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Question Number 194316 by SajaRashki last updated on 03/Jul/23 $${if}\:\:{x}\in{R}\:\:\&\:\:{x}^{{x}^{\mathrm{6}} } =\left(\sqrt{\mathrm{2}}\right)^{\sqrt{\mathrm{2}}} \:\Rightarrow\:\:{x}=? \\ $$ Commented by Frix last updated on 03/Jul/23 $${x}=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{4}}} \\ $$$$\Rightarrow\:{x}^{\mathrm{6}}…
Question Number 194312 by Mingma last updated on 03/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194315 by cortano12 last updated on 03/Jul/23 $$\:\:\:\:\: \\ $$ Answered by Frix last updated on 03/Jul/23 $$\mathrm{This}\:\mathrm{can}\:\mathrm{be}\:\mathrm{transformed}\:\mathrm{to}\:\left[{s}=\mathrm{sin}\:{x}\right]: \\ $$$${s}^{\mathrm{4}} +\frac{{s}^{\mathrm{3}} }{\mathrm{2}}−{s}^{\mathrm{2}} −\frac{{s}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{16}}=\mathrm{0}…
Question Number 194301 by a.lgnaoui last updated on 02/Jul/23 $$\boldsymbol{\mathrm{Resolution}}\:\boldsymbol{\mathrm{de}}\:\boldsymbol{\mathrm{l}}\:\boldsymbol{\mathrm{exercice}}\:\boldsymbol{\mathrm{du}}\:\mathrm{28}.\mathrm{6}.\mathrm{23} \\ $$$$\:\:\left({env}\mathrm{o}{ye}\:{par}\:{universe}\:\right) \\ $$$$\boldsymbol{{Q}}\mathrm{194116} \\ $$$$ \\ $$ Answered by a.lgnaoui last updated on 02/Jul/23…
Let-a-b-c-be-real-positive-numbers-amp-abc-1-prove-that-ab-a-5-b-5-ab-bc-b-5-c-5-bc-ac-a-5-c-5-ac-1-
Question Number 194297 by York12 last updated on 02/Jul/23 $${Let}\:{a}\:,\:{b}\:,\:{c}\:{be}\:\:{real}\:{positive}\:{numbers}\:\&\: \\ $$$${abc}=\mathrm{1}\: \\ $$$${prove}\:{that} \\ $$$$\frac{{ab}}{{a}^{\mathrm{5}} +{b}^{\mathrm{5}} +{ab}}+\frac{{bc}}{{b}^{\mathrm{5}} +{c}^{\mathrm{5}} +{bc}}+\frac{{ac}}{{a}^{\mathrm{5}} +{c}^{\mathrm{5}} +{ac}}\leqslant\mathrm{1} \\ $$ Answered…
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Question Number 194295 by Abdullahrussell last updated on 02/Jul/23 Answered by BaliramKumar last updated on 02/Jul/23 $$\mathrm{1}!×\mathrm{2}!×\mathrm{3}!×………………×\mathrm{2023}! \\ $$$$\mathrm{1}^{\mathrm{2023}} ×\mathrm{2}^{\mathrm{2022}} ×\mathrm{3}^{\mathrm{2021}} ×………………×\mathrm{2023}^{\mathrm{1}} \\ $$$$\mathrm{1}^{\mathrm{2023}} ×…×\mathrm{5}^{\mathrm{2019}}…
Question Number 194286 by mokys last updated on 02/Jul/23 $$ \\ $$$$\:\:\boldsymbol{{find}}\:\underset{\boldsymbol{{x}}\rightarrow\mathrm{0}} {\boldsymbol{{lim}}}\:\lfloor\:\frac{\boldsymbol{{tan}}\left(\boldsymbol{{x}}\right)}{\boldsymbol{{x}}}\rfloor \\ $$ Answered by tri26112004 last updated on 02/Jul/23 $$=\:\mathrm{1} \\ $$…