Question Number 141753 by mohammad17 last updated on 23/May/21 $$\int\frac{{dx}}{{sinx}+{cosx}} \\ $$ Commented by mohammad17 last updated on 23/May/21 $${help}\:{me}\:{sir} \\ $$ Answered by rs4089…
Question Number 141752 by 0731619 last updated on 23/May/21 Answered by qaz last updated on 23/May/21 $$\Omega=\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{tan}^{−\mathrm{1}} {x}}{\left({x}+\mathrm{1}\right)\left({x}^{\mathrm{2}} +\mathrm{1}\right)}{dx} \\ $$$$=\int_{\mathrm{0}} ^{\pi/\mathrm{2}} \frac{{u}}{\mathrm{tan}\:{u}+\mathrm{1}}{du}…
Question Number 141755 by rs4089 last updated on 23/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 141749 by Huy last updated on 23/May/21 $$\begin{cases}{\mathrm{x}^{\mathrm{2}} −\mathrm{y}+\sqrt{\mathrm{y}^{\mathrm{2}} +\mathrm{5}}=\mathrm{xy}−\sqrt{\mathrm{x}−\mathrm{1}}}\\{\mathrm{y}^{\mathrm{2}} +\sqrt{\mathrm{xy}+\mathrm{2}}=\mathrm{2}\left(\mathrm{x}+\mathrm{y}\right)}\end{cases} \\ $$$$\mathrm{Find}\:\mathrm{x},\mathrm{y} \\ $$ Answered by MJS_new last updated on 23/May/21 $$\mathrm{assuming}\:\mathrm{a}\:“\mathrm{nice}''\:\mathrm{solution}\:\mathrm{I}\:\mathrm{tried}…
Question Number 76214 by Emmanuel_N last updated on 25/Dec/19 $$\mathrm{x}^{\mathrm{2}} +\mathrm{2x}−\mathrm{9}+\frac{\mathrm{9}}{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} }=\mathrm{0} \\ $$$$\mathrm{please} \\ $$ Answered by benjo last updated on 25/Dec/19 $$\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} \:−\mathrm{10}+\mathrm{9}/\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}}…
Question Number 141750 by Algoritm last updated on 23/May/21 Answered by cherokeesay last updated on 23/May/21 $$\frac{\pi\left(\mathrm{2}{r}\right)^{\mathrm{2}} }{\mathrm{4}}\:−\:\pi{r}^{\mathrm{2}} \:\Leftrightarrow\:\frac{\pi\mathrm{4}{r}^{\mathrm{2}} }{\mathrm{4}}\:−\:\pi{r}^{\mathrm{2}} \:=\:\mathrm{0} \\ $$$$\frac{{B}_{{Area}} }{{R}_{{Area}} }\:=\:\mathrm{1}…
Question Number 76213 by Emmanuel_N last updated on 25/Dec/19 $$\left(\frac{\mathrm{1}}{\mathrm{64}}×\mathrm{5}^{−\mathrm{3}} \right)^{−\frac{\mathrm{1}}{\mathrm{3}}} \\ $$ Answered by MJS last updated on 25/Dec/19 $$=\left(\mathrm{4}^{−\mathrm{3}} ×\mathrm{5}^{−\mathrm{3}} \right)^{−\frac{\mathrm{1}}{\mathrm{3}}} =\left(\mathrm{20}^{−\mathrm{3}} \right)^{−\frac{\mathrm{1}}{\mathrm{3}}}…
Question Number 10675 by niraj last updated on 22/Feb/17 $${given}\:{that}\:{x},{y}\in{R}\:{solve}. \\ $$$$\left(\mathrm{1}\right)\:\left({x}+\mathrm{2}{y}\right)+{i}\left(\mathrm{2}{x}−\mathrm{3}{y}\right)=\mathrm{5}−\mathrm{4}{i} \\ $$$$\left(\mathrm{2}\right)\:\left({x}+{iy}\right)×\left(\mathrm{7}−\mathrm{5}{i}\right)=\mathrm{9}+\mathrm{4}{i} \\ $$ Commented by niraj last updated on 22/Feb/17 $${sir}\:{answer}\:{please} \\…
Question Number 141747 by mathsuji last updated on 23/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10671 by Saham last updated on 22/Feb/17 $$\underset{\mathrm{n}\:=\:\mathrm{1}} {\overset{\infty} {\sum}}\mathrm{5}\left(\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{n}\:−\:\mathrm{1}} \\ $$ Answered by FilupS last updated on 22/Feb/17 $${S}=\mathrm{5}\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\mathrm{4}^{{n}−\mathrm{1}} }…