Question Number 10653 by Saham last updated on 21/Feb/17 $$\mathrm{A}\:\mathrm{ship}\:\mathrm{leaves}\:\mathrm{a}\:\mathrm{port}\:\mathrm{P}\:\mathrm{which}\:\mathrm{lies}\:\mathrm{in}\:\mathrm{latitude}\:\mathrm{20}°\mathrm{N}.\:\mathrm{It}\:\mathrm{sails}\:\mathrm{due}\:\mathrm{east} \\ $$$$\mathrm{through}\:\mathrm{30}°\:\mathrm{of}\:\:\mathrm{longitude}\:\mathrm{and}\:\mathrm{then}\:\mathrm{through}\:\mathrm{south}\:\mathrm{to}\:\mathrm{Q}\:\mathrm{which}\:\mathrm{lies} \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{equator}.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{it}\:\mathrm{has}\:\mathrm{travelled}, \\ $$$$\left(\mathrm{Take}\:\mathrm{the}\:\mathrm{cicumference}\:\mathrm{of}\:\mathrm{the}\:\mathrm{earth}\:\mathrm{to}\:\mathrm{be}\:\mathrm{40},\mathrm{000}\:\mathrm{km}\right). \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{return}\:\mathrm{jouney}\:\mathrm{it}\:\mathrm{sails}\:\mathrm{due}\:\mathrm{west}\:\mathrm{through}\:\mathrm{30}°\:\mathrm{of}\:\mathrm{longitude}\:\mathrm{and} \\ $$$$\mathrm{then}\:\mathrm{due}\:\mathrm{north}\:\mathrm{back}\:\mathrm{to}\:\mathrm{P}.\:\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{difference}\:\mathrm{in}\:\mathrm{length}\:\mathrm{between} \\ $$$$\mathrm{the}\:\mathrm{outward}\:\mathrm{and}\:\mathrm{return}\:\mathrm{jouney}\:\mathrm{is}\:\mathrm{approximately}\:\mathrm{201}\:\mathrm{kilometers}. \\ $$$$\mathrm{Using}\:\mathrm{this}\:\mathrm{value}\:\mathrm{of}\:\mathrm{201}\:\mathrm{km}\:\mathrm{and}\:\mathrm{taking}\:\mathrm{1}\:\mathrm{knot}\:\mathrm{to}\:\mathrm{be}\:\mathrm{1}.\mathrm{852}\:\mathrm{km}/\mathrm{hr}\:. \\…
Question Number 141716 by qaz last updated on 22/May/21 $$\left({x}^{\mathrm{2}} {lnx}\right){y}''−{xy}'+{y}=\mathrm{0} \\ $$ Answered by mnjuly1970 last updated on 23/May/21 $$\:\:{y}_{{p}_{\mathrm{1}} } ={ln}\left({x}\right)+\mathrm{1}\:\:\:\:\:\:\:\:{or}\:\:\:\:{y}_{{p}_{\mathrm{1}} } ={x}…
Question Number 141719 by qaz last updated on 22/May/21 $$\int_{\mathrm{0}} ^{\infty} \frac{{e}^{−{x}^{\mathrm{2}} } }{\left({x}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} }{dx}=? \\ $$ Answered by MJS_new last updated on 23/May/21…
Question Number 141713 by rs4089 last updated on 22/May/21 Answered by Dwaipayan Shikari last updated on 22/May/21 $$\mathrm{1}−{x}={u} \\ $$$$\int_{−\mathrm{1}} ^{\mathrm{1}} \int_{\mathrm{0}} ^{{u}} {x}^{\mathrm{1}/\mathrm{3}} {y}^{−\mathrm{1}/\mathrm{2}}…
Question Number 141715 by SOMEDAVONG last updated on 22/May/21 $$\mathrm{Find}\:\mathrm{x}\:\mathrm{if}\:\underset{\mathrm{n}=\mathrm{2}} {\overset{\mathrm{24}} {\sum}}\frac{\mathrm{250}}{\left(\mathrm{1}+\mathrm{x}\right)^{\mathrm{n}} }\:=\:\mathrm{5000}. \\ $$ Answered by mathmax by abdo last updated on 22/May/21 $$\sum_{\mathrm{n}=\mathrm{2}}…
Question Number 76176 by Master last updated on 24/Dec/19 Commented by mr W last updated on 24/Dec/19 $$\left(\mathrm{3}{x}+\mathrm{1}\right)\mathrm{8}^{{x}} =\mathrm{6} \\ $$$$\left(\mathrm{3}{x}+\mathrm{1}\right)\mathrm{2}^{\mathrm{3}{x}} =\mathrm{6} \\ $$$$\left(\mathrm{3}{x}+\mathrm{1}\right)\mathrm{2}^{\mathrm{3}{x}+\mathrm{1}} =\mathrm{12}…
Question Number 10640 by Saham last updated on 21/Feb/17 $$\mathrm{A}\:\mathrm{circular}\:\mathrm{disc}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{20kg}\:\mathrm{and}\:\mathrm{radius}\:\mathrm{15cm}\:\mathrm{is}\:\mathrm{mounted}\:\mathrm{in}\:\mathrm{an} \\ $$$$\mathrm{horizontal}\:\mathrm{cylinder}\:\mathrm{axel}\:\mathrm{of}\:\mathrm{radius}\:\mathrm{1}.\mathrm{5cm},\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{kinectic} \\ $$$$\mathrm{energy}\:\mathrm{of}\:\mathrm{the}\:\mathrm{disc}\:\mathrm{after}\:\mathrm{1}.\mathrm{2}\:\mathrm{secs}\:\mathrm{if}\:\mathrm{a}\:\mathrm{force}\:\mathrm{of}\:\mathrm{12N}\:\mathrm{is}\:\mathrm{applied}\:\mathrm{tangentially} \\ $$$$\mathrm{to}\:\mathrm{the}\:\mathrm{axel}. \\ $$ Answered by mrW1 last updated on 21/Feb/17…
Question Number 10639 by Saham last updated on 21/Feb/17 $$\mathrm{A}\:\mathrm{manometer}\:\mathrm{wire}\:\mathrm{of}\:\mathrm{lenght}\:\mathrm{60}\:\mathrm{cm}\:\mathrm{is}\:\mathrm{maintained}\:\mathrm{under} \\ $$$$\mathrm{a}\:\mathrm{tension}\:\mathrm{of}\:\mathrm{value}\:\mathrm{20V}\:\mathrm{and}\:\mathrm{an}\:\mathrm{a}.\mathrm{c}\:\mathrm{is}\:\mathrm{passed}\:\mathrm{through} \\ $$$$\mathrm{the}\:\mathrm{wire}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{density}\:\mathrm{of}\:\mathrm{the}\:\mathrm{wire}\:\mathrm{is}\:\mathrm{4000kgm}^{−\mathrm{3}} \:\mathrm{and}\:\mathrm{it}\: \\ $$$$\mathrm{diamerter}\:\mathrm{is}\:\mathrm{2mm}.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{frequency}\:\mathrm{of}\:\mathrm{the}\:\mathrm{a}.\mathrm{c} \\ $$ Commented by Saham last updated on…
Question Number 141708 by Snail last updated on 22/May/21 $$\mathrm{2}\left(\mathrm{8}{n}^{\mathrm{3}} +{m}^{\mathrm{3}} \right)+\mathrm{6}\left({m}^{\mathrm{2}} −\mathrm{6}{n}^{\mathrm{2}} \right)+\mathrm{3}\left(\mathrm{2}{m}+\mathrm{9}{n}\right)=\mathrm{437}\: \\ $$$${Find}\:{all}\:{positive}\:\:{values}\:{of}\:{mn}….? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10638 by FilupS last updated on 21/Feb/17 $${S}=\sqrt{\mathrm{1}+\sqrt{{a}+\sqrt{{a}^{\mathrm{2}} +\sqrt{{a}^{\mathrm{3}} +\sqrt{…}}}}},\:\:\:\:{a}>\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com