Question Number 10660 by okhema last updated on 22/Feb/17 $${ind}\:{the}\:{centre}\:{and}\:{radius}\:{of}\:{these}: \\ $$$$\left({a}\right)\:\mathrm{6}{x}^{\mathrm{2}} +\mathrm{6}{y}^{\mathrm{2}} −\mathrm{4}{x}−\mathrm{5}{y}−\mathrm{2}=\mathrm{0} \\ $$$$\left({b}\right)\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\mathrm{6}{x}+\mathrm{8}{y}−\mathrm{1}=\mathrm{0} \\ $$$$\left({c}\right)\:\mathrm{3}{x}^{\mathrm{2}} +\mathrm{3}{y}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{8}{y}−\mathrm{2}=\mathrm{0} \\ $$ Answered…
Question Number 76194 by abdomathmax last updated on 25/Dec/19 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\:\frac{{cos}\left({x}^{\mathrm{2}} \right)}{{x}^{\mathrm{4}} −{x}^{\mathrm{2}} \:+\mathrm{1}}{dx} \\ $$ Commented by abdomathmax last updated on 25/Dec/19 $${let}\:{A}\:=\int_{\mathrm{0}}…
Question Number 76192 by abdomathmax last updated on 25/Dec/19 $${calculate}\:{lim}_{{x}\rightarrow\mathrm{0}} \:\:\:\frac{{arctan}\left({sin}\left(\mathrm{2}{x}\right)\right)−{sin}\left({arctan}\left(\mathrm{2}{x}\right)\right)}{{x}^{\mathrm{2}} } \\ $$ Answered by benjo last updated on 25/Dec/19 Commented by benjo last…
Question Number 141730 by mathdanisur last updated on 22/May/21 $${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{xy}=\mathrm{9} \\ $$$${y}^{\mathrm{2}} +{z}^{\mathrm{2}} +{yz}=\mathrm{16} \\ $$$${x}^{\mathrm{2}} +{z}^{\mathrm{2}} +{xz}=\mathrm{25} \\ $$$${xy}+{yz}+{xz}=? \\ $$ Commented…
Question Number 76193 by abdomathmax last updated on 25/Dec/19 $${calculate}\:\int\:\:\left({x}^{\mathrm{2}} −\mathrm{1}\right){sh}\left(\mathrm{3}{x}\right){dx} \\ $$ Commented by benjo last updated on 25/Dec/19 $$\mathrm{sir}\:\:\mathrm{do}\:\mathrm{you}\:\mathrm{mean}\:\mathrm{sh}\left(\mathrm{3x}\right)\:=\mathrm{sinh}\:\left(\mathrm{3x}\right)? \\ $$ Commented by…
Question Number 10656 by okhema last updated on 22/Feb/17 $${find}\:{the}\:{equation}\:{of}\:{the}\:{circle}\:{with}\:{diameter}\:{AB}\:{where}\:{A}\:{is}\:{at}\:\left(\mathrm{2},\mathrm{4}\right)\:{and}\:{B}\:{is}\:{at}\:\left(−\mathrm{1},\mathrm{6}\right) \\ $$ Answered by FilupS last updated on 22/Feb/17 $$\mathrm{circle}\:\mathrm{centred}\:\mathrm{at}\:\left({a},\:{b}\right)\:\mathrm{with}\:\mathrm{radius}\:{r} \\ $$$${r}=\:\frac{\mathrm{1}}{\mathrm{2}}{AB} \\ $$$$\left({a},\:{b}\right)\:\mathrm{is}\:\mathrm{half}\:\mathrm{way}\:\mathrm{between}\:{A}\:\mathrm{and}\:{B} \\…
Question Number 76190 by abdomathmax last updated on 25/Dec/19 $${let}\:{f}\left({x}\right)=\frac{{arctan}\left(\mathrm{1}+{x}\right)}{\mathrm{2}+{x}} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{f}^{\left({n}\right)} \left({x}\right)\:{and}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right)\:{developp}\:{f}\:{at}\:{integr}\:{serie}. \\ $$ Commented by mathmax by abdo last updated…
Question Number 10655 by FilupS last updated on 22/Feb/17 $$\mathrm{Show}\:\mathrm{me}\:\mathrm{your}\:\mathrm{favourite}\:\mathrm{proofs} \\ $$$$\mathrm{relating}\:\mathrm{to}\:{e} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 76191 by abdomathmax last updated on 25/Dec/19 $${find}\:{lim}_{{x}\rightarrow\mathrm{0}} \:\:\:\:\frac{{e}^{{x}} −{e}^{\left[{x}\right]} }{{x}} \\ $$ Answered by Rio Michael last updated on 25/Dec/19 $${Am}\:{not}\:{sure}\:{if}\:{this}\:{limit} \\…
Question Number 10654 by FilupS last updated on 22/Feb/17 $$\mathrm{Show}\:\mathrm{me}\:\mathrm{your}\:\mathrm{favorite}\:\mathrm{proofs} \\ $$$$\mathrm{relating}\:\mathrm{to}\:\pi \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com