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Author: Tinku Tara

n-c-n-n-n-n-n-

Question Number 11344 by jaskaurrangerleader@gmail.com last updated on 21/Mar/17 $${n}_{{c}_{{n}} } =\frac{{n}!}{\left({n}−{n}\right)!{n}!} \\ $$ Commented by FilupS last updated on 21/Mar/17 $$\frac{{n}!}{\left({n}−{n}\right)!\centerdot{n}!}=\frac{\mathrm{1}}{\mathrm{0}!} \\ $$$$=\frac{\mathrm{1}}{\mathrm{1}}=\mathrm{1} \\…

n-c-n-n1-n-n-

Question Number 11343 by jaskaurrangerleader@gmail.com last updated on 21/Mar/17 $${n}_{\boldsymbol{\mathrm{c}}_{\boldsymbol{\mathrm{n}}} } =\frac{{n}\mathrm{1}}{\left({n}−{n}\right)} \\ $$ Commented by FilupS last updated on 21/Mar/17 $$\frac{{n}}{{n}−{n}}=\mathrm{undefined} \\ $$ Terms…

x-x-4-5-x-7-7-x-5-x-

Question Number 142415 by Rankut last updated on 31/May/21 $$\frac{{x}}{{x}+\mathrm{4}}=\frac{\mathrm{5}\lfloor{x}\rfloor−\mathrm{7}}{\mathrm{7}\lfloor{x}\rfloor−\mathrm{5}} \\ $$$${x}=? \\ $$ Answered by mr W last updated on 31/May/21 $${say}\:{x}={n}+{f} \\ $$$$\frac{{n}+{f}}{{n}+{f}+\mathrm{4}}=\frac{\mathrm{5}{n}−\mathrm{7}}{\mathrm{7}{n}−\mathrm{5}}…

Question-11341

Question Number 11341 by Nadium last updated on 21/Mar/17 Commented by FilupS last updated on 22/Mar/17 $$\Omega=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{1}}{{n}^{\mathrm{4}} }\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\left(\underset{{j}=\mathrm{1}} {\overset{{n}} {\sum}}\left({i}^{\mathrm{2}} +{j}^{\mathrm{2}} \right)\mid{i}^{\mathrm{2}}…