Question Number 193714 by Rupesh123 last updated on 18/Jun/23 Commented by Frix last updated on 18/Jun/23 $$\sqrt{\mathrm{17}\pm\sqrt{\mathrm{288}}}=\sqrt{\mathrm{17}\pm\mathrm{12}\sqrt{\mathrm{2}}}=\mathrm{3}\pm\mathrm{2}\sqrt{\mathrm{2}} \\ $$$$\sqrt{\mathrm{7}\pm\sqrt{\mathrm{48}}}=\sqrt{\mathrm{7}\pm\mathrm{4}\sqrt{\mathrm{3}}}=\mathrm{2}\pm\sqrt{\mathrm{3}} \\ $$$$\Rightarrow \\ $$$$\mathrm{Answer}\:\mathrm{is}\:\mathrm{2} \\ $$…
Question Number 193711 by Mastermind last updated on 18/Jun/23 $$\mathrm{Ques}.\:\mathrm{1} \\ $$$$\:\:\:\:\:\mathrm{Let}\:\mathrm{G}\:\mathrm{be}\:\mathrm{a}\:\mathrm{group}\:\mathrm{and}\:\mathrm{b}\:\mathrm{a}\:\mathrm{fixed}\:\mathrm{element} \\ $$$$\mathrm{of}\:\mathrm{G}.\:\mathrm{Prove}\:\mathrm{that}\:\mathrm{the}\:\mathrm{map}\:\mathrm{G}\:\mathrm{into}\:\mathrm{G}\:\mathrm{given} \\ $$$$\mathrm{by}\:\mathrm{x}\rightarrow\mathrm{bx}\:\mathrm{is}\:\mathrm{bijective} \\ $$$$ \\ $$$$\mathrm{Ques}.\:\mathrm{2}\: \\ $$$$\:\:\:\:\:\mathrm{Let}\:\mathrm{G}\:\mathrm{be}\:\mathrm{a}\:\mathrm{group}\:\mathrm{and}\:\mathrm{g}\:\mathrm{be}\:\mathrm{an}\:\mathrm{element}\: \\ $$$$\mathrm{of}\:\mathrm{G}.\:\mathrm{Prove}\:\mathrm{that}\: \\…
Question Number 193707 by Mingma last updated on 18/Jun/23 Answered by Subhi last updated on 18/Jun/23 $$\frac{{a}^{\mathrm{2}} }{{b}^{\mathrm{2}} +{c}^{\mathrm{2}} }+\frac{{b}^{\mathrm{2}} }{{a}^{\mathrm{2}} +{c}^{\mathrm{2}} }+\frac{{c}^{\mathrm{2}} }{{a}^{\mathrm{2}} +{b}^{\mathrm{2}}…
Question Number 193706 by Rupesh123 last updated on 18/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 193688 by Mingma last updated on 18/Jun/23 Answered by cortano12 last updated on 18/Jun/23 $$\:\mathrm{4}\left(\mathrm{2p}+\mathrm{1}\right)^{\mathrm{2}} −\mathrm{4}.\left(−\mathrm{1}\right).\left(−\mathrm{2p}−\mathrm{31}\right)<\mathrm{0} \\ $$$$\:\mathrm{4p}^{\mathrm{2}} +\mathrm{4p}+\mathrm{1}−\mathrm{2p}−\mathrm{31}<\mathrm{0} \\ $$$$\:\mathrm{4p}^{\mathrm{2}} +\mathrm{2p}−\mathrm{30}<\mathrm{0} \\…
Question Number 193691 by cortano12 last updated on 18/Jun/23 $$ \\ $$ Commented by cortano12 last updated on 18/Jun/23 Answered by MM42 last updated on…
Question Number 193685 by cortano12 last updated on 18/Jun/23 $$\:\:\:\:\:\:\:\left(\mathrm{f}\left(\mathrm{x}\right)\right)^{\mathrm{2}} −\mathrm{4xf}\left(\mathrm{x}\right)+\mathrm{3}=\mathrm{0} \\ $$$$\:\:\:\:\mathrm{f}^{−\mathrm{1}} \left(\mathrm{3}\right)=?\: \\ $$ Answered by mr W last updated on 18/Jun/23 $${y}^{\mathrm{2}}…
Question Number 193687 by Mingma last updated on 18/Jun/23 Commented by Frix last updated on 18/Jun/23 $$\mathrm{Squaring}\:\&\:\mathrm{transforming}\:\mathrm{3}\:\mathrm{times}\:\mathrm{leads}\:\mathrm{to} \\ $$$${x}^{\mathrm{8}} −\frac{\mathrm{10}{x}^{\mathrm{7}} }{\mathrm{3}}+\frac{\mathrm{143}{x}^{\mathrm{6}} }{\mathrm{27}}−\frac{\mathrm{854}{x}^{\mathrm{5}} }{\mathrm{81}}+\frac{\mathrm{4352}{x}^{\mathrm{4}} }{\mathrm{243}}−\frac{\mathrm{4678}{x}^{\mathrm{3}} }{\mathrm{243}}+\frac{\mathrm{611}{x}^{\mathrm{2}}…
Question Number 193686 by Rupesh123 last updated on 18/Jun/23 Answered by mr W last updated on 18/Jun/23 Commented by mr W last updated on 18/Jun/23…
Question Number 193677 by lapache last updated on 18/Jun/23 $${li}\underset{{x}\rightarrow\mathrm{1}} {{m}}\:\frac{\mathrm{2}{arctan}^{\mathrm{2}} {x}−\frac{\pi}{\mathrm{8}}}{{x}^{\mathrm{2}} −\mathrm{1}}=… \\ $$ Answered by cortano12 last updated on 18/Jun/23 $$\:\:\underline{\underbrace{\:}} \cancel{\:} \\…