ $$ Answered by MM42 last updated on 04/Jul/23 $$\mathrm{9} \\ $$ Answered by…
Question Number 194352 by cortano12 last updated on 04/Jul/23 $$\:\:\:\:\Subset \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194338 by mathlove last updated on 04/Jul/23 Answered by Peace last updated on 04/Jul/23 $${e}^{{cos}\left({t}\right){ln}\left(\mathrm{2}+{sin}\left({t}\right)\right)} −\mathrm{2}={f}\left({t}\right) \\ $$$$\left.{f}\:{in}\:\left[\mathrm{0},{x}\right];\exists{c}\in\right]\mathrm{0},{x}\left[\right. \\ $$$$\Rightarrow{f}\left({x}\right)−{f}\left(\mathrm{0}\right)={f}'\left({c}\right)\left({x}−\mathrm{0}\right) \\ $$$$\Rightarrow{f}'\left({c}\right)=\frac{\left(\mathrm{2}+{sin}\left({x}\right)\right)^{{cos}\left({x}\right)} −\mathrm{2}}{{x}}…
Question Number 194331 by 073 last updated on 03/Jul/23 Answered by Frix last updated on 03/Jul/23 $$\mathrm{cos}\:{x}\:={C} \\ $$$${A}+{B}=\mathrm{1}\:\Leftrightarrow\:{B}=\mathrm{1}−{A} \\ $$$${S}_{{n}} ={C}^{\mathrm{4}} {A}^{{n}} +\left({C}^{\mathrm{2}} −\mathrm{1}\right)^{\mathrm{2}}…
Question Number 194325 by horsebrand11 last updated on 03/Jul/23 $$\:\:\cancel{\mathcal{X}} \\ $$ Answered by AST last updated on 04/Jul/23 $$\sqrt[{\mathrm{4}_{} }]{\frac{{x}^{\mathrm{4}} +{y}^{\mathrm{4}} +{z}^{\mathrm{4}} }{\mathrm{3}}}\geqslant\sqrt{\frac{{x}^{\mathrm{2}} +{y}^{\mathrm{2}}…
Question Number 194327 by pete last updated on 03/Jul/23 $$\mathrm{If}\:\mathrm{ta4}\theta\:=\:\mathrm{1},\:\mathrm{find}\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:\theta. \\ $$ Answered by MikeH last updated on 03/Jul/23 $$\mathrm{tan}\:\mathrm{4}\theta\:=\:\mathrm{1}\: \\ $$$$\Rightarrow\:\mathrm{4}\theta\:=\:\pi{n}\:+\:\frac{\mathrm{1}}{\mathrm{4}}\pi \\ $$$$\Rightarrow\:\theta\:=\:\frac{\mathrm{1}}{\mathrm{4}}\pi{n}\:+\:\frac{\mathrm{1}}{\mathrm{16}}\pi \\…
Question Number 194326 by horsebrand11 last updated on 03/Jul/23 $$\:\:\sqrt{\frac{\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{66}^{\mathrm{2}} +\mathrm{x}}}{\mathrm{x}}\:}\:−\sqrt{\mathrm{x}\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{66}^{\mathrm{2}} }−\mathrm{x}^{\mathrm{2}} }\:=\:\mathrm{5}\: \\ $$ Answered by cortano12 last updated on 03/Jul/23 $$\:\:\:\cancel{\lesseqgtr}…
Question Number 194321 by CrispyXYZ last updated on 04/Jul/23 $$\mathrm{find}\:\mathrm{min}\:\:−\frac{\left({x}−{y}\right)\left(\frac{{xy}}{\mathrm{4}}−\mathrm{4}\right)^{\mathrm{2}} }{{xy}} \\ $$$$\mathrm{s}.\:\mathrm{t}.\:\:{x}>\mathrm{0}>{y} \\ $$ Answered by Frix last updated on 04/Jul/23 $${f}\left({x},{y}\right)=−\frac{\left({x}−{y}\right)\left(\frac{{xy}}{\mathrm{4}}−\mathrm{4}\right)^{\mathrm{2}} }{{xy}}=−\frac{\left({x}−{y}\right)\left({xy}−\mathrm{16}\right)^{\mathrm{2}} }{\mathrm{16}{xy}}…