Question Number 141908 by dhgt last updated on 24/May/21 $${Q}\mathrm{137984} \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 10837 by okhema last updated on 27/Feb/17 $${given}\:{that}\:{sinA}=\frac{\mathrm{12}}{\mathrm{13}}{and}\:{sinB}=\frac{\mathrm{4}}{\mathrm{5}}, \\ $$$${where}\:{A}\:{and}\:{B}\:{are}\:{acute}\:{angles}, \\ $$$${find}\:{cos}\left({A}−{B}\right)\:{and}\:{sin}\left({A}+{B}\right) \\ $$$$ \\ $$ Answered by ridwan balatif last updated on…
Question Number 141910 by dhgt last updated on 24/May/21 $${Q}\mathrm{137026} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10836 by okhema last updated on 27/Feb/17 $${solve}\:{cos}\mathrm{2}\theta−\mathrm{3}{cos}\theta=\mathrm{1} \\ $$$${for}\:{o}\leqslant\theta\leqslant\mathrm{2}\pi \\ $$ Answered by ridwan balatif last updated on 27/Feb/17 $$\mathrm{cos2}\theta−\mathrm{3cos}\theta=\mathrm{1} \\ $$$$\left(\mathrm{2cos}^{\mathrm{2}}…
Question Number 141905 by dhgt last updated on 24/May/21 $${Q}\mathrm{137503} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 76368 by Rio Michael last updated on 26/Dec/19 $${prove}\:{that} \\ $$$$\mathrm{1}.\:\:\underset{{r}=\mathrm{1}} {\overset{{n}} {\sum}}\:{r}\:=\:\frac{\mathrm{1}}{\mathrm{2}}{n}\left({n}+\mathrm{1}\right) \\ $$$$\mathrm{2}.\:\underset{{r}=\mathrm{1}} {\overset{{n}} {\sum}}\:{r}^{\mathrm{2}} \:=\:\frac{\mathrm{1}}{\mathrm{6}}{n}\left({n}+\mathrm{1}\right)\left(\mathrm{2}{n}\:+\:\mathrm{1}\right) \\ $$$$\mathrm{3}.\:\:\underset{{r}=\mathrm{1}} {\overset{{n}} {\sum}}{r}^{\mathrm{3}} =\:\frac{\mathrm{1}}{\mathrm{4}}{n}^{\mathrm{2}}…
Question Number 141901 by gsk2684 last updated on 24/May/21 Commented by gsk2684 last updated on 24/May/21 $${does}\:{this}\:{series}\:{converges}\:{or}\:{diverges} \\ $$$${by}\:{using}\:{comparison}\:{test}\:{or}\:{limit} \\ $$$${comparison}\:{test}?\:{explanation}\:{please} \\ $$ Terms of…
Question Number 141900 by iloveisrael last updated on 24/May/21 $$\:\mathcal{L}\:=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{e}^{{x}} \:\mathrm{cos}\:{x}−{x}−\mathrm{1}}{{x}^{\mathrm{3}} }\:=? \\ $$ Answered by Dwaipayan Shikari last updated on 24/May/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{e}^{{x}}…