Question Number 140937 by harckinwunmy last updated on 14/May/21 $${can}\:{someone}\:{please}\:{share}\:{maple}\:{with}\:{me}\:{or}\:{show}\:{me}\:{the}\:{site}\:{to}\:{download}\:{free}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 75402 by vishalbhardwaj last updated on 10/Dec/19 $$\mathrm{Explain}\:\mathrm{the}\:\mathrm{proof}\: \\ $$$$\mathrm{with}\:\mathrm{appropriate} \\ $$$$\mathrm{diagram}\::\: \\ $$$$\mathrm{Lim}_{{h}\rightarrow\mathrm{0}} \frac{{f}\left({x}\right)−{f}\left({x}−{h}\right)}{−{h}}\: \\ $$$$\:\:\:=\:\frac{{dy}}{{dx}}\:,\:\mathrm{where}\:{y}\:=\:{f}\left({x}\right) \\ $$ Commented by Kunal12588 last…
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Question Number 75403 by TawaTawa last updated on 10/Dec/19 Answered by mind is power last updated on 10/Dec/19 $$=\left(\underset{\mathrm{m}\geqslant\mathrm{0}} {\sum}\frac{\mathrm{1}}{\left(\mathrm{2m}+\mathrm{1}\right)^{\mathrm{6}} }\right)\left(\underset{\mathrm{n}=\mathrm{1}} {\overset{+\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{\mathrm{n}+\mathrm{1}} }{\mathrm{4n}^{\mathrm{2}} −\mathrm{1}}\right)…
Question Number 140939 by iloveisrael last updated on 14/May/21 $$\:{x}^{\mathrm{sgn}\:\left({x}^{\mathrm{3}} −{x}\right)} \:=\:{x}^{\mathrm{2}} \:−\:\frac{\mathrm{4}}{\mathrm{9}}\: \\ $$ Answered by john_santu last updated on 14/May/21 $$\:{x}\:=\:−\frac{\mathrm{1}}{\mathrm{3}}\:\wedge\:{x}=\frac{\mathrm{4}}{\mathrm{3}} \\ $$…
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Question Number 9863 by richard last updated on 10/Jan/17 $$\mathrm{the}\:\mathrm{value}\:\mathrm{of}: \\ $$$$\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\frac{\mathrm{1}}{\mathrm{1}+\mathrm{tan}^{\mathrm{3}} {x}}\:{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9861 by Raja Naik last updated on 09/Jan/17 $$\mathrm{find}\:\:\lambda\:\mathrm{value}\:\mathrm{in}\:\lambda^{\mathrm{2}} −\mathrm{4}\lambda−\mathrm{13}=\mathrm{0} \\ $$ Answered by FilupSmith last updated on 09/Jan/17 $$\lambda=\frac{\mathrm{4}\pm\sqrt{\mathrm{16}+\mathrm{4}\left(\mathrm{13}\right)}}{\mathrm{2}} \\ $$$$\lambda=\frac{\mathrm{4}\pm\sqrt{\mathrm{68}}}{\mathrm{2}} \\…
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Question Number 9859 by Joel575 last updated on 09/Jan/17 Terms of Service Privacy Policy Contact: info@tinkutara.com