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Author: Tinku Tara

log-x-2-7x-2-x-3-log-1-x-2-x-2-3x-log-x-2-5-x-

Question Number 140680 by bemath last updated on 11/May/21 $$\:\mathrm{log}\:_{\left(\mathrm{x}+\mathrm{2}\right)} \left(\mathrm{7x}^{\mathrm{2}} −\mathrm{x}^{\mathrm{3}} \right)−\mathrm{log}\:_{\frac{\mathrm{1}}{\mathrm{x}+\mathrm{2}}} \left(\mathrm{x}^{\mathrm{2}} −\mathrm{3x}\right)\geqslant\:\mathrm{log}\:_{\sqrt{\mathrm{x}+\mathrm{2}}\:} \left(\sqrt{\mathrm{5}−\mathrm{x}}\:\right) \\ $$ Answered by liberty last updated on 11/May/21…

hello-show-that-sin-5pi-18-cos-13pi-18-1-2-sin-4pi-9-

Question Number 75147 by mathocean1 last updated on 07/Dec/19 $$\mathrm{hello} \\ $$$$\mathrm{show}\:\mathrm{that}\: \\ $$$$\mathrm{sin}\frac{\mathrm{5}\pi}{\mathrm{18}}\mathrm{cos}\frac{\mathrm{13}\pi}{\mathrm{18}}=−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{sin}\frac{\mathrm{4}\pi}{\mathrm{9}} \\ $$ Answered by MJS last updated on 07/Dec/19 $$\mathrm{sin}\:{a}\:\mathrm{cos}\:{b}\:=\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{sin}\:\left({a}−{b}\right)\:+\mathrm{sin}\:\left({a}+{b}\right)\right) \\…

x-3-1-x-2-dx-

Question Number 140676 by ZiYangLee last updated on 11/May/21 $$\int\:\frac{{x}^{\mathrm{3}} }{\mathrm{1}+{x}^{\mathrm{2}} }\:{dx}=? \\ $$ Answered by Dwaipayan Shikari last updated on 11/May/21 $$\int\frac{{x}^{\mathrm{3}} }{\mathrm{1}+{x}^{\mathrm{2}} }{dx}…

is-A-A-2-A-F-A-F-A-2-A-the-same-

Question Number 9604 by madscientist last updated on 20/Dec/16 $${is}\: \\ $$$$\bigtriangledown×\left(\bigtriangledown×{A}\right)=\bigtriangledown\left(\bigtriangledown\centerdot{A}\right)−\bigtriangledown^{\mathrm{2}} {A} \\ $$$${F}×\left(\bigtriangledown×{A}\right)={F}\left(\bigtriangledown\centerdot{A}\right)−\bigtriangledown^{\mathrm{2}} {A} \\ $$$${the}\:{same}? \\ $$ Terms of Service Privacy Policy…

A-regular-hexagon-has-sides-of-lenght-8-cm-Find-the-perpendicular-distance-between-two-opposite-faces-

Question Number 9603 by tawakalitu last updated on 20/Dec/16 $$\mathrm{A}\:\mathrm{regular}\:\mathrm{hexagon}\:\mathrm{has}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{lenght}\:\mathrm{8}\:\mathrm{cm}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{perpendicular}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{two} \\ $$$$\mathrm{opposite}\:\mathrm{faces}. \\ $$ Answered by mrW last updated on 20/Dec/16 $$\mathrm{2}×\frac{\mathrm{8}}{\mathrm{2}}×\sqrt{\mathrm{3}}=\mathrm{8}\sqrt{\mathrm{3}}\:\mathrm{cm} \\…

Question-9600

Question Number 9600 by Sopheak last updated on 20/Dec/16 Commented by prakash jain last updated on 20/Dec/16 $${k}^{{th}} \:\mathrm{Term}=\underset{{i}=\mathrm{0}} {\overset{{k}−\mathrm{1}} {\sum}}\mathrm{18}×\left(\mathrm{10}^{\mathrm{2}{i}} \right)=\frac{\mathrm{18}\left(\mathrm{10}^{\mathrm{2}{k}} −\mathrm{1}\right)}{\mathrm{99}} \\ $$$${S}_{{n}}…