Question Number 140449 by byaw last updated on 07/May/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{first}\:\mathrm{four}\:\mathrm{values}\:\mathrm{of} \\ $$$$\mathrm{2}{x}+\mathrm{5}=\mathrm{1}\left(\mathrm{mod}\:\mathrm{7}\right) \\ $$ Answered by Rasheed.Sindhi last updated on 08/May/21 $$\mathrm{2}{x}+\mathrm{5}=\mathrm{1}\left(\mathrm{mod}\:\mathrm{7}\right) \\ $$$$\mathrm{2}{x}\equiv\mathrm{1}−\mathrm{5}=−\mathrm{4}\left({mod}\mathrm{7}\right) \\…
Question Number 74914 by arkanmath7@gmail.com last updated on 03/Dec/19 $${Can}\:{someone}\:{solve}\:{this}\:{question}\:{plz}? \\ $$$${solve}\:{the}\:{contour}\:{integral}\: \\ $$$$\int_{{C}} \:\frac{{e}^{{iz}} }{{z}^{\mathrm{3}} }\:{dz}\:{where}\:{C}\:{is}\:{the}\:{circle}\:\mid{z}\mid=\mathrm{2} \\ $$ Answered by mind is power last…
Question Number 9379 by FilupSmith last updated on 03/Dec/16 $${S}=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(−{n}\right)^{\mathrm{1}−{n}} \\ $$$${S}=?? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 9378 by tawakalitu last updated on 03/Dec/16 $$\mathrm{Solve}: \\ $$$$\mathrm{x}^{\mathrm{3}} \:−\:\mathrm{18x}\:−\:\mathrm{32}\:=\:\mathrm{0} \\ $$ Answered by mrW last updated on 03/Dec/16 $$\mathrm{a}=\mathrm{1},\:\mathrm{b}=\mathrm{0},\:\mathrm{c}=−\mathrm{18},\:\mathrm{d}=−\mathrm{32} \\ $$$$\Delta=\mathrm{b}^{\mathrm{2}}…
Question Number 74912 by behi83417@gmail.com last updated on 03/Dec/19 $$\begin{cases}{\boldsymbol{\mathrm{x}}^{\mathrm{2}} =\boldsymbol{\mathrm{yz}}+\mathrm{1}}\\{\boldsymbol{\mathrm{y}}^{\mathrm{2}} =\boldsymbol{\mathrm{xz}}+\mathrm{2}}\\{\boldsymbol{\mathrm{z}}^{\mathrm{2}} =\boldsymbol{\mathrm{xy}}+\mathrm{3}}\end{cases}\:\:\:\:\Rightarrow\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}+\boldsymbol{\mathrm{z}}=? \\ $$ Answered by MJS last updated on 03/Dec/19 $${y}={px}\wedge{z}={qx} \\ $$$$\left(\mathrm{1}\right)\:\:\left(\mathrm{1}−{pq}\right){x}^{\mathrm{2}}…
Question Number 140450 by aliibrahim1 last updated on 07/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 140445 by EnterUsername last updated on 07/May/21 $$\mathrm{If}\:\mathrm{the}\:\mathrm{straight}\:\mathrm{lines}\:\bar {{a}}_{{i}} {z}+{a}_{{i}} \bar {{z}}+{b}_{{i}} =\mathrm{0}\left({i}=\mathrm{1},\:\mathrm{2},\:\mathrm{3}\right),\:\mathrm{where} \\ $$$${b}_{{i}} \:\mathrm{are}\:\mathrm{real},\:\mathrm{are}\:\mathrm{concurrent},\:\mathrm{then}\:\Sigma{b}_{{i}} \left({a}_{\mathrm{2}} \bar {{a}}_{\mathrm{3}} −\bar {{a}}_{\mathrm{2}} {a}_{\mathrm{3}} \right)\:\mathrm{is}…
Question Number 74910 by vishalbhardwaj last updated on 03/Dec/19 $$\mathrm{Explain}\:\mathrm{a}\:\mathrm{function}\:\mathrm{with}\:\mathrm{examples}\:\mathrm{based} \\ $$$$\mathrm{on}\:\mathrm{our}\:\mathrm{daily}\:\mathrm{life}\:? \\ $$ Answered by MJS last updated on 03/Dec/19 $$\mathrm{renting}\:\mathrm{a}\:\mathrm{car} \\ $$$$\mathrm{deal}\:\mathrm{1} \\…
Question Number 140444 by EnterUsername last updated on 07/May/21 $$\mathrm{If}\:\mathrm{the}\:\mathrm{points}\:\mathrm{1}+\mathrm{2}{i}\:\mathrm{and}\:−\mathrm{1}+\mathrm{4}{i}\:\mathrm{are}\:\mathrm{reflections}\:\mathrm{of} \\ $$$$\mathrm{each}\:\mathrm{other}\:\mathrm{in}\:\mathrm{the}\:\mathrm{line}\:{z}\left(\mathrm{1}+{i}\right)+\bar {{z}}\left(\mathrm{1}−{i}\right)+{K}=\mathrm{0},\:\mathrm{then} \\ $$$$\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{K}\:\mathrm{is}\:\_\_\_\_\_. \\ $$ Answered by mr W last updated on 08/May/21…
Question Number 140447 by 676597498 last updated on 07/May/21 Answered by EDWIN88 last updated on 07/May/21 $$\mathrm{L}+\mathrm{M}=\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}\:\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}\left(\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}+\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}\right)\mathrm{dx} \\ $$$$\mathrm{L}+\mathrm{M}\:=\:\underset{\mathrm{0}}…