Question Number 75272 by peter frank last updated on 09/Dec/19 $$\left.{a}\right)\:{If}\:{z}=\mathrm{1}+{i}\sqrt{\mathrm{3}}\:{prove}\:{that} \\ $$$${prove}\:{that} \\ $$$${z}^{\mathrm{14}} =\mathrm{2}^{\mathrm{13}} \left(−\mathrm{1}+{i}\sqrt{\mathrm{3}}\:\right) \\ $$$$ \\ $$$$\left.{b}\right){prove}\:{that}\:{in}\:{triangle}\:{ABC} \\ $$$${a}^{\mathrm{2}} −\left({b}−{c}\right)^{\mathrm{2}} \mathrm{cos}\:^{\mathrm{2}}…
Question Number 140810 by mathsuji last updated on 12/May/21 $${Find}\:{the}\:{natural}\:{value}\:{of}\:\boldsymbol{{x}}\:{that} \\ $$$${satisfies}\:{the}\:{equation}: \\ $$$$\frac{\mathrm{1}}{\mathrm{6}\centerdot\mathrm{7}}\:+\:\frac{\mathrm{1}}{\mathrm{7}\centerdot\mathrm{8}}\:+\:\frac{\mathrm{1}}{\mathrm{8}\centerdot\mathrm{9}}\:+…+\:\frac{\mathrm{1}}{{x}\centerdot\left({x}+\mathrm{1}\right)}\:=\:\frac{\mathrm{1}}{\mathrm{12}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 140805 by jlewis last updated on 12/May/21 $${find}\:{x}\:\mathrm{2cosh}\:\mathrm{2}{x}+\mathrm{10sinh}\:\mathrm{2}{x}=\mathrm{5} \\ $$ Answered by Ar Brandon last updated on 12/May/21 $$\mathrm{2cosh2x}+\mathrm{10sinh2x}=\mathrm{5} \\ $$$$\mathrm{e}^{\mathrm{2x}} +\mathrm{e}^{−\mathrm{2x}} +\mathrm{5}\left(\mathrm{e}^{\mathrm{2x}}…
Question Number 9734 by geovane10math last updated on 29/Dec/16 $${What}\:{is}\:{the}\:{group}\:\:\:\:\mathbb{Z}/\boldsymbol{{n}}\mathbb{Z}\:?? \\ $$ Commented by FilupSmith last updated on 29/Dec/16 $$\mathbb{Z}\:\mathrm{is}\:\mathrm{all}\:\mathrm{whole}\:\mathrm{numbers}. \\ $$$$\mathrm{e}.\mathrm{g}.\:\forall{x}\in\mathbb{R}\Rightarrow\lfloor{x}\rfloor\in\mathbb{Z} \\ $$$$\: \\…
Question Number 75268 by aliesam last updated on 09/Dec/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9732 by tawakalitu last updated on 29/Dec/16 $$\mathrm{Find}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{an}\:\mathrm{ellipse}\:\mathrm{whose}\:\mathrm{major}\:\mathrm{axis} \\ $$$$\mathrm{is}\:\mathrm{vertical},\:\mathrm{with}\:\mathrm{the}\:\mathrm{center}\:\mathrm{located}\:\left(−\:\mathrm{1},\:\mathrm{3}\right) \\ $$$$\mathrm{at}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{the}\:\mathrm{center}\:\mathrm{and}\:\mathrm{one}\: \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{covertices}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{4},\:\mathrm{and}\:\mathrm{the}\:\mathrm{distance} \\ $$$$\mathrm{between}\:\mathrm{the}\:\mathrm{center}\:\mathrm{and}\:\mathrm{one}\:\mathrm{of}\:\mathrm{the}\:\mathrm{vertices}\: \\ $$$$\mathrm{equal}\:\mathrm{to}\:\mathrm{6}. \\ $$ Answered by sandy_suhendra…
Question Number 9731 by tawakalitu last updated on 29/Dec/16 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{asymptotes}\:\mathrm{of}\:\mathrm{the}\:\mathrm{hypebola}\:\mathrm{whose} \\ $$$$\mathrm{equation}\:\mathrm{is}\:\mathrm{given}\:\mathrm{by}. \\ $$$$\frac{\mathrm{x}}{\mathrm{24}}\:−\:\frac{\mathrm{y}}{\mathrm{29}}\:=\:\mathrm{1} \\ $$ Commented by geovane10math last updated on 29/Dec/16 $$\frac{\mathrm{29}{x}\:−\:\mathrm{24}{y}}{\mathrm{696}}\:=\:\mathrm{1} \\…
Question Number 75267 by aliesam last updated on 09/Dec/19 Commented by mind is power last updated on 09/Dec/19 $$\mathrm{let}\:\mathrm{f}\left(\mathrm{x}\right)=\frac{\sqrt{\mathrm{1}+\mathrm{sin}\left(\mathrm{x}\right)}+\sqrt{\mathrm{1}−\mathrm{sin}\left(\mathrm{x}\right)}}{\:\sqrt{\mathrm{1}+\mathrm{sin}\left(\mathrm{x}\right)}−\sqrt{\mathrm{1}−\mathrm{sin}\left(\mathrm{x}\right)}} \\ $$$$\mathrm{sin}\left(\mathrm{x}\right)=\mathrm{2sin}\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\mathrm{cos}\left(\frac{\mathrm{x}}{\mathrm{2}}\right) \\ $$$$\mathrm{1}\underset{−} {+}\mathrm{sin}\left(\mathrm{x}\right)=\left(\mathrm{cos}\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\underset{−} {+}\mathrm{sin}\left(\frac{\mathrm{x}}{\mathrm{2}}\right)\right)^{\mathrm{2}}…
Question Number 140803 by jlewis last updated on 12/May/21 Answered by Ar Brandon last updated on 12/May/21 $$\mathrm{tany}=\frac{\mathrm{2x}}{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}\:,\:\mathrm{1}+\mathrm{tan}^{\mathrm{2}} \mathrm{y}=\mathrm{sec}^{\mathrm{2}} \mathrm{y} \\ $$$$\Rightarrow\mathrm{cosy}=\pm\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+\mathrm{tan}^{\mathrm{2}} \mathrm{y}}}=\pm\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+\left(\frac{\mathrm{2x}}{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}\right)^{\mathrm{2}}…
Question Number 75262 by chess1 last updated on 09/Dec/19 Commented by chess1 last updated on 09/Dec/19 $$\mathrm{Sir}\:\boldsymbol{\mathrm{mind}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{power}} \\ $$$$\mathrm{Sir}\:\boldsymbol{\mathrm{mathmax}}\:\mathrm{and}\:\boldsymbol{\mathrm{Mjs}}\:\:\mathrm{and}\:\:\boldsymbol{\mathrm{W}}\:\:\:\boldsymbol{\mathrm{solution}}\:\boldsymbol{\mathrm{please}} \\ $$ Commented by chess1 last…