Question Number 75368 by vishalbhardwaj last updated on 10/Dec/19 $$ \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{interval}\:\mathrm{for}\:\mathrm{which}\:\mathrm{the}\:\mathrm{function} \\ $$$$\:{f}\left({x}\right)\:=\:{sinx}\:+\:{cosx},\:\mathrm{for}\:\:{x}\in\:\left[\mathrm{0},\:\mathrm{2}\pi\right] \\ $$$$\mathrm{is}\:\mathrm{strictly}\:\mathrm{inceasing}\:\mathrm{and}\:\mathrm{srictly}\:\mathrm{decreasing}\:? \\ $$ Commented by vishalbhardwaj last updated on 10/Dec/19…
Question Number 75366 by arkanmath7@gmail.com last updated on 10/Dec/19 $${i}\:{need}\:{the}\:{sol}\:{plz} \\ $$$${expansion}\:{the}\:{maclaurin}\:{series} \\ $$$${f}\left({z}\right)=\frac{{z}}{{z}^{\mathrm{4}} \:+\:\mathrm{9}}\:=\:\frac{{z}}{\mathrm{9}}\:×\frac{\mathrm{1}}{\mathrm{1}+\frac{{z}^{\mathrm{4}} }{\mathrm{9}}}\: \\ $$ Answered by Smail last updated on 10/Dec/19…
Question Number 9831 by tawakalitu last updated on 06/Jan/17 Answered by ridwan balatif last updated on 06/Jan/17 $$\mathrm{Area}_{\mathrm{AC}} =\mathrm{Area}_{\mathrm{ABC}} =\mathrm{Area}_{\mathrm{AB}} \\ $$$$\mathrm{Area}_{\mathrm{AC}} +\mathrm{Area}_{\mathrm{ABC}} +\mathrm{Area}_{\mathrm{AB}} =\mathrm{Area}\:\mathrm{of}\:\mathrm{circle}…
Question Number 140900 by bramlexs22 last updated on 14/May/21 $$\:\begin{cases}{\mathrm{x}^{\mathrm{3}} =\mathrm{xyz}+\mathrm{1}}\\{\mathrm{y}^{\mathrm{3}} =\mathrm{xyz}+\mathrm{2}}\\{\mathrm{z}^{\mathrm{3}} =\mathrm{xyz}−\mathrm{3}}\end{cases} \\ $$ Commented by bramlexs22 last updated on 14/May/21 $$\mathrm{Thank}\:\mathrm{all}\:\mathrm{master} \\ $$…
Question Number 75367 by 7005506270 last updated on 10/Dec/19 $$\frac{\mathrm{6}}{\mathrm{100}}×\mathrm{10}=? \\ $$ Commented by MJS last updated on 10/Dec/19 $$\mathrm{seriously}? \\ $$ Commented by Rio…
Question Number 9827 by tawakalitu last updated on 06/Jan/17 $$\left(\mathrm{7}\:−\:\mathrm{4}\sqrt{\mathrm{3}}\right)^{\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{4x}\:+\:\mathrm{3}} \:+\:\left(\mathrm{7}\:+\:\mathrm{4}\sqrt{\mathrm{3}}\right)^{\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{4x}\:+\:\mathrm{3}} \:=\:\mathrm{14} \\ $$ Answered by ridwan balatif last updated on 06/Jan/17 $$\mathrm{7}−\mathrm{4}\sqrt{\mathrm{3}}=\left(\mathrm{7}−\mathrm{4}\sqrt{\mathrm{3}}\right)\frac{\left(\mathrm{7}+\mathrm{4}\sqrt{\mathrm{3}}\right)}{\left(\mathrm{7}+\mathrm{4}\sqrt{\mathrm{3}}\right)}…
Question Number 140896 by bramlexs22 last updated on 14/May/21 $$\mathrm{the}\:\mathrm{function}\:\mathrm{f}\:\mathrm{with}\:\mathrm{variable}\:\mathrm{x} \\ $$$$\mathrm{satisfies}\:\mathrm{the}\:\mathrm{equation}\: \\ $$$$\mathrm{x}^{\mathrm{2}} \:\mathrm{f}\:'\left(\mathrm{x}\right)\:+\mathrm{2x}\:\mathrm{f}\left(\mathrm{x}\right)\:=\:\mathrm{arctan}\:\mathrm{x}\:\mathrm{for}\: \\ $$$$\mathrm{0}\:<\:\mathrm{arctan}\:\mathrm{x}\:<\frac{\pi}{\mathrm{2}}\:\mathrm{and}\:\mathrm{f}\left(\mathrm{1}\right)=\frac{\pi}{\mathrm{4}}. \\ $$$$\mathrm{find}\:\mathrm{f}\left(\mathrm{x}\right). \\ $$ Answered by EDWIN88 last…
Question Number 140899 by ajfour last updated on 14/May/21 Commented by ajfour last updated on 14/May/21 Commented by ajfour last updated on 14/May/21 $${construction}\:{method}\:{please}.. \\…
Question Number 75360 by crystal0207 last updated on 10/Dec/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9824 by j.masanja06@gmail.com last updated on 06/Jan/17 Answered by sandy_suhendra last updated on 06/Jan/17 $$\left(\mathrm{i}\right) \\ $$$$\mathrm{AP}\:: \\ $$$$\mathrm{P}=\mathrm{a}−\mathrm{b} \\ $$$$\mathrm{2Q}=\mathrm{a}\:\Rightarrow\:\mathrm{Q}=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{a} \\ $$$$\mathrm{R}=\mathrm{a}+\mathrm{b}…