Question Number 9765 by tawakalitu last updated on 01/Jan/17 $$\mathrm{The}\:\mathrm{gravitational}\:\mathrm{force}\:\mathrm{of}\:\mathrm{attraction}\:\mathrm{between} \\ $$$$\mathrm{two}\:\mathrm{spherical}\:\mathrm{bodies}\:\mathrm{having}\:\mathrm{equal}\:\mathrm{densities} \\ $$$$\mathrm{is}\:\mathrm{increase}\:\mathrm{by}\:−−−−−\:? \\ $$$$\mathrm{if}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{each}\:\mathrm{of}\:\mathrm{the}\:\mathrm{bodies}\:\mathrm{is}\:\mathrm{doubled}. \\ $$ Answered by ridwan balatif last updated on…
Question Number 140838 by mr W last updated on 13/May/21 Commented by mr W last updated on 13/May/21 $${solution}\:{to}\:{Q}\mathrm{140785} \\ $$ Commented by mr W…
Question Number 75301 by vishalbhardwaj last updated on 09/Dec/19 $$\mathrm{Find}\:\mathrm{S}_{\mathrm{n}} \:\mathrm{and}\:\mathrm{S}_{\infty} \:\mathrm{of}\:\mathrm{the}\:\mathrm{series}\::\:\frac{\mathrm{1}}{\mathrm{1}.\mathrm{2}.\mathrm{3}.\mathrm{4}}\:+\:\frac{\mathrm{1}}{\mathrm{2}.\mathrm{3}.\mathrm{4}.\mathrm{5}}\:+\:\frac{\mathrm{1}}{\mathrm{3}.\mathrm{4}.\mathrm{5}.\mathrm{6}}\:+\:.\:.\:. \\ $$ Commented by vishalbhardwaj last updated on 09/Dec/19 $$\mathrm{please}\:\mathrm{solve}\:\mathrm{this} \\ $$ Commented…
Question Number 9764 by tawakalitu last updated on 01/Jan/17 Answered by sandy_suhendra last updated on 01/Jan/17 Commented by sandy_suhendra last updated on 01/Jan/17 $$\mathrm{OM}=\mathrm{OK}=\mathrm{5}\:\mathrm{cm} \\…
Question Number 140833 by liberty last updated on 13/May/21 $$\mathrm{Determine}\:\mathrm{if}\:\mathrm{the}\:\mathrm{series}\:\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\mathrm{a}_{\mathrm{n}} \\ $$$$\mathrm{defined}\:\mathrm{by}\:\mathrm{the}\:\:\mathrm{formula}\:\mathrm{converges}\:\mathrm{or} \\ $$$$\mathrm{diverges}\:.\:\mathrm{a}_{\mathrm{1}} =\:\mathrm{4}\:,\:\mathrm{a}_{\mathrm{n}+\mathrm{1}} \:=\:\frac{\mathrm{10}+\mathrm{sin}\:\mathrm{n}}{\mathrm{n}}.\:\mathrm{a}_{\mathrm{n}} \\ $$ Commented by liberty last updated…
Question Number 75299 by 21042004 last updated on 09/Dec/19 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{this}? \\ $$$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left[\:\frac{\mathrm{1}}{\mathrm{10}^{{n}} }\:\right] \\ $$$$\left.\mathrm{a}\right)\:\mathrm{0}.\mathrm{00}…\mathrm{001} \\ $$$$\left.\mathrm{b}\right)\:\mathrm{0} \\ $$$$\left.\mathrm{c}\right)\:\mathrm{uknown} \\ $$ Commented by 21042004…
Question Number 75296 by ajfour last updated on 09/Dec/19 Commented by ajfour last updated on 09/Dec/19 $${If}\:{perimeter}\:{of}\:\bigtriangleup{PQR}\:{is}\:{p},\:{find} \\ $$$${maximum}\:{area}\:{of}\:\bigtriangleup{PQR}\:{in} \\ $$$${terms}\:{of}\:{a},{b},{c},{p}.\:\:\:\left({p}<{a}+{b}+{c}\right)\: \\ $$ Commented by…
Question Number 140834 by greg_ed last updated on 13/May/21 $$\boldsymbol{\mathrm{hi}},\:\boldsymbol{\mathrm{sirs}}\:! \\ $$$$\boldsymbol{\mathrm{please}},\:\boldsymbol{\mathrm{how}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{thing}}\:\boldsymbol{\mathrm{below}}\:\left(\boldsymbol{{a}}\:\in\:\mathbb{R}\right)\: \\ $$$$\:\:\:\:\:\:\:\:\begin{cases}{\boldsymbol{{x}}_{\mathrm{1}} −\boldsymbol{{x}}_{\mathrm{2}} \:=\:\boldsymbol{{a}}}\\{\boldsymbol{{x}}_{\mathrm{2}} −\boldsymbol{{x}}_{\mathrm{3}} \:=\:\mathrm{2}\boldsymbol{{a}}}\\{……………..}\\{……………..}\\{…………….}\\{\boldsymbol{{x}}_{\boldsymbol{{n}}−\mathrm{1}} −\:\boldsymbol{{x}}_{\boldsymbol{{n}}} \:=\:\left(\boldsymbol{{n}}−\mathrm{1}\right)\boldsymbol{{a}}}\\{\boldsymbol{{x}}_{\mathrm{1}} +\:\boldsymbol{{x}}_{\mathrm{2}} +\:…\:+\:\boldsymbol{{x}}_{\boldsymbol{{n}}−\mathrm{1}} +\:\boldsymbol{{x}}_{\boldsymbol{{n}}} \:=\:\boldsymbol{{na}}}\end{cases} \\…
Question Number 140829 by jlewis last updated on 13/May/21 $${factorise}\:\mathrm{5}{x}^{\mathrm{2}{m}} \mathrm{8}{x}^{{m}} +\mathrm{8} \\ $$ Answered by Rasheed.Sindhi last updated on 13/May/21 $$\:\mathrm{5}{x}^{\mathrm{2}{m}} \mathrm{8}{x}^{{m}} +\mathrm{8} \\…
Question Number 140828 by jlewis last updated on 13/May/21 $$\mathrm{factorise}\:\mathrm{3k}^{\mathrm{2}} \:+\mathrm{2kh}−\mathrm{8h}^{\mathrm{2}} \\ $$ Answered by liberty last updated on 13/May/21 $$\left(\mathrm{3k}\:\:−\mathrm{4h}\:\:\right)\left(\mathrm{k}+\mathrm{2h}\right) \\ $$ Commented by…