Question Number 10417 by okhema francis last updated on 08/Feb/17 $${hence}\:{or}\:{other}\mathrm{wise}\:\mathrm{solve}\:\mathrm{sin}\:\mathrm{6}\theta−\mathrm{sin}\:\mathrm{2}\theta=\mathrm{0}\:{for}\:\mathrm{0}\leqslant\theta\leqslant\frac{\pi}{\mathrm{2}}. \\ $$$$ \\ $$ Answered by nume1114 last updated on 08/Feb/17 $$\:\:\:\:\mathrm{sin}\:\left(\alpha+\beta\right)−\mathrm{sin}\:\left(\alpha−\beta\right) \\ $$$$=\left(\mathrm{sin}\:\alpha\mathrm{cos}\:\beta+\mathrm{cos}\:\alpha\mathrm{sin}\:\beta\right)…
Question Number 75953 by mhmd last updated on 21/Dec/19 $${prove}\:{that}\:\left({C}\left({I}\right),+,.\right)\:{identical}\:{in}\:\left({R},+,.\right)? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 75950 by turbo msup by abdo last updated on 21/Dec/19 $${give}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\frac{{x}}{{sinx}}{dx}\:\:{at}\:{form}\:{of}\:{serie}. \\ $$ Commented by mathmax by abdo last updated on…
Question Number 10415 by okhema francis last updated on 08/Feb/17 $${find}\:{all}\:{the}\:{possible}\:{values}\:{of}\:\mathrm{cos}\:\theta\:{such}\:{that}\:\mathrm{2cot}\:^{\mathrm{2}} \theta\:+\:\mathrm{cos}\:\theta=\mathrm{0} \\ $$$$ \\ $$ Answered by bansal22luvi@gmail.com last updated on 08/Feb/17 $$\mathrm{2}\left(\frac{\mathrm{cos}^{\mathrm{2}} \theta}{\mathrm{sin}^{\mathrm{2}}…
Question Number 75951 by turbo msup by abdo last updated on 21/Dec/19 $${give}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\:\frac{{x}^{\mathrm{2}} }{\mathrm{1}−{cosx}}{dx}\:\:{at}\:{form}\:{of} \\ $$$${serie}. \\ $$ Terms of Service Privacy Policy…
Question Number 10414 by amir last updated on 07/Feb/17 Commented by mrW1 last updated on 08/Feb/17 $${the}\:{angle}\:{between}\:{tangent}\:{lines}\:{is} \\ $$$${not}\:{a}\:{constant}! \\ $$ Commented by amir last…
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Question Number 10408 by konen last updated on 07/Feb/17 Answered by mrW1 last updated on 08/Feb/17 $${y}^{\mathrm{2}} ={e}^{{x}+{y}} \\ $$$$\Rightarrow\mathrm{2ln}\:{y}={x}+{y} \\ $$$$\Rightarrow{x}=\mathrm{2ln}\:{y}−{y} \\ $$$$\frac{{dx}}{{dy}}=\frac{\mathrm{2}}{{y}}−\mathrm{1}=\frac{\mathrm{2}−{y}}{{y}} \\…
Question Number 75940 by Rio Michael last updated on 21/Dec/19 $${Given}\:{that}\:{a}\in\mathbb{Z}\:{and}\:{k}\in\mathbb{Z}\:{and}\:\left[{a}+{x}\right]\:=\:{a}\:+\left[{x}\right]\:=\:{k} \\ $$$$\left.{a}\right)\:{show}\:{that}\:\:{k}−{a}\leqslant\:{x}\leqslant\:{k}−{a}\:+\mathrm{1} \\ $$$$\left.{b}\left.\right)\:{Deduce}\:{from}\:\left({a}\right)\right)\:{that}\:\left[{x}+{a}\right]\:=\:\left[{x}\right]\:+{a} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 75938 by Rio Michael last updated on 21/Dec/19 $${solve}\:{the}\:{inequality} \\ $$$$\:{ln}\left({x}^{\mathrm{2}} −\mathrm{4}{e}^{\mathrm{2}} \right)<\:\mathrm{1}\:+\:{ln}\mathrm{3}{x} \\ $$ Commented by turbo msup by abdo last updated…