Question Number 140709 by mathdanisur last updated on 11/May/21 $$\frac{{z}^{\mathrm{999}} −\mathrm{1}}{\left({z}^{\mathrm{2}} +\mathrm{1}\right)\centerdot\left({z}^{\mathrm{2}} +{z}+\mathrm{1}\right)} \\ $$$${find}\:{the}\:{sum}\:{of}\:{the}\:{coefficientes}\:{of} \\ $$$${the}\:{polynomial}\:{obtained}\:{bh}\:{dividing} \\ $$$${the}\:{expression}\:{by}\:{the}\:{polynomial}… \\ $$ Commented by mr W…
Question Number 140708 by mathocean1 last updated on 11/May/21 $$\mathrm{Given}\:\mathrm{an}\:\mathrm{Elipsis}\:\mathrm{in}\:\left(\mathrm{O};\overset{\rightarrow} {\mathrm{i}};\overset{\rightarrow} {\mathrm{j}}\right) \\ $$$$\left(\mathrm{E}\right):\:\frac{{x}^{\mathrm{2}} }{\mathrm{1}/\mathrm{4}}+\frac{{y}^{\mathrm{2}} }{\mathrm{1}}=\mathrm{1}.\: \\ $$$${W}\mathrm{e}\:\mathrm{admit}\:\mathrm{that}\:\mathrm{it}\:\mathrm{image}\:\mathrm{by}\:\mathrm{the}\:\mathrm{transformation}\: \\ $$$$\mathrm{f}\::\:\begin{cases}{{x}'=\sqrt{\mathrm{2}}\left({x}+{y}\right)}\\{{y}'=\sqrt{\mathrm{2}}\left(−{x}+{y}\right)\:}\end{cases} \\ $$$${is}\:{an}\:{elipsis}\:\left({E}'\right):\:\mathrm{5}{x}^{\mathrm{2}} +\mathrm{5}{y}^{\mathrm{2}} +\mathrm{6}{xy}−\mathrm{8}=\mathrm{0} \\…
Question Number 75175 by Rio Michael last updated on 08/Dec/19 $${solve}\:{the}\:{differential}\:{equation} \\ $$$$\:\left({x}^{\mathrm{2}} −\mathrm{1}\right)\frac{{dy}}{{dx}}\:+\:\mathrm{2}{y}\:=\:\mathrm{0}\:{when}\:{y}=\mathrm{3}\:{and}\:{x}=\:\mathrm{2},{expressing} \\ $$$${your}\:{answer}\:{in}\:{the}\:{form}\:{y}={f}\left({x}\right) \\ $$ Answered by Kunal12588 last updated on 08/Dec/19…
Question Number 9637 by tawakalitu last updated on 22/Dec/16 $$\mathrm{A}\:\mathrm{body}\:\mathrm{starts}\:\mathrm{from}\:\mathrm{rest}\:\mathrm{and}\:\mathrm{move}\:\mathrm{with}\: \\ $$$$\mathrm{uniform}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{6m}/\mathrm{s}^{\mathrm{2}} .\:\:\mathrm{what}\: \\ $$$$\mathrm{distance}\:\mathrm{does}\:\mathrm{it}\:\mathrm{covered}\:\mathrm{in}\:\mathrm{the}\:\mathrm{3rd}\:\mathrm{seconds}. \\ $$ Answered by ridwan balatif last updated on 22/Dec/16…
Question Number 75173 by liki last updated on 08/Dec/19 Commented by liki last updated on 08/Dec/19 $$…{i}\:{need}\:{help}\:{plz} \\ $$ Answered by mind is power last…
Question Number 9636 by tawakalitu last updated on 22/Dec/16 $$\mathrm{The}\:\mathrm{distance}\:\mathrm{x}\:\mathrm{m}\:\mathrm{have}\:\mathrm{used}\:\mathrm{by}\:\mathrm{a}\:\mathrm{particle}\:\mathrm{in} \\ $$$$\mathrm{time}\:\mathrm{t}\:\mathrm{sec}\:\mathrm{is}\:\mathrm{described}\:\mathrm{by}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\mathrm{x}\:=\:\mathrm{10}\:+\:\mathrm{12t}^{\mathrm{2}} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{average}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{particle}\:\mathrm{between} \\ $$$$\mathrm{the}\:\mathrm{interval}\:\mathrm{t}\:=\:\mathrm{2}\:\mathrm{sec}\:\mathrm{and}\:\mathrm{t}\:=\:\mathrm{5}\:\mathrm{sec} \\ $$ Commented by ridwan balatif last…
Question Number 9635 by tawakalitu last updated on 22/Dec/16 $$\mathrm{A}\:\mathrm{body}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{20g}\:\mathrm{performs}\:\mathrm{simple}\:\mathrm{harmonic} \\ $$$$\mathrm{motion}\:\mathrm{at}\:\mathrm{a}\:\mathrm{frequency}\:\mathrm{of}\:\mathrm{5Hz},\:\mathrm{at}\:\mathrm{a}\:\mathrm{distance} \\ $$$$\mathrm{of}\:\mathrm{10cm}\:\mathrm{from}\:\mathrm{the}\:\mathrm{mean}\:\mathrm{position}.\:\mathrm{its}\:\mathrm{velocity} \\ $$$$\mathrm{is}\:\mathrm{200cm}/\mathrm{s}.\:\:\mathrm{calculate} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{Maximum}\:\mathrm{displacement}\:\mathrm{from}\:\mathrm{the}\:\mathrm{mean} \\ $$$$\mathrm{position} \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{Maximum}\:\mathrm{velocity} \\ $$$$\left(\mathrm{iii}\right)\:\mathrm{Maximum}\:\mathrm{potential}\:\mathrm{energy}. \\…
Question Number 75166 by jagannath.02 last updated on 08/Dec/19 Answered by peter frank last updated on 08/Dec/19 $${i}\:{think}\:{option}\:\mathrm{1}\rightarrow\rightarrow\:{becouse}\:{the}\:{system}\:{undergo} \\ $$$${isothermal}\:{process} \\ $$ Terms of Service…
Question Number 140703 by rs4089 last updated on 11/May/21 Answered by Dwaipayan Shikari last updated on 11/May/21 $${x}={t}+\mathrm{1} \\ $$$$\int_{\mathrm{1}} ^{\infty} \frac{{dt}}{\left({t}+\mathrm{1}\right)^{{p}+\mathrm{1}} {t}^{{q}} }\:\:\:{t}=\frac{\mathrm{1}}{{g}} \\…
Question Number 140702 by help last updated on 11/May/21 Answered by liberty last updated on 12/May/21 $$\left(\mathrm{3}\right)\:\frac{\mathrm{y}^{\cancel{\mathrm{2}}} }{\mathrm{2}}\:=−\mathrm{x}\cancel{\mathrm{y}}\:\frac{\mathrm{dy}}{\mathrm{dx}} \\ $$$$\Rightarrow\:−\frac{\mathrm{dx}}{\mathrm{x}}\:=\:\frac{\mathrm{2dy}}{\mathrm{y}} \\ $$$$\Rightarrow−\mathrm{ln}\:\mathrm{x}\:+\:\mathrm{c}\:=\:\mathrm{2ln}\:\mathrm{y}\: \\ $$$$\Rightarrow\:−\mathrm{ln}\:\mathrm{Cx}\:=\:\mathrm{ln}\:\mathrm{y}^{\mathrm{2}} \\…