Question Number 9954 by Tawakalitu ayo mi last updated on 18/Jan/17 $$\mathrm{A}\:\mathrm{sound}\:\mathrm{wave}\:\mathrm{of}\:\mathrm{velocity}\:\mathrm{350}\:\mathrm{m}/\mathrm{s}\:\mathrm{is}\:\mathrm{directed} \\ $$$$\mathrm{towards}\:\mathrm{the}\:\mathrm{surface}\:\mathrm{of}\:\mathrm{water}\:.\:\mathrm{If}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{wave}\:\mathrm{length}\:\mathrm{of}\:\mathrm{sound}\:\mathrm{in}\:\mathrm{water}\:\mathrm{to}\:\mathrm{that}\:\mathrm{in}\: \\ $$$$\mathrm{air}\:\mathrm{is}\:\mathrm{425}:\mathrm{100},\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{wave}\:\mathrm{in}\:\mathrm{water}. \\ $$ Answered by sandy_suhendra…
Question Number 9953 by konen last updated on 18/Jan/17 $$\mathrm{x}−\mathrm{y}\:=\mathrm{8} \\ $$$$\mathrm{xy}=\mathrm{7}\:\:\Rightarrow\:\mathrm{x}^{\mathrm{2}} −\mathrm{y}^{\mathrm{2}} \:=? \\ $$ Answered by mrW1 last updated on 19/Jan/17 $$\left({x}−{y}\right)^{\mathrm{2}} =\mathrm{8}^{\mathrm{2}}…
Question Number 9952 by Johnexcel last updated on 18/Jan/17 $$\int{e}^{{xy}^{\mathrm{2}\:} } {dy}\:\:\:\:\:\:\:_{} {help}\:{solve} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9951 by aksir1986 last updated on 18/Jan/17 $$\int\sqrt{{tan}\:{x}}{dx} \\ $$ Answered by prakash jain last updated on 19/Jan/17 $$\mathrm{check}\:\mathrm{question}\:\mathrm{119} \\ $$ Terms of…
Question Number 75484 by vishalbhardwaj last updated on 11/Dec/19 $$\mathrm{If}\:\theta\:\mathrm{is}\:\mathrm{eleminated}\:\mathrm{from}\:\mathrm{the} \\ $$$$\mathrm{equation}\:{x}={a}\:{cos}\left(\theta−\alpha\right)\:\mathrm{and} \\ $$$${y}={b}\:{cos}\left(\theta−\beta\right)\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that} \\ $$$$\frac{{x}^{\mathrm{2}} }{{a}^{\mathrm{2}} }\:+\:\frac{{y}^{\mathrm{2}} }{{b}^{\mathrm{2}} }\:−\frac{\mathrm{2}{xy}}{{ab}}\:{cos}\left(\alpha−\beta\right)\: \\ $$$$=\:{sin}^{\mathrm{2}} \left(\alpha−\beta\right) \\ $$…
Question Number 141017 by 777316 last updated on 14/May/21 Commented by mnjuly1970 last updated on 15/May/21 $$\:\:{hello}\:{mr}\:: \\ $$$$\:\:{what}\:“{font}“\:{and}\:“\:{app}“\:{did}\:{you} \\ $$$$\:{use}\:{to}\:{write}\:{math}?? \\ $$$$\:\: \\ $$…
Question Number 9947 by ridwan balatif last updated on 18/Jan/17 Commented by sandy_suhendra last updated on 18/Jan/17 $$\mathrm{x}=\mathrm{3}+\frac{\mathrm{1}}{\mathrm{3}+\frac{\mathrm{1}}{\mathrm{x}}}\:\:\Rightarrow\:\mathrm{x}=\mathrm{3}+\frac{\mathrm{1}}{\mathrm{x}}\:\Rightarrow\:\mathrm{x}^{\mathrm{2}} =\mathrm{3x}+\mathrm{1}\Rightarrow\mathrm{x}^{\mathrm{2}} −\mathrm{3x}−\mathrm{1}=\mathrm{0} \\ $$$$ \\ $$$$\mathrm{y}=\mathrm{3}\:+\:\frac{\mathrm{1}}{\mathrm{3}+\frac{\mathrm{1}}{\mathrm{3}+\frac{\mathrm{1}}{\mathrm{y}}}}\:\Rightarrow\:\mathrm{y}=\mathrm{3}+\frac{\mathrm{1}}{\mathrm{y}}\:\Rightarrow\mathrm{y}^{\mathrm{2}} =\mathrm{3y}+\mathrm{1}\Rightarrow\mathrm{y}^{\mathrm{2}}…
Question Number 141012 by ajfour last updated on 14/May/21 $$\:{s}^{\mathrm{2}} \left({s}+\mathrm{1}\right)^{\mathrm{2}} +\frac{{c}}{\mathrm{2}}{s}\left({s}+\mathrm{1}\right)^{\mathrm{2}} −\frac{{c}^{\mathrm{2}} }{\mathrm{2}}\left({s}+\mathrm{1}\right) \\ $$$$\:\:+\frac{{c}^{\mathrm{3}} }{\mathrm{2}}\:=\:\mathrm{0}\:\:\:\:\:{solve}\:{for}\:{s}\:{in}\:{terms} \\ $$$${of}\:\:\:\:\mathrm{0}<{c}<\frac{\mathrm{2}}{\mathrm{3}\sqrt{\mathrm{3}}}\:. \\ $$ Terms of Service Privacy…
Question Number 9941 by Tawakalitu ayo mi last updated on 17/Jan/17 $$\mathrm{Prove}\:\mathrm{that}. \\ $$$$\mathrm{tan}^{−\mathrm{1}} \left[\frac{\mathrm{p}}{\mathrm{p}\:+\:\mathrm{2q}}\right]\:+\:\mathrm{tan}^{−\mathrm{1}} \left[\frac{\mathrm{q}}{\mathrm{p}\:+\:\mathrm{q}}\right]\:=\:\frac{\pi}{\mathrm{4}} \\ $$ Answered by mrW1 last updated on 17/Jan/17…
Question Number 9936 by Tawakalitu ayo mi last updated on 16/Jan/17 $$\mathrm{Two}\:\mathrm{parallel}\:\mathrm{plate}\:\mathrm{capacitor}\:\mathrm{seperated}\:\mathrm{by}\:\mathrm{a} \\ $$$$\mathrm{di}\:\mathrm{electric}\:\mathrm{of}\:\mathrm{thickness}\:\mathrm{5mm}.\:\mathrm{They}\:\mathrm{acquire} \\ $$$$\mathrm{a}\:\mathrm{charge}\:\mathrm{of}\:\mathrm{55}\:\mathrm{milli}\:\mathrm{coloumb},\:\mathrm{when}\:\mathrm{a}\:\mathrm{voltage} \\ $$$$\mathrm{180}\:\mathrm{volt}\:\mathrm{is}\:\mathrm{connected}\:\mathrm{accross}\:\mathrm{them}.\: \\ $$$$\mathrm{calculate}\:\mathrm{electric}\:\mathrm{field}\:\mathrm{strength}. \\ $$ Terms of Service…