Question Number 75985 by Ajao yinka last updated on 21/Dec/19 Answered by MJS last updated on 21/Dec/19 $$\mathrm{1}+\frac{\mathrm{1}}{{n}^{\mathrm{2}} }+\frac{\mathrm{1}}{\left({n}+\mathrm{1}\right)^{\mathrm{2}} }=\left(\frac{{n}^{\mathrm{2}} +{n}+\mathrm{1}}{{n}\left({n}+\mathrm{1}\right)}\right)^{\mathrm{2}} \\ $$$${S}_{{k}} =\underset{{n}=\mathrm{1}} {\overset{{k}}…
Question Number 75983 by mathocean1 last updated on 21/Dec/19 $$\mathrm{show}\:\mathrm{that} \\ $$$$\mathrm{cos}^{\mathrm{6}} \mathrm{x}+\mathrm{sin}^{\mathrm{6}} \mathrm{x}=\frac{\mathrm{1}}{\mathrm{8}}\left(\mathrm{5}+\mathrm{3cos4x}\right) \\ $$ Commented by MJS last updated on 21/Dec/19 $$\mathrm{answer}\:\mathrm{is}\:\mathrm{part}\:\mathrm{of}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{the}\:\mathrm{other} \\…
Question Number 141513 by mathdanisur last updated on 19/May/21 $$\mathrm{1}.\:\:\mathrm{27}^{\frac{\mathrm{1}}{{log}_{\mathrm{2}} \mathrm{3}}\:+\:{log}_{\mathrm{125}} \mathrm{0},\mathrm{2}} =? \\ $$$$\mathrm{2}.\:\:{if},\:\:\alpha\:=\:\frac{\pi}{\mathrm{12}} \\ $$$${find},\:\:{cos}^{\mathrm{2}} \alpha\:+\:\mathrm{2}{sin}\alpha{cos}\alpha\:−\:{sin}^{\mathrm{2}} \alpha=? \\ $$ Terms of Service Privacy…
Question Number 141512 by mnjuly1970 last updated on 19/May/21 $$ \\ $$$$\:\:\:\underset{{n}=\mathrm{1}\:} {\overset{\infty} {\sum}}\frac{{sin}\left(\frac{\left(\mathrm{2}{n}−\mathrm{1}\right)\pi}{\mathrm{6}}\right)}{\left(\mathrm{2}{n}−\mathrm{1}\right)^{\mathrm{2}} }\:=\:{a}.{G} \\ $$$$\:\:{a}\:=\:?\:\:\:\:\:\:\left({G}:=\:{catalan}\:{constant}\right) \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 75976 by mathocean1 last updated on 21/Dec/19 $$\left.\mathrm{h}\left.\mathrm{ello}\:\:\mathrm{solve}\:\mathrm{it}\:\mathrm{in}\:\right]−\pi;\pi\right]\:\mathrm{and}\:\mathrm{place}\:\mathrm{solutions} \\ $$$$\mathrm{in}\:\mathrm{trigonometric}\:\mathrm{circle}. \\ $$$$\mathrm{cos}^{\mathrm{6}} \mathrm{x}+\mathrm{sin}^{\mathrm{6}} \mathrm{x}=\frac{\mathrm{3}}{\mathrm{8}}\left(\sqrt{\mathrm{3}}\mathrm{sin4x}+\frac{\mathrm{8}}{\mathrm{3}}\right) \\ $$$$\mathrm{please}\:\mathrm{help}\:\mathrm{me}… \\ $$ Commented by MJS last updated…
Question Number 141509 by I want to learn more last updated on 19/May/21 $$\underset{\theta\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\frac{\mathrm{sin}^{\mathrm{3}} \mathrm{3}\theta\:\:\:−\:\:\:\mathrm{3}\theta^{\mathrm{3}} }{\theta^{\mathrm{3}} \:\:+\:\:\theta^{\mathrm{4}} } \\ $$ Answered by bramlexs22 last…
Question Number 10435 by Joel575 last updated on 09/Feb/17 Commented by Joel575 last updated on 09/Feb/17 $$\mathrm{The}\:\mathrm{side}\:\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{is}\:\mathrm{1}\:\mathrm{cm}. \\ $$$$\mathrm{5}\:\mathrm{circles}\:\mathrm{have}\:\mathrm{same}\:\mathrm{radius}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}'\mathrm{s}\:\mathrm{radius}? \\ $$ Answered by…
Question Number 141507 by I want to learn more last updated on 19/May/21 $$\int\:\frac{\mathrm{dx}}{\mathrm{sin}^{\mathrm{4}} \mathrm{x}\:\:\:+\:\:\:\mathrm{cos}^{\mathrm{4}} \mathrm{x}}\:\:\mathrm{dx} \\ $$ Answered by mathmax by abdo last updated…
Question Number 141501 by Rozix last updated on 19/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10429 by ridwan balatif last updated on 09/Feb/17 $$\mathrm{2}^{\mathrm{cos2x}} +\mathrm{2}^{\mathrm{cos}^{\mathrm{2}} \mathrm{x}} =\mathrm{3}×\mathrm{2}^{−\mathrm{cos2x}} \: \\ $$$$\mathrm{x}=…? \\ $$$$\mathrm{i}'\mathrm{m}\:\mathrm{so}\:\mathrm{sorry},\:\mathrm{it}'\mathrm{s}\:\mathrm{my}\:\mathrm{mistake},\:\mathrm{the}\:\mathrm{true}\:\mathrm{question}\:\mathrm{is} \\ $$$$\mathrm{2}^{\mathrm{cos2x}} +\mathrm{2}^{\mathrm{cos}^{\mathrm{2}} \mathrm{x}} =\mathrm{3}×\mathrm{2}^{−\mathrm{cos2}\pi} \:…