Question Number 194031 by Mingma last updated on 26/Jun/23 Commented by ellen12 last updated on 26/Jun/23 Impressive �� Answered by mr W last updated on 27/Jun/23…
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Question Number 194057 by Subhi last updated on 26/Jun/23 $${find}\:{all}\:{functions}\:{such}\:{that} \\ $$$${f}\left({x}\right){f}\left({y}\right)\:=\:{x}^{{a}} {f}\left(\frac{{y}}{\mathrm{2}}\right)+{y}^{{b}} {f}\left(\frac{{x}}{\mathrm{2}}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194056 by ajfour last updated on 26/Jun/23 Answered by a.lgnaoui last updated on 27/Jun/23 $$\mathrm{ABC}\:\:\:\mathrm{triangle}\:\mathrm{equilaterale}\:\: \\ $$$$\mathrm{AB}=\mathrm{BC}=\mathrm{AC}\:\:\:\mathrm{BC}=\mathrm{2acos}\:\mathrm{30}=\mathrm{a}\sqrt{\mathrm{3}} \\ $$$$\Rightarrow\mathrm{AH}=\mathrm{BCsin}\:\mathrm{60}=\frac{\mathrm{3a}}{\mathrm{2}} \\ $$$$\:\:\mathrm{AI}=\mathrm{AM}+\mathrm{MI}=\mathrm{2a}\:\:\:\:\:\left(\mathrm{i}\right) \\ $$$$\:\:\measuredangle\mathrm{MAN}=\mathrm{30}\:;\mathrm{sin}\:\mathrm{30}=\frac{\mathrm{c}}{\mathrm{AM}}\Rightarrow\:\mathrm{AM}=\mathrm{2}\boldsymbol{\mathrm{c}}…
Question Number 194021 by mr W last updated on 26/Jun/23 $${find}\:\sqrt[{\mathrm{3}}]{\mathrm{1}+\sqrt[{\mathrm{3}}]{\mathrm{2}}+\sqrt[{\mathrm{3}}]{\mathrm{4}}}=? \\ $$ Commented by BaliramKumar last updated on 26/Jun/23 $$\left(\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{3}}} −\mathrm{1}\right)^{−\frac{\mathrm{1}}{\mathrm{3}}} \: \\ $$…
Question Number 194020 by mnjuly1970 last updated on 26/Jun/23 $$\:\:\:\:\:\:{F}_{{n}} =\:{F}_{{n}} \:_{−\mathrm{1}} +{F}_{{n}−\mathrm{2}} \:\:\:\:\:\:{F}_{\mathrm{2}} =\:{F}_{\mathrm{1}} =\mathrm{1}\:\:\:\:\:\:\: \\ $$$$\:\:\:\:{F}_{{n}} \::\:\:\:\:\mathrm{1}\:,\:\mathrm{1}\:,\:\mathrm{2}\:,\:\mathrm{3}\:,\mathrm{5}…\:\: \\ $$$$\:\:\:\:\:\:\:{f}\left({x}\right)=\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:{F}_{{n}} \:{x}^{\:{n}} \:=\:{x}\:+\:{x}^{\:\mathrm{2}}…
Question Number 194017 by MrGHK last updated on 26/Jun/23 Answered by witcher3 last updated on 26/Jun/23 $$\forall\left(\mathrm{x},\mathrm{y},\mathrm{z}\right)\in\left[\mathrm{0},\mathrm{1}\right]^{\mathrm{3}} ,\left(\mathrm{xyz}\right)^{\mathrm{4}} \leqslant\mathrm{1} \\ $$$$\frac{\mathrm{x}^{\mathrm{4}} \mathrm{y}^{\mathrm{6}} \mathrm{z}^{\mathrm{8}} }{\mathrm{1}−\mathrm{x}^{\mathrm{4}} \mathrm{y}^{\mathrm{4}}…
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Question Number 193982 by cortano12 last updated on 25/Jun/23 $$\:\:\:\:\:\int\:\frac{\mathrm{6x}^{\mathrm{3}} +\mathrm{9x}^{\mathrm{2}} +\mathrm{15x}+\mathrm{6}}{\:\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{x}+\mathrm{1}}}\:\mathrm{dx}\:=? \\ $$ Answered by MM42 last updated on 26/Jun/23 $${I}=\left({ax}^{\mathrm{2}} +{bx}+{e}\right)\sqrt{{x}^{\mathrm{2}} +{x}+\mathrm{1}}+{f}\int\frac{{dx}}{\:\sqrt{{x}^{\mathrm{2}}…
Question Number 193976 by Risandu last updated on 25/Jun/23 Answered by Subhi last updated on 25/Jun/23 $$ \\ $$$${lim}_{{x}\rightarrow\mathrm{1}} \frac{\left(^{\mathrm{3}} \sqrt{{x}}−\mathrm{1}\right)^{\mathrm{2}} }{\left({x}−\mathrm{1}\right)^{\mathrm{2}} } \\ $$$${lim}_{{x}\rightarrow\mathrm{1}}…