Question Number 76926 by aliesam last updated on 01/Jan/20 Commented by aliesam last updated on 01/Jan/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 11389 by tawa last updated on 23/Mar/17 $$\mathrm{Given}\:\mathrm{that}\:\mathrm{the}\:\mathrm{mean}\:\mathrm{relative}\:\mathrm{atomic}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{chlorine}\:\mathrm{contain}\:\mathrm{two}\:\mathrm{isotopes} \\ $$$$\mathrm{of}\:\mathrm{mass}\:\mathrm{numbe}\:\mathrm{35}\:\mathrm{and}\:\mathrm{37}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{percentage}\:\mathrm{of}\:\mathrm{composition}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{isotope}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{number}\:\mathrm{37}\: \\ $$ Answered by sandy_suhendra last updated on 23/Mar/17 $$\mathrm{isotope}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{number}\:\mathrm{37}=\mathrm{x\%} \\…
Question Number 142462 by BHOOPENDRA last updated on 01/Jun/21 Answered by MJS_new last updated on 01/Jun/21 $${y}={px}\:\Rightarrow\:\frac{{xy}+\mathrm{2}}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }=\frac{{p}}{{p}^{\mathrm{2}} +\mathrm{1}}+\frac{\mathrm{2}}{{p}^{\mathrm{2}} +\mathrm{1}}×\frac{\mathrm{1}}{{x}^{\mathrm{2}} } \\ $$$${p}\in\mathbb{R}\:\Rightarrow\:\frac{{p}}{{p}^{\mathrm{2}} +\mathrm{1}}={q}\in\mathbb{R}\wedge{r}=\frac{\mathrm{2}}{{p}^{\mathrm{2}}…
Question Number 11388 by tawa last updated on 23/Mar/17 $$\mathrm{A}\:\mathrm{cell}\:\mathrm{supplies}\:\mathrm{a}\:\mathrm{current}\:\mathrm{of}\:\mathrm{6}\:\mathrm{ameter}\:\mathrm{through}\:\mathrm{a}\:\mathrm{2}\:\mathrm{coil}\:\mathrm{and}\:\mathrm{a}\:\mathrm{current}\:\mathrm{of}\:\mathrm{0}.\mathrm{2}\: \\ $$$$\mathrm{ameter}\:\mathrm{through}\:\mathrm{7}\:\mathrm{coil}.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{limits}\:\mathrm{and}\:\mathrm{the}\:\mathrm{internal}\:\mathrm{resistance} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{cell} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 142457 by ajfour last updated on 01/Jun/21 $$\:{I}=\int\frac{{dx}}{\:\sqrt{{a}^{\mathrm{2}} −\left({x}+\frac{\mathrm{1}}{{x}}\right)}} \\ $$ Answered by MJS_new last updated on 01/Jun/21 $$\mathrm{I}'\mathrm{m}\:\mathrm{afraid}\:\mathrm{you}'\mathrm{re}\:\mathrm{ending}\:\mathrm{on}\:\mathrm{elliptic}\:\mathrm{functions} \\ $$$$\mathrm{again}. \\ $$$$\mathrm{my}\:\mathrm{try}:…
Question Number 76922 by TawaTawa last updated on 01/Jan/20 Commented by ajfour last updated on 13/Jan/20 $${this}\:{post}\:{always}\:{comes}\:{at} \\ $$$${my}\:{recent}\:{activity}\:{page},\:{not} \\ $$$${matter}\:{what}\:{the}\:{recent}\:{posts} \\ $$$${there}\:{are},\:{something}\:{wrong}…! \\ $$$${Admin}\:{please}\:{help}.…
Question Number 142459 by bramlexs22 last updated on 01/Jun/21 $$\:\:\:\:\:\:−−−−−−−−−−− \\ $$$$\:\:\:\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}} {\mathrm{lim}}\:\left(\frac{{x}}{\mathrm{cot}\:{x}}−\frac{\pi}{\mathrm{2cos}\:{x}}\right)=? \\ $$$$\:\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \\ $$ Answered by benjo_mathlover last updated on 01/Jun/21 $$\:\:\:\:\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}}…
Question Number 76920 by jagoll last updated on 01/Jan/20 $${how}\:{can}\:{i}\:{solve}\: \\ $$$$\int\:\frac{\mathrm{sin}\:{x}\:{dx}}{{x}^{\mathrm{2}} \:{e}^{{x}} }\:?\:{can}\:{using}\:{elementary} \\ $$$${calculus}? \\ $$ Commented by MJS last updated on 01/Jan/20…
Question Number 11384 by tawa last updated on 22/Mar/17 $$\mathrm{Out}\:\mathrm{of}\:\mathrm{5}\:\mathrm{accountants}\:\mathrm{and}\:\mathrm{7}\:\mathrm{bankers},\:\mathrm{a}\:\mathrm{committee}\:\mathrm{consisting}\:\mathrm{of}\: \\ $$$$\mathrm{2}\:\mathrm{accountants}\:\mathrm{and}\:\mathrm{3}\:\mathrm{bankers}\:\mathrm{is}\:\mathrm{to}\:\mathrm{be}\:\mathrm{formed}.\:\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{this} \\ $$$$\mathrm{be}\:\mathrm{done}\:\mathrm{if} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{Any}\:\mathrm{acountant}\:\mathrm{and}\:\mathrm{any}\:\mathrm{bankers}\:\mathrm{must}\:\mathrm{be}\:\mathrm{included} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{One}\:\mathrm{particular}\:\mathrm{banker}\:\mathrm{must}\:\mathrm{be}\:\mathrm{included} \\ $$$$\left(\mathrm{c}\right)\:\mathrm{2}\:\mathrm{accountant}\:\mathrm{cannot}\:\mathrm{be}\:\mathrm{in}\:\mathrm{the}\:\mathrm{committee} \\ $$ Answered by sandy_suhendra…
Question Number 11383 by tawa last updated on 22/Mar/17 $$\mathrm{There}\:\mathrm{are}\:\mathrm{six}\:\mathrm{trains}\:\mathrm{travelling}\:\mathrm{between}\:\mathrm{Abuja}\:\mathrm{and}\:\mathrm{Lagos}\:\mathrm{and}\:\mathrm{back}. \\ $$$$\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{a}\:\mathrm{man}\:\mathrm{travel}\:\mathrm{from}\:\mathrm{abuja}\:\mathrm{to}\:\mathrm{Lagos}\:\mathrm{by}\:\mathrm{one}\:\mathrm{train}\:\mathrm{and} \\ $$$$\mathrm{return}\:\mathrm{by}\:\mathrm{a}\:\mathrm{different}\:\mathrm{train} \\ $$ Answered by sandy_suhendra last updated on 23/Mar/17 $$\mathrm{Abuja}\:\mathrm{to}\:\mathrm{Lagos}\:=\:\mathrm{6}\:\mathrm{trains} \\…