Question Number 9627 by ridwan balatif last updated on 21/Dec/16 Commented by ridwan balatif last updated on 21/Dec/16 Commented by sou1618 last updated on 22/Dec/16…
Question Number 140698 by BHOOPENDRA last updated on 11/May/21 Commented by BHOOPENDRA last updated on 11/May/21 $${B}\:{part}\:{Mr}.{W}\: \\ $$ Answered by mr W last updated…
Question Number 75158 by peter frank last updated on 08/Dec/19 Answered by mr W last updated on 08/Dec/19 $${let}\:{u}=\sqrt{\frac{\mathrm{7}{ga}}{\mathrm{2}}} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}{mu}^{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{2}}{mv}^{\mathrm{2}} +{mga}\left(\mathrm{1}−\mathrm{cos}\:\theta\right) \\ $$$$\Rightarrow{v}^{\mathrm{2}}…
Question Number 9623 by tawakalitu last updated on 21/Dec/16 $$\mathrm{Evaluate}\::\:\int_{\mathrm{4}} ^{\mathrm{5}.\mathrm{2}} \:\mathrm{ln}\left(\mathrm{x}\right)\:\mathrm{dx}\:\: \\ $$$$\mathrm{using}\:\mathrm{trapezoidal}\:\mathrm{rule}.\:\mathrm{take}\:\mathrm{h}\:=\:\mathrm{0}.\mathrm{2} \\ $$ Commented by sandy_suhendra last updated on 21/Dec/16 Answered by…
Question Number 140695 by Chhing last updated on 11/May/21 $$\mathrm{Differential}\:\mathrm{system} \\ $$$$\begin{cases}{\mathrm{x}'+\mathrm{x}−\mathrm{y}−\mathrm{z}=\mathrm{ae}^{\mathrm{2t}} }\\{\mathrm{y}'+\mathrm{y}−\mathrm{z}−\mathrm{x}=\mathrm{be}^{\mathrm{2t}} }\\{\mathrm{z}'+\mathrm{z}−\mathrm{x}−\mathrm{y}=\mathrm{ce}^{\mathrm{2t}} }\end{cases} \\ $$$$\:\mathrm{a},\mathrm{b},\mathrm{c}\:\mathrm{are}\:\mathrm{constants} \\ $$$$\mathrm{help}\:\mathrm{me} \\ $$ Answered by mr W…
Question Number 75156 by chess1 last updated on 08/Dec/19 Answered by $@ty@m123 last updated on 08/Dec/19 $$\mathrm{2}{x}+\mathrm{3}{x}+\left(\mathrm{360}−\mathrm{230}\right)=\mathrm{180} \\ $$$$\Rightarrow\mathrm{5}{x}+\mathrm{130}=\mathrm{180} \\ $$$$\Rightarrow{x}=\mathrm{10}\:…..\left(\left(\mathrm{1}\right)\right. \\ $$$$\mathrm{58}+\mathrm{2}\left(\mathrm{20}+{y}\right)=\mathrm{180} \\ $$$$\mathrm{40}+\mathrm{2}{y}=\mathrm{122}…
Question Number 140688 by mohammad17 last updated on 11/May/21 Commented by mohammad17 last updated on 11/May/21 $${help}\:{me} \\ $$ Answered by TheSupreme last updated on…
Question Number 9617 by tawakalitu last updated on 20/Dec/16 Commented by sou1618 last updated on 21/Dec/16 $${m}=\sqrt{\frac{\mathrm{1}}{\mathrm{2}}}×\sqrt{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\frac{\mathrm{1}}{\mathrm{2}}}}×\sqrt{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\frac{\mathrm{1}}{\mathrm{2}}}}}×… \\ $$$$\mathrm{put}\:{a}_{{n}} :\:{a}_{\mathrm{1}} =\sqrt{\frac{\mathrm{1}}{\mathrm{2}}},{a}_{{n}+\mathrm{1}} =\sqrt{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}}{a}_{{n}} } \\ $$$${m}={a}_{\mathrm{1}}…
Question Number 140690 by liberty last updated on 11/May/21 $$\:\mathrm{Vector}\: \\ $$$$\mathrm{let}\:\mathcal{L}_{\mathrm{1}} =\:\mathrm{AC}\:\mathrm{where}\:\mathrm{A}=\left(\mathrm{2},−\mathrm{1},\mathrm{3}\right)\:\mathrm{and} \\ $$$$\mathrm{C}=\left(\mathrm{1},\mathrm{0},−\mathrm{5}\right)\mathrm{and}\:\mathrm{let}\:\mathcal{L}_{\mathrm{2}} =\:\mathrm{BD}\:\mathrm{where} \\ $$$$\mathrm{B}=\left(\mathrm{1},\mathrm{3},\mathrm{0}\right)\:\mathrm{and}\:\mathrm{D}=\left(\mathrm{3},−\mathrm{4},\mathrm{1}\right).\:\mathrm{Determine} \\ $$$$\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathcal{L}_{\mathrm{1}} \:\mathrm{and}\:\mathcal{L}_{\mathrm{2}} . \\ $$ Answered…
Question Number 140685 by Algoritm last updated on 11/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com