Question Number 10728 by Saham last updated on 23/Feb/17 $$\mathrm{A}\:\mathrm{pipe}\:\mathrm{closed}\:\mathrm{at}\:\mathrm{one}\:\mathrm{end}\:\mathrm{emits}\:\mathrm{sound}\:\mathrm{wave}\:\mathrm{of}\:\mathrm{frequency}\:\mathrm{440}\:\mathrm{Hz}.\: \\ $$$$\left(\mathrm{i}\right)\:\mathrm{Determine}\:\mathrm{the}\:\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{air}\:\mathrm{column} \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{Frequencies}\:\mathrm{of}\:\mathrm{the}\:\mathrm{second}\:\mathrm{harmonic}\:\mathrm{and}\:\mathrm{the}\:\mathrm{third}\:\mathrm{harmonic} \\ $$$$\mathrm{Velocity}\:\mathrm{of}\:\mathrm{sound}\:\mathrm{is}\:\mathrm{330m}/\mathrm{s} \\ $$$$\mathrm{Refractive}\:\mathrm{index}\:\mathrm{of}\:\mathrm{glass}\:\mathrm{is}\:\mathrm{1}.\mathrm{50},\:\mathrm{that}\:\mathrm{of}\:\:\mathrm{air}\:\mathrm{is}\:\mathrm{1}.\mathrm{00},\: \\ $$$$\mathrm{and}\:\mathrm{that}\:\mathrm{of}\:\mathrm{water}\:\mathrm{is}\:\mathrm{1}.\mathrm{33} \\ $$ Answered by sandy_suhendra…
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Question Number 10721 by niraj last updated on 23/Feb/17 $${Q}.\mathrm{1}\:\:{x}^{\mathrm{2}} −{y}^{\mathrm{2}} −{i}\left(\mathrm{2}{x}+{y}\right)=\mathrm{2}{i} \\ $$$${Q}.\mathrm{2}\:\:\:\left(\mathrm{2}+\mathrm{3}{i}\right){x}^{\mathrm{2}} −\left(\mathrm{3}−{x}\right){y}=\mathrm{2}{x}−\mathrm{3}{y} \\ $$ Answered by sandy_suhendra last updated on 23/Feb/17 $$\mathrm{Q}.\mathrm{1}…
Question Number 141794 by mathdanisur last updated on 23/May/21 Commented by JDamian last updated on 23/May/21 $${repeated}\:{question}\:\mathrm{141730} \\ $$ Commented by mathdanisur last updated on…
Question Number 141791 by Chhing last updated on 23/May/21 $$\mathrm{Calculate} \\ $$$$\:\underset{\mathrm{n}=\mathrm{1}} {\overset{+\infty} {\sum}}\:\frac{\mathrm{n}^{\mathrm{2}} }{\mathrm{3}^{\mathrm{n}} } \\ $$ Answered by mr W last updated on…
Question Number 76252 by necxxx last updated on 25/Dec/19 $${A}\:{triangle}\:{has}\:{an}\:{area}\:{of}\:\mathrm{20}\:{square} \\ $$$${units}\:{and}\:{two}\:{vertices}\:{are}\:\left(\mathrm{3},\mathrm{4}\right)\:{and}\:\left(\mathrm{2},\mathrm{7}\right). \\ $$$${What}\:{is}\:{the}\:{position}\:{of}\:{the}\:{third}\:{vertex}? \\ $$ Commented by MJS last updated on 25/Dec/19 $$\mathrm{in}\:\mathrm{words}:\:\mathrm{we}\:\mathrm{know}\:\mathrm{the}\:\mathrm{area}=\frac{\mathrm{side}×\mathrm{height}}{\mathrm{2}} \\…
Question Number 141785 by 7770 last updated on 23/May/21 $$\boldsymbol{\mathrm{If}}\:\:\boldsymbol{\mathrm{x}}=\boldsymbol{\mathrm{asin}}\mathrm{2}\boldsymbol{\mathrm{t}}+\boldsymbol{\mathrm{bcos}}\mathrm{2}\boldsymbol{\mathrm{t}},\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{that}}\: \\ $$$$\frac{\boldsymbol{\mathrm{dx}}}{\boldsymbol{\mathrm{dt}}}=\mathrm{2}\sqrt{\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\boldsymbol{\mathrm{b}}^{\mathrm{2}} −\boldsymbol{\mathrm{x}}^{\mathrm{2}} } \\ $$$$\boldsymbol{\mathrm{Solution}}…. \\ $$ Answered by iloveisrael last updated on…
Question Number 76250 by Mikael_786 last updated on 25/Dec/19 Commented by Mikael_786 last updated on 25/Dec/19 $${how}\:{to}\:{find}\:{tranform}\:{laplace}\:{invers}? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 10714 by Saham last updated on 23/Feb/17 $$\mathrm{Given}\:\mathrm{the}\:\mathrm{following}\:\mathrm{information}\:\mathrm{regarding}\:\mathrm{the}\:\mathrm{follwing}\: \\ $$$$\mathrm{distribution}\::\:\: \\ $$$$\mathrm{n}\:=\:\mathrm{5},\:\:\:\:\overset{−} {\mathrm{x}}\:=\:\mathrm{10},\:\:\:\overset{−} {\mathrm{y}}\:=\:\mathrm{20},\:\:\:\Sigma\left(\mathrm{x}\:−\:\mathrm{4}\right)^{\mathrm{2}} \:=\:\mathrm{100},\:\:\Sigma\left(\mathrm{y}\:−\:\mathrm{10}\right)^{\mathrm{2}} \:=\:\mathrm{160}, \\ $$$$\Sigma\left(\mathrm{x}\:−\:\mathrm{4}\right)\left(\mathrm{y}\:−\:\mathrm{10}\right)\:=\:\mathrm{80} \\ $$$$\left(\mathrm{i}\right) \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{two}\:\mathrm{regression}\:\mathrm{coefficient}\:\mathrm{and} \\…
Question Number 76248 by john santuy last updated on 25/Dec/19 $$\overset{{lim}} {{x}}\rightarrow\overset{\:\:\:\:\left(\frac{{sin}\mathrm{3}{x}}{\mathrm{2}{x}}\right)^{\frac{\mathrm{2}}{\mathrm{5}{x}+\mathrm{1}}} } {\mathrm{0}}=\:?\:\: \\ $$ Commented by Mikael_786 last updated on 25/Dec/19 $$\underset{{x}\rightarrow\mathrm{0}} {{lim}}\frac{{sin}\mathrm{3}{x}}{\mathrm{2}{x}}=\underset{{x}\rightarrow\mathrm{0}}…