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Author: Tinku Tara

The-wall-of-mr-nelsons-bathroom-is-covered-with-1200-square-tiles-eah-of-length-24cm-How-many-square-tiles-of-sides-length-24cm-would-be-needed-to-cover-the-same-wall-

Question Number 75338 by otchereabdullai@gmail.com last updated on 10/Dec/19 $$\mathrm{The}\:\mathrm{wall}\:\mathrm{of}\:\mathrm{mr}\:\mathrm{nelsons}\:\mathrm{bathroom}\:\mathrm{is} \\ $$$$\mathrm{covered}\:\mathrm{with}\:\mathrm{1200}\:\mathrm{square}\:\mathrm{tiles}\:\mathrm{eah}\:\mathrm{of}\: \\ $$$$\mathrm{length}\:\mathrm{24cm}.\:\mathrm{How}\:\mathrm{many}\:\mathrm{square}\:\mathrm{tiles}\: \\ $$$$\mathrm{of}\:\mathrm{sides}\:\mathrm{length}\:\mathrm{24cm}\:\mathrm{would}\:\mathrm{be}\:\mathrm{needed}\:\mathrm{to}\: \\ $$$$\mathrm{cover}\:\mathrm{the}\:\mathrm{same}\:\mathrm{wall}. \\ $$ Commented by MJS last updated…

A-water-flows-from-a-tap-into-an-empty-cylindrical-jar-at-rate-of-23211cm-3-per-secons-At-what-time-will-the-tap-fill-the-cylinder-with-volume-of-6011cm-3-

Question Number 75339 by otchereabdullai@gmail.com last updated on 10/Dec/19 $$\mathrm{A}\:\mathrm{water}\:\mathrm{flows}\:\mathrm{from}\:\mathrm{a}\:\mathrm{tap}\:\mathrm{into}\:\mathrm{an}\:\mathrm{empty} \\ $$$$\mathrm{cylindrical}\:\mathrm{jar}\:\mathrm{at}\:\mathrm{rate}\:\mathrm{of}\:\:\mathrm{23211cm}^{\mathrm{3}} \:\mathrm{per} \\ $$$$\mathrm{secons}.\:\mathrm{At}\:\mathrm{what}\:\mathrm{time}\:\mathrm{will}\:\mathrm{the}\:\mathrm{tap}\:\mathrm{fill}\: \\ $$$$\mathrm{the}\:\mathrm{cylinder}\:\mathrm{with}\:\mathrm{volume}\:\mathrm{of}\:\mathrm{6011cm}^{\mathrm{3}} . \\ $$ Commented by MJS last updated…

the-velocities-of-air-particles-above-and-below-the-wing-of-an-aircraft-speeding-down-the-runway-at-a-given-instant-are-210m-s-and-200m-s-respectively-If-the-density-of-air-is-1-2kg-m-3-what-is-

Question Number 140869 by jlewis last updated on 13/May/21 $${the}\:\mathrm{velocities}\:\mathrm{of}\:\mathrm{air}\:\mathrm{particles}\: \\ $$$$\mathrm{above}\:\mathrm{and}\:\mathrm{below}\:\mathrm{the}\:\mathrm{wing}\:\mathrm{of}\:\mathrm{an}\:\mathrm{aircraft} \\ $$$$\:\mathrm{speeding}\:\mathrm{down}\:\mathrm{the}\:\mathrm{runway}\:\mathrm{at}\:\mathrm{a} \\ $$$$\:\mathrm{given}\:\mathrm{instant} \\ $$$$\mathrm{are}\:\mathrm{210m}/\mathrm{s}\:\mathrm{and}\:\mathrm{200m}/\mathrm{s}\: \\ $$$$\mathrm{respectively}.\mathrm{If}\:\mathrm{the}\:\mathrm{density}\:\mathrm{of}\:\mathrm{air}\:\mathrm{is}\: \\ $$$$\mathrm{1}.\mathrm{2kg}/\mathrm{m}^{\mathrm{3}} ,\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{pressure} \\ $$$$\:\mathrm{difference}\:\mathrm{between}\:\mathrm{the}\:\mathrm{upper}\:\mathrm{and}…

Ocean-waves-are-observed-to-travel-along-the-water-surface-during-a-developing-storm-A-Coast-Guard-weather-station-observes-that-there-is-a-vertical-distance-from-high-point-to-low-point-of-4-6-m

Question Number 140870 by jlewis last updated on 13/May/21 $${O}\mathrm{cean}\:\mathrm{waves}\:\mathrm{are}\:\mathrm{observed}\:\mathrm{to} \\ $$$$\mathrm{travel}\:\mathrm{along}\:\mathrm{the}\:\mathrm{water}\:\mathrm{surface} \\ $$$$\:\mathrm{during}\:\mathrm{a}\:\mathrm{developing}\:\mathrm{storm}. \\ $$$$\mathrm{A}\:\mathrm{Coast}\:\mathrm{Guard}\:\mathrm{weather}\:\mathrm{station} \\ $$$$\:\mathrm{observes}\:\mathrm{that}\:\mathrm{there}\:\mathrm{is}\:\mathrm{a}\:\mathrm{vertical}\: \\ $$$$\mathrm{distance}\:\mathrm{from}\:\mathrm{high}\:\mathrm{point}\:\mathrm{to}\:\mathrm{low} \\ $$$$\:\mathrm{point}\:\mathrm{of}\:\mathrm{4}.\mathrm{6}\:\mathrm{meters}\:\mathrm{and}\:\mathrm{horizontal} \\ $$$$\mathrm{distance}\:\mathrm{of}\:\mathrm{8}.\mathrm{6}\:\mathrm{meters}\:\mathrm{between}\: \\…

0-1-ln-2-ln-1-x-2-1-x-dx-

Question Number 140866 by liberty last updated on 13/May/21 $$\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\frac{\mathrm{ln}\:\mathrm{2}−\mathrm{ln}\:\left(\mathrm{1}+\mathrm{x}^{\mathrm{2}} \right)}{\mathrm{1}−\mathrm{x}}\:\mathrm{dx}\:=?\: \\ $$ Answered by mindispower last updated on 15/May/21 $$=\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\int_{\mathrm{0}} ^{{x}}…

Question-75329

Question Number 75329 by lalitchand last updated on 10/Dec/19 Answered by $@ty@m123 last updated on 10/Dec/19 $${R}=\frac{{abc}}{\mathrm{4}\bigtriangleup} \\ $$$${where}, \\ $$$$\bigtriangleup=\sqrt{{s}\left({s}−{a}\right)\left({s}−{b}\right)\left({s}−{c}\right)} \\ $$ Terms of…