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Author: Tinku Tara

1-k-1-C-n-k-

Question Number 141614 by ArielVyny last updated on 21/May/21 $$\Sigma\frac{\mathrm{1}}{{k}+\mathrm{1}}{C}_{{n}} ^{{k}} \:.\: \\ $$ Commented by Dwaipayan Shikari last updated on 21/May/21 $$\frac{\mathrm{1}}{{k}+\mathrm{1}}\underset{{n}=\mathrm{0}} {\overset{{k}} {\sum}}{C}_{{n}}…

Find-the-maximum-area-of-an-isosceles-triangle-inscribed-in-an-ellipse-x-2-a-2-y-2-b-2-1with-its-vetrex-at-one-end-of-the-major-axis-

Question Number 76077 by vishalbhardwaj last updated on 23/Dec/19 $$\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{maximum}}\:\boldsymbol{\mathrm{area}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{an}}\:\boldsymbol{\mathrm{isosceles}}\:\boldsymbol{\mathrm{triangle}} \\ $$$$\boldsymbol{\mathrm{inscribed}}\:\boldsymbol{\mathrm{in}}\:\boldsymbol{\mathrm{an}}\:\boldsymbol{\mathrm{ellipse}}\:\frac{\boldsymbol{{x}}^{\mathrm{2}} }{\boldsymbol{{a}}^{\mathrm{2}} }\:+\:\frac{\boldsymbol{{y}}^{\mathrm{2}} }{\boldsymbol{{b}}^{\mathrm{2}} }\:=\:\mathrm{1}\boldsymbol{\mathrm{with}}\:\boldsymbol{\mathrm{its}}\:\boldsymbol{\mathrm{vetrex}}\: \\ $$$$\boldsymbol{\mathrm{at}}\:\boldsymbol{\mathrm{one}}\:\boldsymbol{\mathrm{end}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{major}}\:\boldsymbol{\mathrm{axis}}\:?\:? \\ $$ Commented by MJS last updated…

Question-10540

Question Number 10540 by FilupS last updated on 17/Feb/17 Commented by FilupS last updated on 17/Feb/17 $$\mathrm{All}\:\mathrm{side}\:\mathrm{lenghts}\:=\:{n} \\ $$$$\angle{CAE}=\theta \\ $$$$\mathrm{0}\leqslant\theta<\frac{\pi}{\mathrm{3}} \\ $$$$\: \\ $$$$\mathrm{1}.\:\:\mathrm{Determine}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{overlapping}\:\mathrm{sections}…

Give-the-velocity-field-v-6-2xy-t-2-i-xy-2-10t-j-25k-what-is-the-acceleration-of-the-particle-at-3-0-2-at-time-t-1-

Question Number 10528 by Saham last updated on 16/Feb/17 $$\mathrm{Give}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{field} \\ $$$$\mathrm{v}\:=\:\left(\mathrm{6}\:+\:\mathrm{2xy}\:+\:\mathrm{t}^{\mathrm{2}} \right)\mathrm{i}\:−\:\left(\mathrm{xy}^{\mathrm{2}} \:+\:\mathrm{10t}\right)\mathrm{j}\:+\:\mathrm{25k} \\ $$$$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{the}\:\mathrm{particle}\:\mathrm{at}\:\left(\mathrm{3},\:\mathrm{0},\:\mathrm{2}\right) \\ $$$$\mathrm{at}\:\mathrm{time}\:\mathrm{t}\:=\:\mathrm{1}. \\ $$ Answered by robocop last updated…