Question Number 194191 by JohnIsaac last updated on 29/Jun/23 Answered by Tinku Tara last updated on 30/Jun/23 $$\mathrm{4}{x}−\mathrm{3}{y}=\mathrm{9} \\ $$$$\mathrm{divide}\:\mathrm{both}\:\mathrm{sides}\:\mathrm{by}\:\mathrm{9}. \\ $$$$\frac{{x}}{\left(\mathrm{9}/\mathrm{4}\right)}+\frac{{y}}{\left(−\mathrm{3}\right)}=\mathrm{1} \\ $$$$\mathrm{x}−\mathrm{intercept}=\mathrm{9}/\mathrm{4} \\…
Question Number 194190 by tri26112004 last updated on 29/Jun/23 $${Explanation}\:{Why}: \\ $$$${While}\:{f}\left({ax}+{b}\right)+{f}\left({cx}+{d}\right)={ex}+{g} \\ $$$${then}\:{f}\left({x}\right)={Ax}^{\mathrm{2}} +{Bx}+{C}\:¿ \\ $$ Commented by Tinku Tara last updated on 30/Jun/23…
Question Number 194185 by mnjuly1970 last updated on 29/Jun/23 $$ \\ $$$$\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\mathrm{lim}_{\:{x}\rightarrow\:\mathrm{0}^{\:−} } \:\left\{\:\frac{\:{x}^{\:\mathrm{2}} \:+\mathrm{2}{cos}\left({x}\right)\:+\:\lfloor−\frac{{tan}\left({x}\right)}{{x}}\:\rfloor}{{ax}^{\:\mathrm{4}} }\:\right\}\:=\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{a}\:=\:? \\ $$$$\:\:\:\:\:\:\:\:{a}:\:\:\:\frac{\mathrm{1}}{\mathrm{12}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{b}:\:\:−\frac{\mathrm{1}}{\mathrm{2}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{c}:\:\:\:\mathrm{12}\:\:\:\:\:\:\:\:\:\:\:\:\:\:{d}:\:\:−\mathrm{12}\:\:\: \\…
Question Number 194183 by tri26112004 last updated on 29/Jun/23 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{{n}\left({n}+\mathrm{15}\right)\left({n}+\mathrm{30}\right)} \\ $$ Answered by ARUNG_Brandon_MBU last updated on 29/Jun/23 $$\frac{\mathrm{1}}{{n}\left({n}+\mathrm{15}\right)\left({n}+\mathrm{30}\right)}=\frac{\mathrm{1}}{\mathrm{450}{n}}−\frac{\mathrm{1}}{\mathrm{225}\left({n}+\mathrm{15}\right)}+\frac{\mathrm{1}}{\mathrm{450}\left({n}+\mathrm{30}\right)} \\ $$$${S}=\frac{\mathrm{1}}{\mathrm{450}}\underset{{n}=\mathrm{0}} {\overset{\infty}…
Question Number 194176 by Skabetix last updated on 29/Jun/23 $${Hello}\:{everyone} \\ $$$${I}\:{try}\:{to}\:{solve}\:\mathrm{4}^{{x}+\mathrm{1}} +\mathrm{2}^{\mathrm{2}−{x}} =\mathrm{65} \\ $$$${Thx}\:{in}\:{advance} \\ $$ Answered by Skabetix last updated on 29/Jun/23…
Question Number 194105 by York12 last updated on 27/Jun/23 $$ \\ $$$${x}\:,\:{y}\:,\:{z}\:{are}\:{positive}\:{real}\:{numbers}\:{if}\:{x}^{\mathrm{4}} +{y}^{\mathrm{4}} +{z}^{\mathrm{4}} =\mathrm{1} \\ $$$${Then}\:{find}\:{the}\:{minimum}\:{value}\:{of}\: \\ $$$$\frac{{x}^{\mathrm{3}} }{\mathrm{1}−{x}^{\mathrm{8}} }+\frac{{y}^{\mathrm{3}} }{\mathrm{1}−{y}^{\mathrm{8}} }+\frac{{z}^{\mathrm{3}} }{\mathrm{1}−{z}^{\mathrm{8}} }…
Question Number 194073 by Rupesh123 last updated on 27/Jun/23 Answered by BaliramKumar last updated on 27/Jun/23 $$\mathrm{10}\pi \\ $$ Answered by mr W last updated…
Question Number 194065 by Abdullahrussell last updated on 27/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194064 by Abdullahrussell last updated on 27/Jun/23 Answered by som(math1967) last updated on 27/Jun/23 $$\left.{i}\left.\right)×{asec}\theta\:−{ii}\right)×\frac{{cos}\theta}{{a}} \\ $$$$\:\frac{{ay}}{{b}}{tan}\theta\:+\frac{{by}}{{a}}{cot}\theta={asec}\theta−\frac{{cos}\theta}{{a}}+\frac{{b}^{\mathrm{2}} {cos}\theta}{{a}} \\ $$$${y}\left(\frac{{a}^{\mathrm{2}} {tan}^{\mathrm{2}} \theta+{b}^{\mathrm{2}} }{{abtan}\theta}\right)=\frac{{a}^{\mathrm{2}}…
Question Number 194067 by Rupesh123 last updated on 27/Jun/23 Answered by som(math1967) last updated on 27/Jun/23 $$\:{x}^{\mathrm{2}} +\mathrm{10}^{\mathrm{2}} =\mathrm{2}\left(\mathrm{10}−{x}\right)^{\mathrm{2}} \\ $$$$\Rightarrow{x}^{\mathrm{2}} −\mathrm{40}{x}+\mathrm{100}=\mathrm{0} \\ $$$$\:{x}=\mathrm{10}\left(\mathrm{2}−\sqrt{\mathrm{3}}\right) \\…