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Author: Tinku Tara

Nice-Calculus-0-1-1-x-1-3-1-x-1-5-1-x-1-7-ln-x-1-3-dx-m-n-

Question Number 142318 by mnjuly1970 last updated on 29/May/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{Nice}…\succcurlyeq\succcurlyeq\succcurlyeq\ast\ast\ast\preccurlyeq\preccurlyeq\preccurlyeq…{Calculus} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\Omega:=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\left(\mathrm{1}−\sqrt[{\mathrm{3}}]{{x}}\:\right)\left(\mathrm{1}−\sqrt[{\mathrm{5}}]{{x}\:}\:\right)\left(\mathrm{1}−\sqrt[{\mathrm{7}}]{{x}}\:\right)}{{ln}\left(\:\sqrt[{\mathrm{3}}]{{x}\:\:}\:\right)}\:{dx}=? \\ $$$$\:\:\:\:\:\:\:….{m}.{n} \\ $$ Answered by Dwaipayan Shikari last updated on…

prove-that-cos-40-1-3-cos-80-1-3-cos-20-1-3-3-2-9-1-3-2-1-3-

Question Number 76777 by aliesam last updated on 30/Dec/19 $${prove}\:{that} \\ $$$$ \\ $$$$\sqrt[{\mathrm{3}}]{{cos}\left(\mathrm{40}°\right)}\:+\:\sqrt[{\mathrm{3}}]{{cos}\left(\mathrm{80}°\right)}\:−\:\sqrt[{\mathrm{3}}]{{cos}\left(\mathrm{20}°\right)}\:=\sqrt[{\mathrm{3}}]{\frac{\mathrm{3}}{\mathrm{2}}\left(\sqrt[{\mathrm{3}}]{\mathrm{9}}−\mathrm{2}\right)} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

lim-x-0-lnlnln-x-1-x-1-x-1-x-x-x-1-1-e-e-1-x-2-

Question Number 142308 by qaz last updated on 29/May/21 $$\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{lnlnln}\left[\mathrm{x}+\left(\mathrm{1}+\mathrm{x}\right)^{\frac{\left(\mathrm{1}+\mathrm{x}\right)^{\frac{\mathrm{1}}{\mathrm{x}}} }{\mathrm{x}}} \right]+\mathrm{x}\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{e}^{\mathrm{e}+\mathrm{1}} }\right)}{\mathrm{x}^{\mathrm{2}} }=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

f-1-2x-g-x-3-f-1-x-A-7-2g-1-x-B-2g-1-x-7-C-2g-1-x-5-D-5-2g-1-x-

Question Number 11238 by Joel576 last updated on 18/Mar/17 $${f}\left(\mathrm{1}\:−\:\mathrm{2}{x}\right)\:=\:{g}\left({x}\:+\:\mathrm{3}\right) \\ $$$${f}^{−\mathrm{1}} \left({x}\right)\:=\:? \\ $$$$ \\ $$$$\left(\mathrm{A}\right)\:\mathrm{7}\:−\:\mathrm{2}{g}^{−\mathrm{1}} \left({x}\right) \\ $$$$\left(\mathrm{B}\right)\:\mathrm{2}{g}^{−\mathrm{1}} \left({x}\right)\:+\:\mathrm{7} \\ $$$$\left(\mathrm{C}\right)\:\mathrm{2}{g}^{−\mathrm{1}} \left({x}\right)\:−\:\mathrm{5} \\…