Question Number 141244 by ajfour last updated on 17/May/21 $${I}=\int_{\mathrm{0}} ^{\:\infty} \frac{{x}\left\{\left({a}^{\mathrm{2}} −{b}^{\mathrm{2}} \right){x}−\mathrm{2}{a}^{\mathrm{2}} {x}^{\mathrm{2}} −\mathrm{2}{b}^{\mathrm{2}} \right\}{dx}}{\left({a}^{\mathrm{2}} {x}^{\mathrm{2}} +{b}^{\mathrm{2}} \right)^{\mathrm{2}} \left\{\left({a}^{\mathrm{2}} −{b}^{\mathrm{2}} \right){x}+{a}^{\mathrm{2}} {x}^{\mathrm{2}} +{b}^{\mathrm{2}}…
Question Number 141246 by ajfour last updated on 17/May/21 $${r}={q}+\mathrm{1} \\ $$$${pq}={q}+\mathrm{1} \\ $$$${c}^{\mathrm{2}} {p}={qr}^{\mathrm{2}} \:\:\:,\:{help}\:{find}\:{p},\:{q},\:{r}. \\ $$ Answered by Rasheed.Sindhi last updated on 17/May/21…
Question Number 10172 by konen last updated on 28/Jan/17 $$\mathrm{x}^{\mathrm{x}} =\mathrm{2}^{\mathrm{24}} \:,\:\mathrm{y}^{\mathrm{y}} =\mathrm{3}^{\mathrm{18}} \Rightarrow\frac{\mathrm{2y}+\mathrm{3x}}{\mathrm{y}−\mathrm{x}}=? \\ $$ Answered by ridwan balatif last updated on 28/Jan/17 $$\mathrm{x}^{\mathrm{x}}…
Question Number 141240 by Ar Brandon last updated on 16/May/21 $$\mathrm{Solve}\:\mathrm{using}\:\mathrm{fourier}'\mathrm{s}\:\mathrm{series} \\ $$$$−\mathrm{y}''+\mathrm{y}=\mathrm{e}^{−\mathrm{2}\mid\mathrm{x}\mid} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10170 by Joel575 last updated on 28/Jan/17 $${y}\:.\:{f}\left({xy}\right)\:=\:{f}\left({x}\right)\:\:\:\:\:\:\:\:{x},\mathrm{y}\:\in\:\mathbb{R} \\ $$$$\mathrm{If}\:{f}\left(\mathrm{4}\right)\:=\:\mathrm{1006},\:\mathrm{so}\:{f}\left(\mathrm{2012}\right)\:=\:? \\ $$ Answered by ridwan balatif last updated on 28/Jan/17 $$\mathrm{f}\left(\mathrm{xy}\right)=\frac{\mathrm{f}\left(\mathrm{x}\right)}{\mathrm{y}},\:\:\:\:\mathrm{f}\left(\mathrm{4}\right)=\mathrm{1006} \\ $$$$\mathrm{if}\:\mathrm{x}=\mathrm{1}\:\mathrm{y}=\mathrm{4},\mathrm{then}…
Question Number 141243 by Ar Brandon last updated on 16/May/21 $$\begin{cases}{\mathrm{ty}''+\mathrm{y}'+\mathrm{ty}=\mathrm{0}}\\{\mathrm{y}\left(\mathrm{0}^{+} \right)=\mathrm{1}}\end{cases} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10169 by Joel575 last updated on 28/Jan/17 $$\frac{\mathrm{2013}}{\mathrm{1}}\:+\:\frac{\mathrm{2013}}{\mathrm{1}+\mathrm{2}}\:+\:\frac{\mathrm{2013}}{\mathrm{1}+\mathrm{2}+\mathrm{3}}\:+\:…\:+\:\frac{\mathrm{2013}}{\mathrm{1}+\mathrm{2}+\mathrm{3}+…+\mathrm{2012}}\:=\:? \\ $$ Answered by prakash jain last updated on 29/Jan/17 $$\underset{{i}=\mathrm{1}} {\overset{\mathrm{2012}} {\sum}}\:\frac{\mathrm{2013}}{\underset{{j}=\mathrm{1}} {\overset{{i}} {\sum}}{j}}\:=\:\:\mathrm{2013}\underset{{i}=\mathrm{1}}…
Question Number 10168 by Joel575 last updated on 28/Jan/17 $$\mathrm{If}\:\mathrm{the}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{quadratic}\:\mathrm{equation} \\ $$$${ax}^{\mathrm{2}} \:+\:{bx}\:+\:{c}\:=\:\mathrm{0} \\ $$$$\mathrm{were}\:\mathrm{within}\:\mathrm{the}\:\mathrm{interval}\:\left[\mathrm{0},\mathrm{1}\right], \\ $$$$\mathrm{the}\:\mathrm{maximum}\:\mathrm{value}\:\mathrm{from} \\ $$$$\frac{\left(\mathrm{2}{a}−{b}\right)\left({a}−{b}\right)}{{a}\left({a}−{b}+{c}\right)}\:\:\:\:\mathrm{is}\:… \\ $$ Terms of Service Privacy…
Question Number 10166 by Joel575 last updated on 28/Jan/17 Commented by Joel575 last updated on 28/Jan/17 $$\mathrm{Two}\:\mathrm{circles}\:\mathrm{with}\:\mathrm{same}\:\mathrm{center}\:\mathrm{point}\:\mathrm{have} \\ $$$$\mathrm{R}_{\mathrm{1}} \:\mathrm{and}\:\mathrm{R}_{\mathrm{2}} \:\mathrm{with}\:\mathrm{R}_{\mathrm{1}} \:<\:\mathrm{R}_{\mathrm{2}} \\ $$$$\mathrm{If}\:\mathrm{the}\:\mathrm{long}\:\mathrm{of}\:\mathrm{AB}\:\mathrm{bowstring}\:\mathrm{is}\:\mathrm{10}\:\mathrm{cm}, \\…
Question Number 75701 by vishalbhardwaj last updated on 15/Dec/19 $$\mathrm{please}\:\mathrm{tell}\:\mathrm{me}\::\left(\infty\right)^{\mathrm{0}\:} \mathrm{is}\:\mathrm{not}\:\mathrm{defined}\:? \\ $$ Commented by malwaan last updated on 16/Dec/19 $${yes} \\ $$$${but}\:\mathrm{0}^{\infty} \:=\:\mathrm{0} \\…