Question Number 193938 by yaslm last updated on 23/Jun/23 Answered by BaliramKumar last updated on 23/Jun/23 $$\mathrm{15}° \\ $$ Commented by yaslm last updated on…
Question Number 193924 by talminator2856792 last updated on 23/Jun/23 $$\:\:\underline{\mathrm{question}\:\mathrm{about}\:\mathrm{tinkutara}} \\ $$$$\:\:\mathrm{how}\:\mathrm{can}\:\mathrm{an}\:\mathrm{answer}\:\mathrm{be}\:\mathrm{placed}\:\: \\ $$$$\:\:\mathrm{in}\:\mathrm{a}\:\mathrm{box}. \\ $$ Commented by pablo1234523 last updated on 23/Jun/23 $$\begin{array}{|c|}{\mathrm{Something}\:\mathrm{like}\:\mathrm{this}?}\\\hline\end{array} \\…
Question Number 193953 by Spillover last updated on 24/Jun/23 $${Name}\:{thefollowing}\:{Complex}\:{compound} \\ $$$$\left({a}\right)\left[{Zn}\left({en}\right)_{\mathrm{2}} \left({c}_{\mathrm{2}} {o}_{\mathrm{2}} \right){Br}_{\mathrm{2}} {F}\right]^{−\mathrm{5}} \\ $$$$\left.\left({b}\right){Ni}\left({CN}\right)_{\mathrm{2}} \left({OH}\right)_{\mathrm{3}} {Cl}\right]\:\:\left[{Fe}\left({H}_{\mathrm{2}} {O}\right)_{\mathrm{3}} \left({OH}\right)_{\mathrm{2}} {F}_{\mathrm{2}} {Br}\right] \\…
Question Number 193921 by Mastermind last updated on 23/Jun/23 $$\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{kernel}\:\mathrm{of}\:\mathrm{a}\:\mathrm{group}\:\mathrm{homomorhism} \\ $$$$\theta\::\:\mathrm{G}\:\rightarrow\:\mathrm{H}\:\mathrm{is}\:\mathrm{a}\:\mathrm{normal}\:\mathrm{subgroup}. \\ $$$$\mathrm{Hint}:\:\mathrm{Check}\:\mathrm{the}\:\mathrm{existence}\:\mathrm{of}\:\mathrm{the}\:\mathrm{combination} \\ $$$$\mathrm{g}^{−\mathrm{1}} \mathrm{kg}\:\mathrm{in}\:\mathrm{the}\:\mathrm{kernel}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 193886 by Rupesh123 last updated on 22/Jun/23 Answered by MM42 last updated on 22/Jun/23 $${a}=\mathrm{521}\left(\mathrm{521}^{{n}} −\mathrm{521}^{{n}−\mathrm{1}} +\mathrm{1}\right)=\mathrm{521}{m} \\ $$$$“\mathrm{521}''\:{is}\:{prime}\:{number}.{therefore}\:“{m}'' \\ $$$$\:{must}\:{be}\:{a}\:{multiple}\:“\mathrm{521}''. \\ $$$${which}\:{is}\:{valid}\:{only}\:{for}\:\:“{n}=\mathrm{1}''…
Question Number 193880 by Mingma last updated on 22/Jun/23 Answered by Subhi last updated on 22/Jun/23 $${put}\:{length}\:{of}\:{each}\:{side}\:=\:{l} \\ $$$${BAF}\:=\:\mathrm{120}\:\Rrightarrow\:{AFB}\:=\:{ABF}\:=\:\frac{\mathrm{180}−\mathrm{120}}{\mathrm{2}}=\mathrm{30} \\ $$$$\frac{{BF}}{{sin}\left(\mathrm{120}\right)}=\frac{{l}}{{sin}\left(\mathrm{30}\right)}\:\Rrightarrow\:{BF}\:=\:\sqrt{\mathrm{3}}\:{l}\: \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}{l}^{\mathrm{2}} \:.\:{sin}\left(\mathrm{120}\right)=\mathrm{2}\:\:\Rrightarrow\:{l}\:=\:\sqrt{\frac{\mathrm{8}\sqrt{\mathrm{3}}}{\mathrm{3}}} \\…
Question Number 193883 by byaw last updated on 22/Jun/23 $$ \\ $$If a 9000kg water flows in a minute through a pipe of cross sectional…
Question Number 193908 by Rupesh123 last updated on 22/Jun/23 Answered by Subhi last updated on 22/Jun/23 $${put}\:{each}\:{side}\:=\:{l} \\ $$$${BH}\:=\:{AG}\:=\:\frac{{l}}{\mathrm{2}} \\ $$$${G}\hat {{A}K}={M}\hat {{B}H}=\mathrm{120}−\mathrm{90}=\mathrm{30} \\ $$$${HM}\:=\:{GK}\:=\:\frac{{l}}{\mathrm{4}}\:\left({opposite}\:{to}\:{angle}\:\mathrm{30}\:{in}\:{a}\:{right}\:{triangle}\right)…
Question Number 193875 by Subhi last updated on 22/Jun/23 $${a},{b},{c},{d},{e},{f},\:{are}\:+\:{real}\:{numbers} \\ $$$${prove}: \\ $$$$\frac{{a}}{{b}+{c}}+\frac{{b}}{{c}+{d}}+\frac{{c}}{{d}+{e}}+\frac{{d}}{{e}+{f}}+\frac{{e}}{{f}+{a}}+\frac{{f}}{{a}+{b}}\geqslant\mathrm{3} \\ $$ Answered by AST last updated on 23/Jun/23 $$=\underset{{cyc}} {\sum}\frac{{a}^{\mathrm{2}}…
Question Number 193906 by cherokeesay last updated on 22/Jun/23 Answered by Subhi last updated on 22/Jun/23 $$ \\ $$$$\frac{\mathrm{1}}{{sin}\left(\mathrm{18}\right)}=\frac{\mathrm{1}+{y}}{{sin}\left(\mathrm{144}−{x}\right)}\: \\ $$$$\frac{\mathrm{1}}{{sin}\left(\mathrm{18}\right)}=\frac{{y}}{{sin}\left({x}\right)}\:\Rrightarrow\:{y}\:=\:\frac{{sin}\left({x}\right)}{{sin}\left(\mathrm{18}\right)} \\ $$$$\frac{\mathrm{1}}{{sin}\left(\mathrm{18}\right)}=\frac{\mathrm{1}+\frac{{sin}\left({x}\right)}{{sin}\left(\mathrm{18}\right)}}{{sin}\left(\mathrm{144}−{x}\right)} \\ $$$${sin}\left(\mathrm{144}−{x}\right)={sin}\left(\mathrm{18}\right)+{sin}\left({x}\right)…