Question Number 10755 by Joel576 last updated on 24/Feb/17 $${x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \:+\:{xy}\:+\:\mathrm{2}\left({x}\:−\:{y}\right)\:=\:\mathrm{9} \\ $$$$\mathrm{How}\:\mathrm{many}\:\mathrm{solution}\:\mathrm{that}\:\mathrm{fulfilled}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{above}\:? \\ $$$${x},\:{y}\:\in\:\mathbb{N} \\ $$ Answered by mrW1 last updated on 24/Feb/17…
Question Number 76288 by benjo last updated on 26/Dec/19 $$\mathrm{what}\:\mathrm{is}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{if}\:\mathrm{f}\left(\mathrm{3}\right)=\mathrm{10},\:\mathrm{f}\left(\mathrm{2}\right)=\mathrm{14} \\ $$$$\mathrm{f}\left(\mathrm{1}\right)=\mathrm{20}\:? \\ $$ Commented by MJS last updated on 26/Dec/19 $$\mathrm{if}\:\mathrm{we}\:\mathrm{don}'\mathrm{t}\:\mathrm{know}\:\mathrm{the}\:\mathrm{type}\:\mathrm{of}\:{f}\left({x}\right)\:\mathrm{there}'\mathrm{s} \\ $$$$\mathrm{zillions}\:\mathrm{of}\:\mathrm{possibilities}… \\…
Question Number 141826 by Rankut last updated on 23/May/21 $${If}\:\:{y}={sin}^{\mathrm{2}} \theta,\:{x}={cot}\theta,\:{find}\:\:\frac{{dy}}{{dx}}. \\ $$$${Any}\:{suggestion}\:{please}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10750 by Joel576 last updated on 24/Feb/17 $$\mathrm{Exact}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{sin}\:\mathrm{9}°\:=\:… \\ $$ Answered by ridwan balatif last updated on 24/Feb/17 $$\mathrm{first}\:\mathrm{we}\:\mathrm{must}\:\mathrm{know}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{sin}\:\mathrm{18}^{\mathrm{o}} \\ $$$$\mathrm{let}\:\mathrm{x}=\mathrm{18}^{\mathrm{o}}…
Question Number 141822 by mathsuji last updated on 23/May/21 Commented by MJS_new last updated on 23/May/21 $$\mathrm{where}\:\mathrm{you}\:\mathrm{found}\:\mathrm{this}? \\ $$$$\mathrm{did}\:\mathrm{your}\:\mathrm{teacher}\:\mathrm{gave}\:\mathrm{it}\:\mathrm{to}\:\mathrm{you}?\:\mathrm{which}\:\mathrm{chapter} \\ $$$$\mathrm{of}\:\mathrm{solving}\:\mathrm{equations}\:\mathrm{are}\:\mathrm{you}\:\mathrm{studying}? \\ $$$$\mathrm{have}\:\mathrm{you}\:\mathrm{got}\:\mathrm{any}\:\mathrm{idea}? \\ $$$$\bullet\:\mathrm{yes}:\:\mathrm{then}\:\mathrm{please}\:\mathrm{tell}\:\mathrm{us}…
Question Number 10746 by okhema last updated on 24/Feb/17 $$\left.{i}\right){express}\:{the}\:{function}\:{f}\left(\theta\right)={sin}\theta\:+\:{cos}\theta\:{in}\:{the}\:{form}\:{rsin}\left(\theta+\alpha\right),\:{r}>\mathrm{0}\:{and}\:\mathrm{0}\leqslant\theta\leqslant\leqslant\frac{\pi}{\mathrm{2}} \\ $$$$\left.{ii}\right){hence}\:{find}\:{the}\:{maximum}\:{value}\:{of}\:{f}\:{and} \\ $$$${the}\:{smallest}\:{non}−{negative}\:{value}\:{of}\:\theta\:{at}\:{which}\:{it}\:{occurs}. \\ $$ Answered by mrW1 last updated on 24/Feb/17 $$\left.{i}\right) \\…
Question Number 10744 by okhema last updated on 24/Feb/17 $${hence}\:{or}\:{otherwise},{solve}\:{the}\:{equation}\:\frac{\mathrm{cosec}\:\theta}{\mathrm{cosec}\:\theta−\mathrm{sin}\:\theta}=\frac{\mathrm{4}}{\mathrm{3}}\:{for}\:\mathrm{0}\leqslant\theta\leqslant\mathrm{2}\Pi \\ $$ Answered by malwaan last updated on 24/Feb/17 $${cox}\:\theta=\pm\frac{\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$$\Rightarrow\theta=\mathrm{30}°\:\:\boldsymbol{{or}}\:\boldsymbol{\theta}=\mathrm{180}−\mathrm{30}=\mathrm{150}° \\ $$$${or}\:\theta=\mathrm{180}+\mathrm{30}=\mathrm{210}°\:{or}\:\theta=−\mathrm{30}° \\…
Question Number 10743 by okhema last updated on 24/Feb/17 $${show}\:{that}\:\mathrm{sec}\:^{\mathrm{2}} \theta=\frac{\mathrm{cosec}\:\theta}{\mathrm{cosec}\:\theta−\mathrm{sin}\:} \\ $$ Commented by ridwan balatif last updated on 24/Feb/17 $$\frac{\mathrm{cosec}\theta}{\mathrm{cosec}\theta−\mathrm{sin}\theta}=\frac{\frac{\mathrm{1}}{\mathrm{sin}\theta}}{\frac{\mathrm{1}}{\mathrm{sin}\theta}−\mathrm{sin}\theta}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\frac{\mathrm{1}}{\mathrm{sin}\theta}}{\frac{\mathrm{1}−\mathrm{sin}^{\mathrm{2}} \theta}{\mathrm{sin}\theta}}…
Question Number 141812 by mathsuji last updated on 23/May/21 Commented by mr W last updated on 23/May/21 $${check}\:{your}\:{question}\:{and}\:{diagram}! \\ $$$$\angle{BEC}=\alpha\:? \\ $$$${but}\:{according}\:{to}\:{diagram} \\ $$$$\angle{BEC}=\mathrm{180}° \\…
Question Number 10742 by okhema last updated on 24/Feb/17 $${let}\:{the}\:{roots}\:{of}\:{the}\:{equation}\mathrm{2}{x}^{\mathrm{3}} −\mathrm{5}{x}^{\mathrm{2}} +\mathrm{4}{x}+\mathrm{6}=\mathrm{0} \\ $$$${be}\:\alpha,\beta\:{and}\:\gamma. \\ $$$$\left.{i}\right){state}\:{the}\:{values}\:{of}\:\alpha+\beta+\gamma,\:\alpha\beta+\alpha\gamma+\beta\gamma\:{and}\:\alpha\beta\gamma. \\ $$$$\left.{ii}\right){hence}\:{or}\:{otherwise}\:{determine}\:{an}\:{equation}\:{with}\:{integer}\:{coefficients}\:{which}\:{as}\:{roots}\:\frac{\mathrm{1}}{\alpha^{\mathrm{2}\:} },\:\frac{\mathrm{1}}{\beta^{\mathrm{2}} }\:,\:{and}\:\frac{\mathrm{1}}{\gamma^{\mathrm{2}} } \\ $$$$ \\ $$…