Question Number 193874 by cortano12 last updated on 22/Jun/23 Answered by Subhi last updated on 22/Jun/23 $$ \\ $$$${cos}\left({y}\right)=\mathrm{1}−\mathrm{2}{sin}^{\mathrm{2}} \left(\frac{{y}}{\mathrm{2}}\right) \\ $$$$\mathrm{1}−{cos}\left({cx}^{\mathrm{2}} +{bx}+{a}\right)=\mathrm{2}{sin}^{\mathrm{2}} \left(\frac{{cx}^{\mathrm{2}} +{bx}+{a}}{\mathrm{2}}\right)…
Question Number 193896 by Mastermind last updated on 22/Jun/23 $$\mathrm{Ques}.\:\mathrm{12} \\ $$$$\mathrm{If}\:\mathrm{Y}\:=\:\left\{\mathrm{0},\:\mathrm{1},\:\mathrm{2},\:\mathrm{3},\:\mathrm{4}\right\}\:\mathrm{is}\:\mathrm{transversal}\:\mathrm{for}\:\mathrm{5}\mathbb{Z} \\ $$$$\mathrm{in}\:\left(\mathbb{Z},\:+\right).\:\mathrm{Show}\:\mathrm{whether}\:\mathrm{or}\:\mathrm{not}\:\mathrm{Y}\:\mathrm{is}\:\mathrm{a}\: \\ $$$$\mathrm{subgroup}\:\mathrm{of}\:\mathrm{5}\mathbb{Z}\: \\ $$$$ \\ $$$$\mathrm{subgroup}\:\mathrm{under}\:\mathrm{addition}\:\mathrm{of}\:\mathrm{integers}\:\mathrm{modulo} \\ $$$$\mathrm{of}\:\mathrm{5} \\ $$ Terms…
Question Number 193893 by Mastermind last updated on 22/Jun/23 $$\mathrm{Ques}.\:\mathrm{11} \\ $$$$\:\:\:\:\:\mathrm{Let}\:\left\{\mathrm{H}_{\alpha} \right\}\:\in\:\Omega\:\mathrm{be}\:\mathrm{a}\:\mathrm{family}\:\mathrm{of}\:\mathrm{subgroup}\:\mathrm{of} \\ $$$$\mathrm{a}\:\mathrm{group}\:\mathrm{G}\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}\:\underset{\alpha=\Omega} {\cap}\mathrm{H}_{\alpha} \:\mathrm{is}\:\mathrm{also}\:\mathrm{a} \\ $$$$\mathrm{subgroup} \\ $$$$ \\ $$$$\mathrm{Ques}.\:\mathrm{12}\: \\ $$$$\:\:\:\:\:\mathrm{Using}\:\mathrm{GAP},\:\mathrm{find}\:\mathrm{the}\:\mathrm{elements}\:\mathrm{A},\:\mathrm{B}\:\mathrm{and}\:…
Question Number 193892 by Mastermind last updated on 22/Jun/23 $$\mathrm{Ques}. \\ $$$$\:\:\:\:\:\mathrm{Find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{integers}\:\mathrm{in}\:\mathrm{the}\:\mathrm{set} \\ $$$$\mathrm{S}=\left\{\mathrm{1},\mathrm{2},\mathrm{3},…,\mathrm{60}\right\}\:\mathrm{which}\:\mathrm{are}\:\mathrm{not}\:\mathrm{divisible} \\ $$$$\mathrm{by}\:\mathrm{2}\:\mathrm{nor}\:\mathrm{by}\:\mathrm{3}\:\mathrm{nor}\:\mathrm{by}\:\mathrm{5}. \\ $$$$ \\ $$$$\mathrm{Hello} \\ $$ Answered by BaliramKumar…
Question Number 193853 by York12 last updated on 21/Jun/23 $$ \\ $$$$\boldsymbol{{Let}}\:\boldsymbol{{n}}\:\&\:\boldsymbol{{k}}\:\boldsymbol{{be}}\:\boldsymbol{{positive}}\:\boldsymbol{{integers}}\:\boldsymbol{{and}}\:\boldsymbol{{let}} \\ $$$$\boldsymbol{{S}}\:\boldsymbol{{be}}\:\boldsymbol{{a}}\:\boldsymbol{{set}}\:\boldsymbol{{of}}\:\boldsymbol{{n}}\:\boldsymbol{{points}}\:\boldsymbol{{in}}\:\boldsymbol{{The}}\:\boldsymbol{{plane}}\:\boldsymbol{{such}}\:\boldsymbol{{that}}\:: \\ $$$$\boldsymbol{{For}}\:\boldsymbol{{any}}\:\boldsymbol{{point}}\:\boldsymbol{{P}}\:\boldsymbol{{of}}\:\boldsymbol{{S}}\:\boldsymbol{{there}}\:\boldsymbol{{are}}\:\boldsymbol{{at}}\:\boldsymbol{{least}}\:\boldsymbol{{K}}\:\boldsymbol{{points}}\:\boldsymbol{{of}}\:\boldsymbol{{S}}\:\boldsymbol{{Equidistant}}\:\boldsymbol{{from}}\:\boldsymbol{{p}} \\ $$$$\boldsymbol{{Prove}}\:\boldsymbol{{that}}\:\boldsymbol{{k}}<\frac{\mathrm{1}}{\mathrm{2}}+\sqrt{\mathrm{2}\boldsymbol{{n}}} \\ $$ Terms of Service Privacy Policy…
Question Number 193852 by SaRahAli last updated on 21/Jun/23 Answered by cortano12 last updated on 21/Jun/23 $$\:\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\int\:\frac{\mathrm{sin}\:\mathrm{2x}}{\mathrm{cos}\:\left(\mathrm{x}−\frac{\pi}{\mathrm{4}}\right)}=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\int\:\frac{\mathrm{cos}\:\mathrm{2u}}{\mathrm{cos}\:\mathrm{u}}\:\mathrm{du} \\ $$$$\:=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\int\:\frac{\mathrm{2cos}\:^{\mathrm{2}} \mathrm{u}−\mathrm{1}}{\mathrm{cos}\:\mathrm{u}}\:\mathrm{du} \\ $$$$\:=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\left[\int\:\mathrm{2cos}\:\mathrm{u}\:\mathrm{du}−\int\mathrm{sec}\:\mathrm{u}\:\mathrm{du}\:\right] \\ $$$$\:=\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\:\left[\:\mathrm{2sin}\:\mathrm{u}−\mathrm{ln}\:\mid\mathrm{sec}\:\mathrm{u}+\mathrm{tan}\:\mathrm{u}\mid\:+\mathrm{c}\:\right. \\…
Question Number 193848 by Mingma last updated on 21/Jun/23 Answered by MM42 last updated on 21/Jun/23 $$\frac{\mathrm{1}}{\mathrm{2}}×\frac{\mathrm{3}}{\mathrm{4}}×\frac{\mathrm{5}}{\mathrm{6}}×…×\:?\:×\frac{\mathrm{2024}}{\mathrm{2025}}\: \\ $$ Answered by witcher3 last updated on…
Question Number 193847 by Mingma last updated on 21/Jun/23 Answered by witcher3 last updated on 21/Jun/23 $$=\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{ln}\left(\mathrm{1}−\mathrm{x}\right)}{\mathrm{x}}\mathrm{dx}=−\mathrm{Li}_{\mathrm{2}} \left(\mathrm{1}\right)=−\frac{\pi^{\mathrm{2}} }{\mathrm{6}} \\ $$$$\frac{\mathrm{1}}{\mathrm{1}−\mathrm{x}}=\Sigma\mathrm{x}^{\mathrm{k}} \\ $$$$=\int_{\mathrm{0}}…
Question Number 193871 by Mastermind last updated on 21/Jun/23 $$\mathrm{Ques}.\:\mathrm{8}\: \\ $$$$\:\:\:\:\:\mathrm{Find}\:\mathrm{the}\:\mathrm{signum}\:\left(\mathrm{sign}\:\mathrm{or}\:\mathrm{sgn}\right)\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{permutation}\:\theta=\left(\mathrm{12345678}\right). \\ $$$$\mathrm{Hint}\::\:\mathrm{for}\:\mathrm{any}\:\mathrm{permutation}\:\beta,\:\mathrm{take} \\ $$$$\mathrm{sgn}\:\beta\:=\:\left\{_{−\mathrm{1}\:\:\:\:\:\:\:\mathrm{if}\:\beta\:\mathrm{is}\:\mathrm{odd}} ^{\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{if}\:\beta\:\mathrm{is}\:\mathrm{even}} \right. \\ $$$$ \\ $$$$ \\…
Question Number 193864 by pascal889 last updated on 21/Jun/23 Answered by MM42 last updated on 21/Jun/23 $$\frac{\frac{{n}!}{\left({n}−\mathrm{5}\right)!}}{\frac{{n}!}{\mathrm{4}!\left({n}−\mathrm{4}\right)!}}=\mathrm{144}\Rightarrow{n}−\mathrm{4}=\mathrm{6}\Rightarrow{n}=\mathrm{10}\checkmark \\ $$ Terms of Service Privacy Policy Contact:…