Question Number 9438 by tawakalitu last updated on 08/Dec/16 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{x},\:\mathrm{y}\:\mathrm{and}\:\mathrm{z} \\ $$$$\mathrm{2xy}\:=\:\mathrm{x}\:+\:\mathrm{y}\:\:\:\:\:\:……\:\left(\mathrm{i}\right) \\ $$$$\mathrm{6xz}\:=\:\mathrm{6z}\:−\:\mathrm{2x}\:\:\:\:…….\:\left(\mathrm{ii}\right) \\ $$$$\mathrm{3yz}\:=\:\mathrm{3y}\:+\:\mathrm{4z}\:\:\:\:………\:\left(\mathrm{iii}\right) \\ $$$$ \\ $$$$\mathrm{That}\:\mathrm{is}\:\mathrm{the}\:\mathrm{correct}\:\mathrm{question}\:\mathrm{sir}. \\ $$ Answered by mrW…
Question Number 9436 by geovane10math last updated on 08/Dec/16 $$\mathrm{If}\:\mathrm{they}\:\mathrm{said}\:\mathrm{that}\:\underset{{k}=\mathrm{1}} {\overset{\infty} {\sum}}\:{k}\:\mathrm{diverges},\:\mathrm{why} \\ $$$$\mathrm{1}\:+\:\mathrm{2}\:+\:\mathrm{3}\:+\:\mathrm{4}\:+\:…\:=\:−\:\frac{\mathrm{1}}{\mathrm{12}}\:? \\ $$ Answered by mrW last updated on 08/Dec/16 $$\:\:\:\mathrm{T}=\mathrm{1}−\mathrm{2}+\mathrm{3}−\mathrm{4}+\mathrm{5}−\mathrm{6}+… \\…
Question Number 74970 by mr W last updated on 05/Dec/19 $${x}+{y}+{z}=\mathrm{1} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} =\mathrm{2} \\ $$$${x}^{\mathrm{3}} +{y}^{\mathrm{3}} +{z}^{\mathrm{3}} =\mathrm{3} \\ $$$$ \\ $$$${find}…
Question Number 140506 by Dwaipayan Shikari last updated on 08/May/21 $${e}^{\left(\frac{\zeta\left(\mathrm{2}\right)}{\mathrm{2}}−\frac{\zeta\left(\mathrm{3}\right)}{\mathrm{3}}+\frac{\zeta\left(\mathrm{4}\right)}{\mathrm{4}}−\frac{\zeta\left(\mathrm{5}\right)}{\mathrm{5}}+…\right)} \:\:\:=? \\ $$ Answered by mnjuly1970 last updated on 08/May/21 Commented by mnjuly1970 last…
Question Number 74966 by ajfour last updated on 05/Dec/19 $${If}\:\:\mathrm{sin}\:\mathrm{2}{A}=\lambda\mathrm{sin}\:\mathrm{2}{B} \\ $$$${Prove}\:{that}\:\:\frac{\mathrm{tan}\:\left({A}+{B}\right)}{\mathrm{tan}\:\left({A}−{B}\right)}=\frac{\lambda+\mathrm{1}}{\lambda−\mathrm{1}}\:. \\ $$ Commented by Prithwish sen last updated on 05/Dec/19 $$\frac{\mathrm{sin2A}}{\mathrm{sin2B}}\:=\:\lambda \\ $$$$\frac{\mathrm{sin2A}+\mathrm{sin2B}}{\mathrm{sin2A}−\mathrm{sin2B}}\:=\:\frac{\lambda+\mathrm{1}}{\lambda−\mathrm{1}}…
Question Number 140500 by qaz last updated on 08/May/21 $$\mathrm{tan}\:^{\mathrm{2}} \mathrm{1}°+\mathrm{tan}\:^{\mathrm{2}} \mathrm{2}°+\mathrm{tan}\:^{\mathrm{2}} \mathrm{3}°+…+\mathrm{tan}\:^{\mathrm{2}} \mathrm{89}°=\frac{\mathrm{15931}}{\mathrm{3}}\:\:\:\:\:??? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 140503 by ERA last updated on 08/May/21 $$\boldsymbol{\mathrm{P}}\mathrm{rove}\:\mathrm{it} \\ $$$$\sqrt{\boldsymbol{{a}}+\sqrt{\boldsymbol{{b}}}}=\sqrt{\frac{\boldsymbol{{a}}+\sqrt{\boldsymbol{{a}}^{\mathrm{2}} +\boldsymbol{{b}}}}{\mathrm{2}}+}\sqrt{\frac{\boldsymbol{{a}}−\sqrt{\boldsymbol{{a}}^{\mathrm{2}} −\boldsymbol{{b}}}}{\mathrm{2}}} \\ $$ Commented by MJS_new last updated on 08/May/21 $$\mathrm{it}'\mathrm{s}\:\mathrm{wrong} \\…
Question Number 140502 by benjo_mathlover last updated on 08/May/21 $$\mathrm{If}\:\mathrm{three}\:\mathrm{vector}\:\overset{\rightarrow} {\mathrm{a}}\:,\:\overset{\rightarrow} {\mathrm{b}}\:\mathrm{and}\:\overset{\rightarrow} {\mathrm{c}}\:\mathrm{are}\: \\ $$$$\mathrm{such}\:\mathrm{that}\:\overset{\rightarrow} {\mathrm{a}}\:\neq\:\mathrm{0}\:\mathrm{and}\:\overset{\rightarrow} {\mathrm{a}}×\overset{\rightarrow} {\mathrm{b}}\:=\:\mathrm{2}\left(\overset{\rightarrow} {\mathrm{a}}×\overset{\rightarrow} {\mathrm{c}}\right) \\ $$$$,\mid\overset{\rightarrow} {\mathrm{a}}\mid\:=\:\mid\overset{\rightarrow} {\mathrm{c}}\mid\:=\:\mathrm{1}\:,\:\mid\overset{\rightarrow} {\mathrm{b}}\mid\:=\:\mathrm{4}\:\mathrm{and}\:\mathrm{the}\:…
Question Number 140497 by benjo_mathlover last updated on 08/May/21 $$\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{sin}\:\mathrm{x}\right)=\mathrm{x} \\ $$$$\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{cos}\:\mathrm{x}\right)=? \\ $$$$\mathrm{sin}^{−\mathrm{1}} \left(\mathrm{tan}\:\mathrm{x}\right)=? \\ $$ Commented by mr W last updated…
Question Number 140498 by mnjuly1970 last updated on 08/May/21 $$\:\:\:\:\:\:……..\:{nice}\:\:\:…….\:\:{calculus}……. \\ $$$$\:\:\:\:\:\:{simplify}: \\ $$$$\:\:\:\:\boldsymbol{\phi}\left({x}\right):=\:{sin}\left(\frac{{x}}{\mathrm{2}}\right)\left(\mathrm{1}+\mathrm{2}\underset{{m}=\mathrm{1}} {\overset{{n}} {\sum}}{cos}\left({mx}\right)\right) \\ $$$$\:\:\:\: \\ $$ Answered by Dwaipayan Shikari last…