Question Number 76143 by Master last updated on 24/Dec/19 Commented by mathmax by abdo last updated on 24/Dec/19 $${let}\:{I}\:=\int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{\mathrm{4}+{x}^{\mathrm{2}} }{dx}\:\:{changement}\:{x}=\mathrm{2}{sh}\left({t}\right)\:{give} \\ $$$${I}\:=\int_{\mathrm{0}} ^{{argsh}\left(\frac{\mathrm{1}}{\mathrm{2}}\right)}…
Question Number 141672 by iloveisrael last updated on 22/May/21 $$\:\:{Solve}\:{the}\:{equation}\: \\ $$$$\:\:{x}^{\mathrm{4}} −\mathrm{2}{x}^{\mathrm{3}} −\mathrm{5}{x}^{\mathrm{2}} +\mathrm{10}{x}−\mathrm{3}=\mathrm{0} \\ $$ Answered by MJS_new last updated on 22/May/21 $$\left({x}^{\mathrm{2}}…
Question Number 141669 by bramlexs22 last updated on 22/May/21 Answered by iloveisrael last updated on 22/May/21 $$\left({i}\right)\:{f}\left({a}\right)={g}\left({a}\right)\:,{a}>\mathrm{0} \\ $$$$\Rightarrow\:{a}+\mid\mathrm{2}{a}\mid\:=\:−{a}^{\mathrm{2}} −\frac{\mathrm{2}}{\mathrm{3}}{a}+\frac{\mathrm{14}}{\mathrm{3}} \\ $$$$\Rightarrow\mathrm{3}{a}\:=−{a}^{\mathrm{2}} −\frac{\mathrm{2}}{\mathrm{3}}{a}+\frac{\mathrm{14}}{\mathrm{3}} \\ $$$$\Rightarrow\mathrm{3}{a}^{\mathrm{2}}…
Question Number 141668 by mnjuly1970 last updated on 22/May/21 $$\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:…….{Advanced}\:…\bigstar\:…\bigstar\:…\:{Calculus}……. \\ $$$$\:\:\:\:\:\:\:\:\:{if}\:\:\:\:\Omega\:=\underset{{n}=\mathrm{2}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} \zeta\left({n}\right)}{\mathrm{2}^{{n}} }\:{then}\:{prove} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:{that}\:::\:\:\:\:\:\frac{\mathrm{1}}{\mathrm{2}}\:=\:{e}^{\Omega−\mathrm{1}} \:\: \\ $$$$\:\:\:\:{proof}\::: \\ $$$$\:\:\:\:{method}\:\left(\mathrm{1}\right):…
Question Number 10597 by Saham last updated on 19/Feb/17 $$\mathrm{prove}\:\mathrm{that} \\ $$$$\mid\mathrm{z}_{\mathrm{1}} −\:\mathrm{z}_{\mathrm{2}} \mid\:\leqslant\:\mid\mathrm{z}_{\mathrm{1}} \mid\:+\:\mid\mathrm{z}_{\mathrm{2}} \mid \\ $$ Answered by mrW1 last updated on 19/Feb/17…
Question Number 141665 by bekzodjumayev last updated on 22/May/21 Commented by bekzodjumayev last updated on 22/May/21 $${Please}\:{Help} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 76126 by Master last updated on 24/Dec/19 Commented by benjo last updated on 24/Dec/19 Commented by benjo last updated on 24/Dec/19 $$\mathrm{i}\:\mathrm{cannot}\:\mathrm{find}\:\mathrm{formula}\:\mathrm{the}\:\mathrm{simple}\:\mathrm{form}\:\mathrm{n}−\:\mathrm{th} \\…
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Question Number 141663 by ajfour last updated on 22/May/21 $$\:\underset{\:\:−−−−−−−−−−−−−−−−−−−} {\:} \\ $$$$\:\:{x}^{\mathrm{2}} \left({x}−\mathrm{12}\right)\left({x}−\mathrm{15}\right)={k}\left({x}−\mathrm{16}\right) \\ $$$$\:\:\:\:{find}\:{x}\:{in}\:{terms}\:{of}\:{k}\:\left(>\mathrm{0}\right). \\ $$$$\:\:\overset{−−−−−−−−−−−−−−−−−−−} {\:} \\ $$ Commented by Rasheed.Sindhi last…
Question Number 76122 by benjo last updated on 24/Dec/19 Answered by john santuy last updated on 24/Dec/19 $${i}\:{think}\:{this}\:{problem}\:{not}\:{difficult} \\ $$ Commented by $@ty@m123 last updated…