Question Number 142036 by mathsuji last updated on 25/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 142035 by Dwaipayan Shikari last updated on 25/May/21 $$\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{1}/\mathrm{4}} }.\frac{\mathrm{3}^{\mathrm{1}/\mathrm{9}} }{\mathrm{4}^{\mathrm{1}/\mathrm{16}} }.\frac{\mathrm{5}^{\mathrm{1}/\mathrm{25}} }{\mathrm{6}^{\mathrm{1}/\mathrm{36}} }.\frac{\mathrm{7}^{\mathrm{1}/\mathrm{49}} }{\mathrm{8}^{\mathrm{1}/\mathrm{64}} }…={exp}\left(−\frac{\zeta'\left(\mathrm{2}\right)}{\mathrm{2}}−\frac{\pi^{\mathrm{2}} }{\mathrm{12}}\mathrm{log}\:\left(\mathrm{2}\right)\right) \\ $$ Answered by mindispower last…
Question Number 76497 by mathmax by abdo last updated on 27/Dec/19 $${calculate}\:{tan}\left(\mathrm{3}{x}\right)\:{interms}\:{of}\:{tanx} \\ $$ Answered by Rio Michael last updated on 27/Dec/19 $${tan}\mathrm{3}{x}\:=\:{tan}\left(\mathrm{2}{x}\:+\:{x}\right)\:=\:\frac{{tan}\mathrm{2}{x}\:+\:{tanx}}{\mathrm{1}−{tan}\mathrm{2}{xtanx}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\frac{\frac{\mathrm{2}{tanx}}{\mathrm{1}−{tan}^{\mathrm{2}}…
Question Number 142028 by mnjuly1970 last updated on 25/May/21 $$\:\:\:\:\:\:\:\:…………{Calculus}………\: \\ $$$$\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:\infty} \frac{{sin}\left({sin}\left({x}\right)\right).{e}^{{cos}\left({x}\right)} }{{x}}{dx}=??? \\ $$$$\:…………{m}.{n}….. \\ $$ Answered by mindispower last updated on…
Question Number 76495 by mathocean1 last updated on 27/Dec/19 $$\mathrm{how}\:\mathrm{that} \\ $$$$\mathrm{tan2}{x}=\frac{\mathrm{2}{tanx}}{\mathrm{1}−{tan}^{\mathrm{2}} {x}} \\ $$ Commented by mathmax by abdo last updated on 27/Dec/19 $${due}\:{to}\:{formula}\:\:{tan}\left(\mathrm{2}{x}\right)={tan}\left({x}+{x}\right)\:=\frac{{tanx}+{tanx}}{\mathrm{1}−{tanx}.{tanx}}…
Question Number 10956 by Joel576 last updated on 04/Mar/17 $${y}\:=\:\frac{{x}\:−\:\mathrm{2}}{\mathrm{2}\left({x}\:−\:\mathrm{1}\right)^{\mathrm{3}/\mathrm{2}} } \\ $$$$\mathrm{Let}\:\:{p}\:=\:{x}\:−\:\mathrm{1} \\ $$$$\Rightarrow\:{y}\:=\:\frac{{p}\:−\:\mathrm{1}}{\mathrm{2}{p}^{\mathrm{3}/\mathrm{2}} } \\ $$$$ \\ $$$$\mathrm{Is}\:\mathrm{it}\:\mathrm{true}\:\mathrm{that}\:\:\:\frac{{dy}}{{dx}}\:\:\:=\:\:\frac{{dy}}{{dp}}\:\:? \\ $$ Commented by FilupS…
Question Number 142025 by mnjuly1970 last updated on 25/May/21 Answered by som(math1967) last updated on 25/May/21 $$\left(\boldsymbol{{a}}+\boldsymbol{{b}}+\boldsymbol{{c}}\right)^{\mathrm{2}} =\mathrm{1} \\ $$$$\mathrm{2}\left(\boldsymbol{{ab}}+\boldsymbol{{bc}}+\boldsymbol{{ca}}\right)=\mathrm{1}−\mathrm{2} \\ $$$$\boldsymbol{{ab}}+\boldsymbol{{bc}}+\boldsymbol{{ca}}=−\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\boldsymbol{{a}}^{\mathrm{3}} +\boldsymbol{{b}}^{\mathrm{3}}…
Question Number 10955 by Joel576 last updated on 04/Mar/17 $$\mathrm{If}\:\:\frac{\mathrm{cos}\:\theta}{\mathrm{1}\:−\:\mathrm{sin}\:\theta}\:=\:{a}\:\:\:\:\:\:\:\:\:\:\:{a}\:\neq\:\frac{\pi}{\mathrm{2}}\:+\:\mathrm{2}{k}\pi \\ $$$$\mathrm{So},\:\:\mathrm{tan}\:\frac{\theta}{\mathrm{2}}\:=\:… \\ $$$$\left(\mathrm{A}\right)\:\:\frac{{a}}{{a}\:+\:\mathrm{1}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:\:\frac{{a}\:+\:\mathrm{1}}{{a}\:−\:\mathrm{1}} \\ $$$$\left(\mathrm{B}\right)\:\:\frac{\mathrm{1}}{{a}\:+\:\mathrm{1}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{E}\right)\:\:\frac{{a}}{{a}\:−\:\mathrm{1}} \\ $$$$\left(\mathrm{C}\right)\:\:\frac{{a}\:−\:\mathrm{1}}{{a}\:+\:\mathrm{1}} \\ $$ Answered by ajfour last updated…
Question Number 142021 by mathmax by abdo last updated on 25/May/21 $$\mathrm{simplfy}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{tan}\left(\alpha\:\mathrm{arcsinx}\right) \\ $$$$\mathrm{and}\:\mathrm{g}\left(\mathrm{x}\right)=\mathrm{tan}\left(\alpha\:\mathrm{arcosx}\right)\:\:\alpha\:\mathrm{is}\:\mathrm{real} \\ $$$$\mathrm{x}\in\left[−\mathrm{1},\mathrm{1}\right] \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 142023 by SOMEDAVONG last updated on 25/May/21 $$\mathrm{S}_{\mathrm{n}} =\underset{\mathrm{k}=\mathrm{0}} {\overset{\mathrm{n}} {\sum}}\frac{\mathrm{1}}{\left(\mathrm{n}−\mathrm{k}\right)!\left(\mathrm{n}+\mathrm{k}\right)!}\:=?? \\ $$ Answered by aleks041103 last updated on 25/May/21 $$\frac{\mathrm{1}}{\left({n}−{k}\right)!\left({n}+{k}\right)!}= \\ $$$$=\frac{\mathrm{1}}{\left(\mathrm{2}{n}\right)!}\:\frac{\left(\mathrm{2}{n}\right)!}{\left({n}−{k}\right)!\left(\left(\mathrm{2}{n}\right)−\left({n}−{k}\right)\right)!}=…