Question Number 76110 by mathocean1 last updated on 23/Dec/19 $${hello}\:\mathrm{solve}\:\mathrm{in}\:\mathbb{R} \\ $$$$\mathrm{tan}{x}>\sqrt{\mathrm{3}} \\ $$$${please}\:{explain}\:{me}\:{if}\:{possible}. \\ $$ Answered by MJS last updated on 24/Dec/19 $$\mathrm{tan}\:{x}\:=\sqrt{\mathrm{3}}\wedge\mathrm{0}\leqslant{x}<\mathrm{2}\pi \\…
Question Number 10575 by ridwan balatif last updated on 19/Feb/17 $$\mathrm{3}\left(\mathrm{2}^{\mathrm{2}} +\mathrm{1}\right)\left(\mathrm{2}^{\mathrm{4}} +\mathrm{1}\right)\left(\mathrm{2}^{\mathrm{8}} +\mathrm{1}\right)\left(\mathrm{2}^{\mathrm{16}} +\mathrm{1}\right)\left(\mathrm{2}^{\mathrm{32}} +\mathrm{1}\right)\left(\mathrm{2}^{\mathrm{64}} +\mathrm{1}\right)\left(\mathrm{2}^{\mathrm{128}} +\mathrm{1}\right)=…? \\ $$ Commented by FilupS last updated…
Question Number 76108 by Maclaurin Stickker last updated on 23/Dec/19 Commented by Maclaurin Stickker last updated on 23/Dec/19 $${in}\:{the}\:{figure},\:{the}\:{circumferences} \\ $$$${have}\:{radius}\:\mathrm{8}\:{cm}\:{and}\:\mathrm{6}\:{cm}\:{and}\:{the} \\ $$$${distance}\:{between}\:{their}\:{centers}\:{is}\:\mathrm{12}\:{cm}.\: \\ $$$${If}\:{QP}={PR},\:{find}\:{QP}.…
Question Number 10572 by j.masanja06@gmail.com last updated on 18/Feb/17 $$\mathrm{factorise} \\ $$$$\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{1} \\ $$ Answered by sandy_suhendra last updated on 18/Feb/17 $$=\left(\mathrm{x}+\mathrm{1}\right)\left(\mathrm{x}^{\mathrm{2}} −\mathrm{x}+\mathrm{1}\right) \\…
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Question Number 141640 by Willson last updated on 21/May/21 Answered by qaz last updated on 22/May/21 $$\underset{{k}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\mathrm{16}^{{k}} \left(\mathrm{8}{k}+{n}\right)} \\ $$$$=\underset{{k}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\mathrm{16}^{{k}} }\int_{\mathrm{0}}…
Question Number 10570 by ABD last updated on 18/Feb/17 $${n}\left({A}\right)=\mathrm{12} \\ $$$${n}\left({B}\right)=\mathrm{10} \\ $$$$\Rightarrow{min}\left({n}\left({A}−{B}−{B}^{'} \right)\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 141643 by Gbenga last updated on 21/May/21 Answered by qaz last updated on 22/May/21 $${S}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(\mathrm{5}{n}+\mathrm{1}\right)^{\mathrm{2}} }{\mathrm{16}^{{n}} } \\ $$$$=\left(\mathrm{5}{xD}+\mathrm{1}\right)^{\mathrm{2}} \mid_{{x}=\mathrm{1}/\mathrm{16}} \underset{{n}=\mathrm{0}}…
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Question Number 10566 by krist last updated on 18/Feb/17 Answered by ridwan balatif last updated on 18/Feb/17 $$\int\frac{\mathrm{cos}{x}}{\mathrm{1}−\mathrm{cos}^{\mathrm{2}} {x}}{dx} \\ $$$$=\int\frac{\mathrm{cos}{x}}{\mathrm{sin}^{\mathrm{2}} {x}}{dx} \\ $$$$=\int\frac{\mathrm{cos}{x}}{\mathrm{sin}{x}}×\frac{\mathrm{1}}{\mathrm{sin}{x}}{dx} \\…