Question Number 9717 by konen last updated on 28/Dec/16 $$\frac{\mathrm{0}.\mathrm{b}\overset{−} {\mathrm{a}}+\mathrm{0}.\mathrm{a}\overset{−} {\mathrm{b}}}{\frac{\mathrm{1}}{\mathrm{ab}−\mathrm{ba}}}=\mathrm{3}\:\Rightarrow\:\mathrm{a}^{\mathrm{2}\:} −\:\mathrm{b}^{\mathrm{2}\:} =? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 140785 by mathdanisur last updated on 12/May/21 $${P}-{intersection}\:{point}\:{of}\:{bimedians}\:{in} \\ $$$${ABCD}-{convexe}\:{quadrilateral}\:{with} \\ $$$${a};{b};{c};{d}-{sides},\:{e};{f}-{diagonals}, \\ $$$${E}-{point}\:{in}\:{plane},\:{x};{y};{z};{t}-{distances} \\ $$$${from},\:{E}-{to}\:{A};{B};{C};{D}.\:{Prove}\:{that}… \\ $$$$\frac{\mathrm{1}}{\mathrm{4}}\left({a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} +{e}^{\mathrm{2}} +{f}^{\mathrm{2}} \right)+\mathrm{4}{PE}^{\mathrm{2}}…
Question Number 9715 by tawakalitu last updated on 28/Dec/16 $$\mathrm{Vector}\:\overset{\rightarrow} {\mathrm{A}}\:\mathrm{of}\:\mathrm{magnitude}\:\mathrm{20}\:\mathrm{unit},\:\mathrm{lies}\:\mathrm{in}\:\mathrm{the}\: \\ $$$$\mathrm{direction}\:\mathrm{45}°\mathrm{S}\:\mathrm{of}\:\mathrm{E}\:\mathrm{while}\:\mathrm{vector}\:\overset{\rightarrow} {\mathrm{B}}\:\mathrm{of}\:\mathrm{magnitude} \\ $$$$\mathrm{30}\:\mathrm{units}\:\mathrm{in}\:\mathrm{the}\:\mathrm{direction}\:\mathrm{60}°\mathrm{W}\:\mathrm{of}\:\mathrm{N}. \\ $$$$\mathrm{calculate}\:\mathrm{the}\:\mathrm{scaler}\:\mathrm{product}\:\:\overset{\rightarrow} {\mathrm{A}}\centerdot\overset{\rightarrow} {\mathrm{B}} \\ $$ Answered by sandy_suhendra…
Question Number 140784 by ajfour last updated on 12/May/21 $${Let}\:{the}\:{i}-{j}\:{plane}\:{be}\:{the}\:{complex} \\ $$$$\:{plane},\:{with}\:{basic}\:{operations} \\ $$$$\:\:{ij}=−{i} \\ $$$$\:\:{ji}=−{j} \\ $$$$\:\:{i}^{\mathrm{2}} =−\mathrm{1} \\ $$$$\:\:{j}^{\mathrm{2}} =−\mathrm{1} \\ $$$${z}={r}+{xi}+{yj}\:\:\:\:{w}={s}+{pi}+{qj} \\…
Question Number 75248 by cesar.marval.larez@gmail.com last updated on 08/Dec/19 Commented by mathmax by abdo last updated on 14/Dec/19 $$\frac{{d}}{{dx}}\left(\frac{{e}^{{x}} }{\mathrm{1}+{x}}\right)\:=\frac{{e}^{{x}} \left(\mathrm{1}+{x}\right)−{e}^{{x}} ×\mathrm{1}}{\left(\mathrm{1}+\mathrm{x}\right)^{\mathrm{2}} }\:=\frac{\mathrm{xe}^{\mathrm{x}} }{\left(\mathrm{1}+\mathrm{x}\right)^{\mathrm{2}} }\:\Rightarrow…
Question Number 140786 by 676597498 last updated on 12/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9709 by tawakalitu last updated on 28/Dec/16 $$\mathrm{A}\:\mathrm{vertical}\:\mathrm{pole}\:\mathrm{3m}\:\mathrm{high}\:\mathrm{is}\:\mathrm{2m}\:\mathrm{south}\:\mathrm{of}\:\mathrm{a}\:\mathrm{wall} \\ $$$$\mathrm{which}\:\mathrm{runs}\:\mathrm{directly}\:\mathrm{east}\:\mathrm{and}\:\mathrm{west}.\:\mathrm{The}\:\mathrm{sun} \\ $$$$\mathrm{is}\:\mathrm{south}\:\mathrm{west}\:\mathrm{at}\:\mathrm{an}\:\mathrm{elevation}\:\mathrm{of}\:\mathrm{35}°. \\ $$$$\mathrm{Find}\:\mathrm{to}\:\mathrm{the}\:\mathrm{nearest}\:\mathrm{centimeter}\:\mathrm{the}\:\mathrm{height}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{shadow}\:\mathrm{of}\:\mathrm{the}\:\mathrm{pole}\:\mathrm{on}\:\mathrm{the}\:\mathrm{wall}. \\ $$ Answered by mrW last updated…
Question Number 75242 by peter frank last updated on 08/Dec/19 $${Find}\:{th}\:{greatest}\:{coefficients} \\ $$$${in}\:{the}\:{expansion}\:{of} \\ $$$$\left(\mathrm{3}{a}+\mathrm{5}{b}\right)^{\mathrm{18}} \\ $$$$ \\ $$$$\left.\mathrm{2}\right){If}\:{three}\:{consecutive}\: \\ $$$${coefficient}\:{of}\:\left(\mathrm{1}+{x}\right)^{{n}} \:{are}\:\mathrm{28},\mathrm{56},\mathrm{70}. \\ $$$${find}\:{the}\:{value}\:{of}\:{n} \\…
Question Number 140779 by 676597498 last updated on 12/May/21 $$\begin{cases}{\mathrm{7}{x}\equiv\mathrm{3}\left({mod}\mathrm{5}\right)}\\{\mathrm{5}{x}\equiv\mathrm{3}\left({mod}\mathrm{9}\right)}\end{cases} \\ $$$${solve}\:{for}\:{x} \\ $$ Commented by 676597498 last updated on 12/May/21 $${pls} \\ $$ Answered…
Question Number 9704 by tawakalitu last updated on 26/Dec/16 Answered by geovane10math last updated on 26/Dec/16 Commented by tawakalitu last updated on 28/Dec/16 $$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\…