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Author: Tinku Tara

a-8-a-4-1-a-6-1-solves-

Question Number 11477 by @ANTARES_VY last updated on 26/Mar/17 $$\frac{\boldsymbol{\mathrm{a}}^{\mathrm{8}} +\boldsymbol{\mathrm{a}}^{\mathrm{4}} +\mathrm{1}}{\boldsymbol{\mathrm{a}}^{\mathrm{6}} +\mathrm{1}}. \\ $$$$\boldsymbol{\mathrm{solves}}…. \\ $$ Answered by sm3l2996 last updated on 26/Mar/17 $$\mathrm{a}^{\mathrm{8}}…

Question-11476

Question Number 11476 by tawa last updated on 26/Mar/17 Answered by sandy_suhendra last updated on 27/Mar/17 $$\frac{\mathrm{1}}{\left(\mathrm{a}−\mathrm{b}\right)\left(\mathrm{b}−\mathrm{c}\right)}\:+\:\frac{\mathrm{1}}{\left(\mathrm{b}−\mathrm{c}\right)\left(\mathrm{c}−\mathrm{a}\right)}\:+\:\frac{\mathrm{1}}{\left(\mathrm{c}−\mathrm{a}\right)\left(\mathrm{a}−\mathrm{b}\right)}\:\: \\ $$$$=\frac{\mathrm{c}−\mathrm{a}+\mathrm{a}−\mathrm{b}+\mathrm{b}−\mathrm{c}}{\left(\mathrm{a}−\mathrm{b}\right)\left(\mathrm{b}−\mathrm{c}\right)\left(\mathrm{c}−\mathrm{a}\right)}\:=\:\mathrm{0} \\ $$$$ \\ $$$$\frac{\mathrm{1}}{\left(\mathrm{a}−\mathrm{b}\right)^{\mathrm{2}} }\:+\:\frac{\mathrm{1}}{\left(\mathrm{b}−\mathrm{c}\right)^{\mathrm{2}} }\:+\:\frac{\mathrm{1}}{\left(\mathrm{c}−\mathrm{a}\right)^{\mathrm{2}}…

Question-11475

Question Number 11475 by tawa last updated on 26/Mar/17 Answered by sm3l2996 last updated on 26/Mar/17 $$\mathrm{Question}\:\mathrm{105}:\left(\mathrm{B}\right) \\ $$$$\mathrm{Question}\:\mathrm{106}: \\ $$$$\Delta\mathrm{AFD}=\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{2}}=\frac{\mathrm{25}}{\mathrm{2}}=\mathrm{12}.\mathrm{5}\:\left(\mathrm{C}\right) \\ $$ Commented…

Show-that-the-graph-of-y-x-3-2x-2-x-1-between-x-1-and-x-2-lies-entirely-above-the-x-axis-

Question Number 11473 by tawa last updated on 26/Mar/17 $$\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{graph}\:\mathrm{of}\:\:\mathrm{y}\:=\:\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{2x}^{\mathrm{2}} \:+\:\mathrm{x}\:+\:\mathrm{1}\:,\:\mathrm{between}\:\mathrm{x}\:=\:−\:\mathrm{1}\:\mathrm{and}\:\mathrm{x}\:=\:\mathrm{2} \\ $$$$\mathrm{lies}\:\mathrm{entirely}\:\mathrm{above}\:\mathrm{the}\:\mathrm{x}\:−\:\mathrm{axis} \\ $$ Commented by prakash jain last updated on 28/Mar/17 $${y}={x}^{\mathrm{3}}…

Question-77009

Question Number 77009 by Master last updated on 02/Jan/20 Commented by Master last updated on 02/Jan/20 $$\mathrm{lose}\:\mathrm{x}\:\mathrm{from}\:\mathrm{the}\:\mathrm{system}\left(\mathrm{find}\:\mathrm{the}\:\mathrm{connection}\:\mathrm{between}\:\mathrm{a}\:\mathrm{and}\:\mathrm{c}\right) \\ $$ Commented by MJS last updated on…