Question Number 10339 by konen last updated on 04/Feb/17 $$\mathrm{A}=\mathrm{1}×\mathrm{2}\:+\:\mathrm{2}×\mathrm{3}\:+\mathrm{3}×\mathrm{4}+…+\mathrm{10}×\mathrm{11} \\ $$$$\mathrm{B}=\mathrm{3}×\mathrm{8}\:+\mathrm{6}×\mathrm{12}\:+\mathrm{9}×\mathrm{16}+…+\mathrm{30}×\mathrm{44} \\ $$$$\Rightarrow\frac{\mathrm{A}}{\mathrm{B}}=? \\ $$ Answered by mrW1 last updated on 04/Feb/17 $${a}_{{n}} ={n}×\left({n}+\mathrm{1}\right)…
Question Number 75873 by Rio Michael last updated on 19/Dec/19 $$\int{xe}^{{x}} {dx} \\ $$ Answered by MJS last updated on 19/Dec/19 $${u}'=\mathrm{e}^{{x}} \:\Rightarrow\:{u}=\mathrm{e}^{{x}} \\ $$$${v}={x}\:\Rightarrow\:{v}'=\mathrm{1}…
Question Number 141405 by iloveisrael last updated on 18/May/21 $$\:\:\:\:\:{Find}\:{the}\:{minimum}\:{value}\:{of}\:{k} \\ $$$$\:\:\:\:\:{such}\:{that}\:{for}\:{arbitrary}\:{a},{b}\:>\mathrm{0} \\ $$$$\:\:\:\:\:{we}\:{have}\:\:\sqrt[{\mathrm{3}\:}]{{a}}\:+\:\sqrt[{\mathrm{3}\:}]{{b}}\:\leqslant\:{k}\:\sqrt[{\mathrm{3}\:}]{{a}+{b}}\: \\ $$ Answered by EDWIN88 last updated on 18/May/21 $$\:\mathrm{consider}\:\mathrm{the}\:\mathrm{function}\:\mathrm{f}\left(\mathrm{x}\right)\:=\:\sqrt[{\mathrm{3}\:}]{\mathrm{x}} \\…
Question Number 141407 by mnjuly1970 last updated on 18/May/21 $$ \\ $$$$\:\:\:\:\:\:\Omega:=\int_{\mathrm{0}} ^{\:\infty} \frac{{dx}}{\left({x}^{\mathrm{4}} −{x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{3}} }=? \\ $$ Answered by MJS_new last updated on…
Question Number 75868 by Crabby89p13 last updated on 19/Dec/19 $${PROVE}\:\:{THAT} \\ $$$$ \\ $$$$\mathrm{sin3}°\:\mathrm{sin39}°\:\mathrm{sin75}°\:=\:\mathrm{sin}\:\mathrm{9}°\:\mathrm{sin}\:\mathrm{24}°\:\mathrm{sin}\:\mathrm{30}° \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 141400 by Raffaqet last updated on 18/May/21 $${fjnd}\:{inverse}\:{of}\:{matrix}\begin{bmatrix}{\mathrm{2}}&{−\mathrm{5}}\\{\mathrm{1}}&{\mathrm{3}}\end{bmatrix} \\ $$ Answered by iloveisrael last updated on 18/May/21 $$\:{A}^{−\mathrm{1}} \:=\:\frac{\mathrm{1}}{\mathrm{6}−\left(−\mathrm{5}\right)}\:\begin{bmatrix}{\:\:\:\:\mathrm{3}\:\:\:\:\:\mathrm{5}}\\{−\mathrm{1}\:\:\:\:\:\mathrm{2}}\end{bmatrix} \\ $$$${A}^{−\mathrm{1}} \:=\:\begin{bmatrix}{\mathrm{3}/\mathrm{11}\:\:\:\:\:\:\:\:\:\mathrm{5}/\mathrm{11}}\\{−\mathrm{1}/\mathrm{11}\:\:\:\:\:\mathrm{2}/\mathrm{11}}\end{bmatrix} \\…
Question Number 75860 by peter frank last updated on 18/Dec/19 $${complete}\:{and}\:{balance}\: \\ $$$${S}+{HNO}_{\mathrm{3}} \rightarrow \\ $$$$ \\ $$ Answered by Crabby89p13 last updated on 19/Dec/19…
Question Number 141398 by miktun last updated on 18/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10324 by amir last updated on 04/Feb/17 Answered by mrW1 last updated on 04/Feb/17 $${y}=\frac{\mathrm{1}}{{x}} \\ $$$${slope}\:{of}\:{tangent}\:{line}: \\ $$$${m}_{{t}} \left({x}\right)=\mathrm{tan}\:\theta={y}'\left({x}\right)=−\frac{\mathrm{1}}{{x}^{\mathrm{2}} } \\ $$$${let}\:{B}\left({t},{s}\right)\:{be}\:{a}\:{point}\:{on}\:{the}\:{curve}\:…
Question Number 10323 by amir last updated on 04/Feb/17 Answered by mrW1 last updated on 04/Feb/17 $${there}\:{are}\:\mathrm{4}\:{circles}\:{which}\:{tangent} \\ $$$${the}\:{curve}\:{and}\:{the}\:{both}\:{coordinate}\:{axes}. \\ $$$${they}\:{tangent}\:{the}\:{curve}\:{at}\:{point}\:\left(\mathrm{1},\mathrm{1}\right) \\ $$$${as}\:{well}\:{as}\:{at}\:{point}\left(−\mathrm{1},−\mathrm{1}\right). \\ $$$$…