Question Number 10095 by Tawakalitu ayo mi last updated on 23/Jan/17 $$\mathrm{Prove}\:\mathrm{that}\:\:\mathrm{f}\left(\mathrm{x}\right)\:=\:\mathrm{x}^{\mathrm{2}} \:\:\mathrm{is}\:\mathrm{continous}\:\mathrm{at}\:\mathrm{x}\:=\:\mathrm{2} \\ $$$$\mathrm{while}\:\mathrm{f}\left(\mathrm{x}\right)\:=\:\left\{_{\mathrm{0}\:\:\:\:\:\:\:\:\:\mathrm{x}\:=\:\mathrm{2}} ^{\mathrm{x}^{\mathrm{2}} \:\:\:\:\:\:\:\mathrm{x}\:\neq\:\mathrm{2}} \:\:\:\mathrm{is}\:\mathrm{not}\:\mathrm{continous}\:\mathrm{at}\:\mathrm{x}\:=\:\mathrm{2}\right. \\ $$ Answered by sandy_suhendra last updated…
Question Number 141164 by iloveisrael last updated on 16/May/21 $$\:\:\:\:{Find}\:{maximum}\:{value}\: \\ $$$$\:\:\:{of}\:{the}\:{product}\:{xy}\left(\mathrm{72}−\mathrm{3}{x}−\mathrm{4}{y}\right) \\ $$$$\:\:\:\:{for}\:{positive}\:{value}\:{of}\:{x}\:\&\:{y}. \\ $$ Commented by mitica last updated on 16/May/21 $${max}=\mathrm{1152}\:{for}\:{x}=\mathrm{8},{y}=\mathrm{6} \\…
Question Number 10094 by Tawakalitu ayo mi last updated on 23/Jan/17 $$\mathrm{Prove}\:\mathrm{that}\:\mathrm{if}\:\:\:\underset{{x}\rightarrow\mathrm{a}} {\mathrm{lim}}\:\:\mathrm{f}_{\mathrm{1}} \left(\mathrm{x}\right)\:=\:\mathrm{L}_{\mathrm{1}} \:\:\mathrm{and}\:\: \\ $$$$\underset{{x}\rightarrow\mathrm{a}} {\mathrm{lim}}\:\:\:\mathrm{f}_{\mathrm{2}} \left(\mathrm{x}\right)\:=\:\mathrm{L}_{\mathrm{2}} \:\mathrm{then}\:\underset{{x}\rightarrow\mathrm{a}} {\mathrm{lim}}\:\left[\mathrm{f}_{\mathrm{1}} \left(\mathrm{x}\right)+\mathrm{f}_{\mathrm{2}} \left(\mathrm{x}\right)\right]\:=\:\mathrm{L}_{\mathrm{1}} +\mathrm{L}_{\mathrm{2}} \\…
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Question Number 10091 by konen last updated on 23/Jan/17 $$\frac{\mathrm{a}−\mathrm{1}}{\mathrm{b}−\mathrm{2}}\:=\frac{\mathrm{2}}{\mathrm{3}}\:\:,\frac{\mathrm{c}+\mathrm{1}}{\mathrm{c}−\mathrm{1}}=\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\Rightarrow\mathrm{2a}−\mathrm{c}+\mathrm{10}=? \\ $$ Answered by ridwan balatif last updated on 24/Jan/17 $$\frac{\mathrm{a}−\mathrm{1}}{\mathrm{b}−\mathrm{2}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$\mathrm{3}\left(\mathrm{a}−\mathrm{1}\right)=\mathrm{2}\left(\mathrm{b}−\mathrm{2}\right)…
Question Number 75627 by liki last updated on 14/Dec/19 Answered by $@ty@m123 last updated on 14/Dec/19 $$\boldsymbol{{Initially}}, \\ $$$${Length}={l} \\ $$$${Breadth}={b} \\ $$$$\therefore\:{Diagonal}\:\:\:\boldsymbol{{d}}=\sqrt{{l}^{\mathrm{2}} +{b}^{\mathrm{2}} }\:\:……\left(\mathrm{1}\right)…
Question Number 141163 by Niiicooooo last updated on 16/May/21 Answered by mindispower last updated on 16/May/21 $$\zeta\left({n}\right)=\mathrm{1}+\underset{{k}\geqslant\mathrm{2}} {\sum}\frac{\mathrm{1}}{{k}^{{n}} } \\ $$$${k}^{{n}} \geqslant{nk}^{\mathrm{2}} \:{easy}\:{to}\:{see}\:{that}\:,{k}\geqslant\mathrm{2} \\ $$$${for}\:{n}>>\mathrm{2}…
Question Number 75623 by liki last updated on 14/Dec/19 Commented by liki last updated on 14/Dec/19 $$…\boldsymbol{{Please}}\:\boldsymbol{{anyone}}\:\boldsymbol{{to}}\:\boldsymbol{{help}}\:\boldsymbol{{me}}\:\boldsymbol{{this}}\:\boldsymbol{{Qn}}\:! \\ $$ Answered by $@ty@m123 last updated on…
Question Number 141153 by iloveisrael last updated on 16/May/21 Answered by iloveisrael last updated on 16/May/21 Commented by SamuelAsaana last updated on 16/May/21 $${i}\:{donot}\:{underdtand}\:{sir}\:{please}\:{explain}\:{for}\:{for}\:{me} \\…
Question Number 75618 by peter frank last updated on 13/Dec/19 Commented by mind is power last updated on 13/Dec/19 $$\mathrm{use}\:\mathrm{x}+\mathrm{y}\geqslant\mathrm{2}\sqrt{\mathrm{xy}} \\ $$$$\left(\mathrm{a}+\mathrm{b}\right)\geqslant\mathrm{2}\sqrt{\mathrm{ab}},\left(\mathrm{a}+\mathrm{c}\right)\geqslant\mathrm{2}\sqrt{\mathrm{ac}},\mathrm{c}+\mathrm{a}\geqslant\mathrm{2}\sqrt{\mathrm{ca}} \\ $$$$\Rightarrow\left(\mathrm{a}+\mathrm{b}\right)\left(\mathrm{b}+\mathrm{c}\right)\left(\mathrm{c}+\mathrm{a}\right)\geqslant\mathrm{2}\sqrt{\mathrm{ab}}.\mathrm{2}\sqrt{\mathrm{bc}}.\mathrm{2}\sqrt{\mathrm{ac}}=\mathrm{8abc} \\…