Question Number 224672 by wongb1506 last updated on 25/Sep/25 Answered by mr W last updated on 26/Sep/25 Commented by mr W last updated on 26/Sep/25…
Question Number 224665 by ajfour last updated on 24/Sep/25 Commented by ajfour last updated on 24/Sep/25 $${At}\:{the}\:{instant}\:{shown}\:{rotating} \\ $$$${frame}\:{plane}\:{lies}\:{in}\:{yz}\:{plane}. \\ $$$${Angular}\:{acceleration}\:\left({constant}\right) \\ $$$${is}\:\boldsymbol{\alpha},\:{angular}\:{velocity}\:\boldsymbol{\omega}.\:{Find}\:\boldsymbol{\theta} \\ $$$${and}\:\boldsymbol{\phi}.\:{String}\:{length}\:{is}\:{L}.…
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Question Number 224634 by gregori last updated on 23/Sep/25 $$\:\:\underbrace{\mathcal{X}} \\ $$ Answered by mr W last updated on 24/Sep/25 $$\_{B\_B\_B\_B\_B\_B\_G\_G\_G\_G\_} \\ $$$$\_{G\_G\_G\_G\_B\_B\_B\_B\_B\_B\_} \\ $$$${B}\ast{B}\ast{B}\ast{B}\ast{B}\ast{B}…
Question Number 224635 by hardmath last updated on 23/Sep/25 $$\mathrm{Prove}\:\mathrm{that}:\:\:\:\mathrm{sin}\left(\mathrm{54}°\right)\:=\:\:\frac{\sqrt{\mathrm{5}}\:+\:\mathrm{1}}{\mathrm{4}} \\ $$ Answered by som(math1967) last updated on 23/Sep/25 $$\:{let}\:\mathrm{54}=\alpha \\ $$$$\therefore\mathrm{5}\alpha=\mathrm{270} \\ $$$$\Rightarrow\mathrm{3}\alpha=\mathrm{270}−\mathrm{2}\alpha \\…
Question Number 224641 by Mingma last updated on 23/Sep/25 Answered by mr W last updated on 07/Oct/25 $$\left({a}\right) \\ $$$${p}=\frac{\mathrm{4}}{{C}_{\mathrm{5}} ^{\mathrm{52}} }=\frac{\mathrm{1}}{\mathrm{649}\:\mathrm{740}} \\ $$$$\left({b}\right) \\…
Question Number 224642 by Rogerkeyter last updated on 23/Sep/25 Answered by som(math1967) last updated on 24/Sep/25 $$\:\:\:\:\:{I}=\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\boldsymbol{{dx}}}{\mathrm{1}+\frac{\boldsymbol{{e}}^{\sqrt{\mathrm{1}−\boldsymbol{{x}}}} }{\boldsymbol{{e}}^{\sqrt{\boldsymbol{{x}}}} }} \\ $$$$\:\:\:\:=\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\boldsymbol{{e}}^{\sqrt{\boldsymbol{{x}}}}…
Question Number 224623 by gregori last updated on 22/Sep/25 $$\:\:\: \\ $$ Commented by gregori last updated on 23/Sep/25 $${no}\:{sir}.\:{i}\:{don}'{t}\:{get}\:{answer}\: \\ $$ Commented by mr…