Question Number 142488 by rs4089 last updated on 01/Jun/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{t}^{{k}−\mathrm{1}} }{\mathrm{1}+{t}^{\mathrm{2}} }{dt} \\ $$ Answered by Ar Brandon last updated on 01/Jun/21 $$\Phi=\int_{\mathrm{0}}…
Question Number 76955 by behi83417@gmail.com last updated on 01/Jan/20 $$\int\:\:\frac{\boldsymbol{\mathrm{x}}^{\boldsymbol{\mathrm{p}}} }{\:\sqrt{\mathrm{1}\pm\boldsymbol{\mathrm{x}}^{\boldsymbol{\mathrm{q}}} }}\:\boldsymbol{\mathrm{dx}}=?\:\:\:\:\left[\boldsymbol{\mathrm{p}}+\boldsymbol{\mathrm{q}}=\mathrm{2}\boldsymbol{\mathrm{n}}\in\boldsymbol{\mathrm{N}},\boldsymbol{\mathrm{p}}<\boldsymbol{\mathrm{q}}\right] \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 76952 by ~blr237~ last updated on 01/Jan/20 $$\mathrm{show}\:\mathrm{that}\: \\ $$$$\sqrt{\mathrm{1}+\:\mathrm{2017}×\mathrm{2018}×\mathrm{2019}×\mathrm{2020}\:}\:\in\:\mathbb{N} \\ $$ Answered by MJS last updated on 01/Jan/20 $$\mathrm{1}+{x}\left({x}+\mathrm{1}\right)\left({x}+\mathrm{2}\right)\left({x}+\mathrm{3}\right)= \\ $$$$={x}^{\mathrm{4}} +\mathrm{6}{x}^{\mathrm{3}}…
Question Number 11417 by Joel576 last updated on 25/Mar/17 $${A}\:=\:\mathrm{log}\:\left(\mathrm{5}{x}\:+\:\mathrm{1}\right)\left(\mathrm{3}{x}\:+\:\mathrm{5}\right) \\ $$$${B}\:=\:\frac{\mathrm{1}}{\mathrm{log}\:\left(\mathrm{5}{x}+\:\mathrm{1}\right)\left({x}\:−\:\mathrm{1}\right)} \\ $$$$\mathrm{If}\:{A}\:+\:{B}\:\geqslant\:\mathrm{1},\:{x}\:\mathrm{must}\:\mathrm{be}\:… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 11416 by anisa last updated on 25/Mar/17 Answered by Joel576 last updated on 25/Mar/17 $$=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{2}\:\mathrm{sin}^{\mathrm{2}} \:{x}}{\mathrm{2}{x}\:\mathrm{sin}\:\mathrm{2}{x}} \\ $$$$=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{2}}{\mathrm{2}}\:.\:\frac{\mathrm{sin}\:{x}}{{x}}\:.\:\frac{\mathrm{sin}\:{x}}{\mathrm{sin}\:\mathrm{2}{x}} \\ $$$$=\:\mathrm{1}\:.\:\mathrm{1}\:.\:\frac{\mathrm{1}}{\mathrm{2}} \\…
Question Number 76948 by Master last updated on 01/Jan/20 Answered by mr W last updated on 02/Jan/20 $${let}\:\alpha=\angle{A} \\ $$$$\angle{B}=\frac{\pi}{\mathrm{2}}−\frac{\alpha}{\mathrm{2}} \\ $$$${AB}={AC}=\frac{\mathrm{1}}{\mathrm{2}\:\mathrm{sin}\:\frac{\alpha}{\mathrm{2}}} \\ $$$$\left(\sqrt{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{1}^{\mathrm{2}}…
Question Number 11413 by agni5 last updated on 24/Mar/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{arc}\:\mathrm{of}\:\mathrm{the}\:\mathrm{hyperbolic} \\ $$$$\mathrm{spiral}\:\:\mathrm{r}\theta=\mathrm{a}\:\:\mathrm{lying}\:\mathrm{between}\:\:\mathrm{r}=\mathrm{a}\:\:\mathrm{and}\: \\ $$$$\mathrm{r}=\mathrm{2a}. \\ $$ Answered by mrW1 last updated on 26/Mar/17 $${r}=\frac{{a}}{\theta} \\…
Question Number 76949 by Master last updated on 01/Jan/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 11408 by anisa last updated on 24/Mar/17 Answered by sm3l2996 last updated on 24/Mar/17 $$=\frac{\mathrm{sin}\left(\frac{\mathrm{4}\pi}{\mathrm{3}}\right)+\mathrm{cos}\left(\frac{\mathrm{4}\pi}{\mathrm{3}}\right)}{\mathrm{tg}\left(\frac{\mathrm{4}\pi}{\mathrm{3}}\right)}=\frac{\frac{−\sqrt{\mathrm{3}}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}}}{\:\sqrt{\mathrm{3}}} \\ $$$$=−\frac{\sqrt{\mathrm{3}}+\mathrm{1}}{\mathrm{2}\sqrt{\mathrm{3}}} \\ $$ Terms of Service Privacy…
Question Number 142477 by mohammad17 last updated on 01/Jun/21 Terms of Service Privacy Policy Contact: info@tinkutara.com