Question Number 10455 by amir last updated on 10/Feb/17 Commented by mrW1 last updated on 10/Feb/17 $${circle}\:{C}\mathrm{1}\:{with}\:{radius}\:{r}_{\mathrm{1}} \:{and}\:{centre} \\ $$$${point}\:{M}_{\mathrm{1}} \left({r}_{\mathrm{1}} ,{h}_{\mathrm{1}} \right){with}\:{h}_{\mathrm{1}} ={r}_{\mathrm{1}} \:{has}\:{two}…
Question Number 75991 by Ajao yinka last updated on 21/Dec/19 Commented by mivheal last updated on 22/Dec/19 $${no}\:{answer} \\ $$ Answered by mind is power…
Question Number 75988 by Ajao yinka last updated on 21/Dec/19 Commented by mivheal last updated on 22/Dec/19 jj Commented by mind is power last updated…
Question Number 141526 by sarkor last updated on 20/May/21 Answered by rs4089 last updated on 20/May/21 $$\int\left({x}+\mathrm{1}\right)\sqrt{{x}^{\mathrm{2}} +\mathrm{2}{x}\:}\:{dx} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\int\left(\mathrm{2}{x}+\mathrm{2}\right)\sqrt{{x}^{\mathrm{2}} +\mathrm{2}{x}}\:{dx} \\ $$$${let}\:{x}^{\mathrm{2}} +\mathrm{2}{x}={t}\:\Rightarrow\left(\mathrm{2}{x}+\mathrm{2}\right){dx}={dt} \\…
Question Number 75989 by Ajao yinka last updated on 21/Dec/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 141521 by 7770 last updated on 19/May/21 $$\begin{cases}{\sqrt[{\mathrm{3}}]{\boldsymbol{{x}}+\boldsymbol{{y}}}+\sqrt{\boldsymbol{{x}}−\mathrm{3}\boldsymbol{{y}}}=\mathrm{4}}\\{\mathrm{2}\boldsymbol{{x}}+\mathrm{3}\boldsymbol{{y}}=\mathrm{17}}\end{cases} \\ $$$$\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{y}}. \\ $$ Answered by MJS_new last updated on 20/May/21 $$\mathrm{let}'\mathrm{s}\:\mathrm{try}\:{x}+{y}={a}^{\mathrm{3}} \:\wedge\:{x}−\mathrm{3}{y}={b}^{\mathrm{2}} \\ $$$$\Leftrightarrow…
Question Number 75986 by Ajao yinka last updated on 21/Dec/19 Commented by abdomathmax last updated on 24/Dec/19 $${let}\:{f}\left({t}\right)\:=\int_{\mathrm{0}} ^{\infty} \:\:\frac{{arctan}\left({xt}\right){cos}\left({nx}\right)}{{x}}{dx}\:\:{with}\:{t}\geqslant\mathrm{0} \\ $$$${f}^{'} \left({t}\right)=\int_{\mathrm{0}} ^{\infty} \:\:\frac{{x}}{\mathrm{1}+{x}^{\mathrm{2}}…
Question Number 10451 by ketto last updated on 09/Feb/17 Answered by amir last updated on 10/Feb/17 $$\Sigma{f}_{{x}} =\mathrm{10}{cos}\mathrm{45}−\mathrm{10}{cos}\mathrm{45}+\mathrm{0}=\mathrm{0} \\ $$$$\Sigma{f}_{{y}} =\mathrm{2}×\mathrm{10}{sin}\mathrm{45}−\mathrm{9}=\mathrm{10}\sqrt{\mathrm{2}}−\mathrm{9}#\mathrm{5}.\mathrm{41} \\ $$$${R}=\sqrt{\left(\Sigma{f}_{{x}} \right)^{\mathrm{2}} +\left(\Sigma{f}_{{y}}…
Question Number 75987 by Ajao yinka last updated on 21/Dec/19 Answered by MJS last updated on 22/Dec/19 $${m}=\sqrt{{x}}\wedge{n}=\sqrt{{y}} \\ $$$${x}^{\mathrm{3}} +\left(\mathrm{375}{y}\right){x}+\left({y}^{\mathrm{3}} −\mathrm{1953125}\right)=\mathrm{0} \\ $$$$\mathrm{Cardano}\:\mathrm{with}\:{p}=\mathrm{375}{y}\wedge{q}={y}^{\mathrm{3}} −\mathrm{1953125}…
Question Number 75984 by Ajao yinka last updated on 21/Dec/19 Answered by mind is power last updated on 23/Dec/19 $$\mathrm{y}=\mathrm{x}^{\mathrm{2}} \\ $$$$\Rightarrow\Omega=\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{log}\left(\mathrm{y}\right)}{\mathrm{4}\left(\mathrm{1}+\mathrm{y}+\mathrm{y}^{\mathrm{2}} \right)}\mathrm{dy}…